\(a,=6\left|a\right|b^2\sqrt{2}=6ab^2\sqrt{2}\\ b,=3\left|ab\right|\sqrt{3a}=-3ab\sqrt{3a}\)

a, \(\sqrt{54}=\sqrt{9.6}=3\sqrt{6}\)

b, \(\sqrt{108}=\sqrt{36.3}=6\sqrt{3}\)

c, \(0,1\sqrt{20000}=0,1\sqrt{2.10000}=10\sqrt{2}\)

d, \(-0,05\sqrt{28800}=-0,05\sqrt{288.100}=-0,05.10.\sqrt{144.2}\)

\(=-0,5.12\sqrt{2}=-6\sqrt{2}\)

e, \(\sqrt{7.63.a^2}=\sqrt{7.7.9.a^2}=21\left|a\right|\)

a) $\sqrt{54}=\sqrt{9.6}=\sqrt{9}.\sqrt{6}=3\sqrt{6}$.

b) $\sqrt{108}=\sqrt{36.3}=\sqrt{36}.\sqrt{3}=6\sqrt{3}$.

c) $0,1\sqrt{20000}=0,1\sqrt{2.10000}=0,1\sqrt{2}.\sqrt{10000}$

$=0,1.100\sqrt{2}=10\sqrt{2}$.

d) $-0,05\sqrt{28800}=-0,05\sqrt{288.100}$

$=-0,05\sqrt{\mathrm{2.144.100}}=-0,05.\sqrt{2}.\sqrt{144}.\sqrt{100}$

$=-0,\mathrm{05.12.10}\sqrt{2}$

$=-6\sqrt{}$

a) \(\sqrt{54}=\sqrt{9}.\sqrt{6}=3\sqrt{6}\)

b) \(\sqrt{108}=\sqrt{9}.\sqrt{4}.\sqrt{3}=6\sqrt{3}\)

c) \(0,1\sqrt{20000}=0,1.\sqrt{2}.\sqrt{10000}=0,1.100.\sqrt{2}=10\sqrt{2}\)

d) \(-0,05\sqrt{28800}=-0,05\sqrt{400}.\sqrt{9}.\sqrt[]{4}.\sqrt{2}=-0,05.20.3.2.\sqrt{2}=-6\sqrt{2}\)

e) \(\sqrt{7.63.a^2}=21\sqrt{a^2}\left\{{}\begin{matrix}=-21a\\=21a\end{matrix}\right.\)

a) √54 = √9.6 = 3√6
b) √108 = √36.3 = 6√3
c) 0,1√20000 = 0,1√10000.2= 0,1.100√2 = 10√2
d) -0,05.√28800 = -0,05.√14400.2 = -0,05.120√2 = -6√2
e)√7.63.a2 = √7.7.9.a2 = 7.3|a| = 21|a|

a: \(=\sqrt{9\cdot6}=3\sqrt{6}\)

b: \(=\sqrt{36\cdot3}=6\sqrt{3}\)

c: \(=\dfrac{1}{10}\cdot\sqrt{10000\cdot2}=\dfrac{1}{10}\cdot100\cdot\sqrt{2}=10\sqrt{2}\)

d: \(=-\dfrac{1}{20}\cdot\sqrt{14400\cdot2}=-\dfrac{1}{20}\cdot120\cdot\sqrt{2}=-6\sqrt{2}\)

e: \(=\sqrt{7\cdot7\cdot9\cdot a^2}=21\left|a\right|\)

a) \(\left(\sqrt{28}-5\sqrt{35}+7\sqrt{112}\right)2\sqrt{7}=2\sqrt{196}-10\sqrt{245}+14\sqrt{784}\)

\(=28-10\sqrt{49.5}+392=420-70\sqrt{5}\)

b) \(\left(\sqrt{72}-3\sqrt{24}+5\sqrt{8}\right)\sqrt{2}+4\sqrt{27}=\sqrt{144}-3\sqrt{48}+5\sqrt{16}+4\sqrt{9.3}\)

\(=12-3\sqrt{16.3}+20+12\sqrt{3}=32-12\sqrt{3}+12\sqrt{3}=32\)

a) = \(4\sqrt{3}+3\sqrt{3}-3\sqrt{5}+\sqrt{5}=\sqrt{3}\cdot\left(4+3\right)-\sqrt{5}\cdot\left(3-1\right)=7\sqrt{3}-2\sqrt{5}\)

b) = \(2a^2b\sqrt{7b}\)

c) = \(6ab^2\sqrt{2}\)

a. \(4\sqrt{3}+\sqrt{27}-\sqrt{45}+\sqrt{5}=4\sqrt{3}+3\sqrt{3}-3\sqrt{5}+\sqrt{5}=\left(4+3\right)\sqrt{3}-\left(3-1\right)\sqrt{5}=7\sqrt{3}-2\sqrt{5}\)b. \(\sqrt{28a^4b^2}=2a^2b\sqrt{7}\)( vì b>=0)

c.\(\sqrt{72a^2b^4}=-6ab^2\sqrt{2}\)( vì a<o)

a: \(=\sqrt{4\cdot a^4b^2\cdot7}=2a^2b\sqrt{7}\left(b>=0\right)\)

b: \(=\sqrt{36\cdot b^4\cdot a^2\cdot2}=-6ab^2\sqrt{2}\)