\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)

=>\(36x^2-12x-36x^2+17x=30\)

=>\(17x-12x=30\)

=>\(5x=30\)

=>x=30:5

=>x=6

\(3.\left(12x-4\right)-9.\left(4x-3\right)=30\)

\(\Rightarrow36x-12-36x+27=30\)

\(\Rightarrow36x-36x=30+12-27\)

\(\Rightarrow x.\left(36-36\right)=15\)

\(\Rightarrow x.0=15\)

\(\Rightarrow x=15:0\) \(???\)

    ĐỀ bài sai rồi 

a) \(36x^2-12x-36x^2+27x=30\)

                                                \(15x=30\)

                                                     \(x=2\)

b) \(5x-2x^2+2x^2-2x=15\)

                                          \(3x=15\)

                                             \(x=5\)

36x²-12x-36x²+27x=30

15x=30

x=2

3x(12x – 4) – 9x(4x – 3) = 30

3x.12x – 3x.4 – (9x.4x – 9x.3) = 30

36x2 – 12x – 36x2 + 27x = 30

(36x2 – 36x2) + (27x – 12x) = 30

15x = 30

x = 2

Vậy x = 2.

a) \(3x\cdot\left(12x-4\right)-9x\cdot\left(4x-3\right)=30\)

\(\Leftrightarrow36x^2-12x-36x^2+27x=30\)

\(\Leftrightarrow15x=30\)

\(\Leftrightarrow x=\dfrac{30}{15}\)

\(\Leftrightarrow x=2\)

b) \(\left(2x+1\right)-5\left(x-2\right)=10\)

\(\Leftrightarrow2x+1-5x+10=10\)

\(\Leftrightarrow-3x+11=10\)

\(\Leftrightarrow-3x=10-11\)

\(\Leftrightarrow-3x=-1\)

\(\Leftrightarrow x=\dfrac{1}{3}\)

3x (12x -4 )- 9x (4x-3)= 30 

<=>36x²-12x-36x³+27x=30

<=>15x=30

<=>x=2

a) 3x (12x - 4) - 9x (4x - 3) = 30

36x² – 12x – 36x² + 27x = 30

15x = 30

Vậy x = 2.

b) x (5 - 2x) + 2x (x - 1) = 15

5x – 2x² + 2x² – 2x = 15

3x = 15

x =5

\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)

\(36x^2-12x-36x^2+27x=30\)

\(15x=30\)

\(x=\frac{30}{15}\)

\(x=2\)