58 - ( x + 34 ) = 15

       x + 34    = 58 - 15 = 43

              x     = 43 - 34 = 9

18 + 24x = 50

       24x = 50 - 18 = 32

           x = 32 : 24 

          x  = 4/3

(x-42) - 17 = 127

=> x - 42 = 127 + 17 = 144

=> x = 144 + 42 = 186

23(x+1) = 69

=> x + 1 = 69 : 23 = 3

x = 3 - 1 = 2

2x + 5 = 120 : 2 = 60

=> 2x = 60 - 5 = 55

x = 55 : 2 = 27,5

5x - 2 = 613

=> 5x = 613 + 2 = 615

x = 615 : 5 = 123

a)(x-42)-17=127

(x-42)=127+17

(x-42)=144

x=144+42

x=186

b)23(x+1)=69

(x+1)=69:23

(x+1)=3

x=3-1

x=2

c)2.x+5=120:2

2.x+5=60

2.x=60-5

2.x=55

x=55:2

x=27,5

d)5.x-2=613

5.x=613+2

5.x=615

x=615:5

x=123

(x-42)-17=127(tim x)xx

23(x+1)=69(timx)xx

2x+5=120:2(Timx)xx

5x-2=613(timx)xx

(15 + x) - 24 = 246

=> 15 + x = 246 + 24 = 270

x = 270 - 15 = 255

(298 - x) - 42 = 252

=> (298 - x) = 252 + 42 = 294

=> x = 298 - 2984 = 4

Biến đổi ta được:  1 x + 20 . T = 1 2 ⇒ T = x + 20 2

\(a,x\left(x+5\right)-\left(x-2\right)\left(x+3\right)=0\\ \Leftrightarrow x^2+5x-x^2-x+6=0\Leftrightarrow4x=-6\\ \Leftrightarrow x=-\dfrac{3}{2}\)

\(b,2x^3-18x=0\\ \Leftrightarrow2x\left(x^2-9\right)=0\\ \Leftrightarrow2x\left(x-3\right)\left(x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\\x=-3\end{matrix}\right.\)

a: Ta có: \(x\left(x+5\right)-\left(x-2\right)\left(x+3\right)=0\)

\(\Leftrightarrow x^2+5x-x^2-3x+2x+6=0\)

\(\Leftrightarrow7x=-6\)

hay \(x=-\dfrac{6}{7}\)

b: Ta có: \(2x^3-18x=0\)

\(\Leftrightarrow2x\left(x-3\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\\x=-3\end{matrix}\right.\)

( x-34).15 =0

x-34 =0

x=34

(x-34).15 = 0

=> x-34 = 0:15 = 0

=> x = 0+34

=> x = 34

18.(x-16) = 18

=> x - 16 = 18 : 18 = 1

=> x = 1 + 16

=> x = 17

=>(x-34)=0:15 ko tồn tại

=>(x-16)=1

=>x=17

 đúng 100%

 tham khảo nha

( x - 34 ) . 15 = 0

 x - 34       = 0

x      = 34

18 . ( x - 16 ) = 18 

 x - 16 = 1

x = 17

Study well 

*) \(\left(x-34\right)\cdot15=0\)

\(\Leftrightarrow x-34=0\)

\(\Leftrightarrow x=34\)

Vậy x=34

*) \(18\cdot\left(x-16\right)=18\)

\(\Leftrightarrow x-16=1\)

\(\Leftrightarrow x=17\)

Vậy x=17

a) ( x-34) x 15=0
   ( x-34)       =0 : 15
   ( x-34)       =0 
     x             =0 + 34
     x             =34
b) 18 x ( x-16)=18
          ( x- 16)=18 : 18
          ( x-16) =1
            x       = 16 + 1 
            x       = 17
c) ( x-4).( x-3)=0
   x . ( 4-3)    =0
   x . 0          =0 ( n* . o = 0 )
   => x = n*

e) 6.x + 4.x=2020
   10.x      =2020
       x      =2020:10
      x      =202

a)34

b)17

c)4

d)17

e)202

f)0

a: =>25-4x=1

=>4x=24

hay x=6

b: =>2x-4=0

hay x=2

c: =>x-35=115

hay x=150

d: =>x-2=12

hay x=14

e: =>x-36=216

hay x=252