a) \(K_2O+H_2O->2KOH\)

b) \(2Fe+3Cl_2->2FeCl_3\)

c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)

d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)

e)\(2Al+6HCl->2AlCl_3+3H_2\)

f) \(2KClO_3->KCl+3O_2\)

g) \(4P+5O_2->2P_2O_5\)

h) \(3Fe+2O_2->Fe_3O_4\)

i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)

j) \(2K+2H_2O->2KOH+H_2\)

a) \(N_2+O_2\rightarrow2NO\)

\(\begin{matrix}N^0\rightarrow N^{+2}+2e\\O^0+2e\rightarrow O^{-2}\end{matrix}|\begin{matrix}\times1\\\times1\end{matrix}\)

b) \(C_2H_5OH+3O_2\rightarrow2CO_2+3H_2O\)

\(\begin{matrix}C^{-2}\rightarrow C^{+4}+6e\\O^0+2e\rightarrow O^{-2}\end{matrix}|\begin{matrix}\times1\\\times3\end{matrix}\)

c) \(CH_4+2O_2\rightarrow CO_2+2H_2O\)

\(\begin{matrix}C^{-4}\rightarrow C^{+4}+8e\\O^0+2e\rightarrow O^{-2}\end{matrix}|\begin{matrix}\times1\\\times4\end{matrix}\)

d) \(2H_2S+3O_2\rightarrow2H_2O+2SO_2\)

\(\begin{matrix}S^{-2}\rightarrow S^{+4}+6e\\O^0+2e\rightarrow O^{-2}\end{matrix}|\begin{matrix}\times1\\\times3\end{matrix}\)

e) \(4NH_3+3O_2\rightarrow2N_2+6H_2O\)

\(\begin{matrix}N^{-3}\rightarrow N^0+3e\\O^0+2e\rightarrow O^{-2}\end{matrix}|\begin{matrix}\times2\\\times3\end{matrix}\)

a)N2+O2->2NO

b)C2H5OH+3O2->2CO2+3H2O

c)CH4+2O2->CO2+2H2O

d)H2S+3/2O2->H2O+SO2 / 2H2S+3O2->2H2O+2SO2

e)2NH3+3/2O2->N2+3H2O / 4NH3+3O2->2N2+6H2O

CHÚC BN HỌC TỐT :))))

\(2C_xH_y+\left(\dfrac{2x+y}{2}\right)O_2\rightarrow2xCO_2+yH_2O\)

\(C_nH_{2n+2}+\left(\dfrac{3n+1}{2}\right)O_2\rightarrow nCO_2+\left(n+1\right)H_2O\)

\(C_nH_{2n}+\dfrac{3n}{2}O_2\rightarrow nCO_2+nH_2O\)

Cân bằng các PTHH

a, Cu + HNO₃ \(\rightarrow\) 4Cu(NO₃)₂ + 2NO₂ + 2H₂O

b, MnO₂ + 4HCl \(\rightarrow\) MnCl₂ + Cl₂ + 2H₂O

c, 3FeO + 10HNO₃ \(\rightarrow\) 3Fe(NO₃)₃ + 5H₂O + 3NO

d, 4FeS₂ + 11O₂ \(\rightarrow\) 2Fe₂O₃ + 8SO₂

a, Cu + HNO3 → 4Cu(NO3)2 + 2NO2 + 2H2O

b, MnO2 + 4HCl → MnCl2 + Cl2 + 2H2O

c, 3FeO + 10HNO3 → 3Fe(NO3)3 + 5H2O + 3NO

d, 4FeS2 + 11O2 → 2Fe2O3 + 8SO2 ( to)

1) \(\overset{+2}{Fe}\overset{-1}{S_2}+\overset{0}{O_2}\rightarrow\overset{+3}{Fe_2}\overset{-2}{O_3}+\overset{+4}{S}\overset{-2}{O_2}\)

quá trình OXH :\(\overset{+2}{Fe}\overset{-1}{S_2}\rightarrow\overset{+3}{Fe}+\overset{+4}{2S}+11e|\times4\)

quá trình khử : \(\overset{0}{2O}+2.2e\rightarrow\overset{-2}{2O}|\times11\)

2) \(\overset{+2}{Fe}\overset{-2}{S}+H\overset{+5}{N}O_3\rightarrow\overset{+3}{Fe}\left(\overset{+5}{N}O_3\right)_3+\overset{+2}{N}\overset{-2}{O}+H_2O+H_2\overset{+6}{S}O_4\)

quá trình OXH : \(\overset{+2}{Fe}\overset{-2}{S}\rightarrow\overset{+3}{Fe}+\overset{+6}{S}+9e|\times1\)

quá trình khử : \(\overset{+5}{N}+3e\rightarrow\overset{+2}{N}|\times3\)

\(\Rightarrow FeS+6HNO_3\rightarrow Fe\left(NO_3\right)_3+3NO+2H_2O+H_2SO_4\)

CÒN ĐỂ CHIỀU MK LM CHO NHA

1) 2

2) C_nH_{2n + 2} + \(\dfrac{3n+1}{2}\) O₂ -> nCO₂ + (n+1)H₂O.

3) C_nH_{2n – 2} + \(\dfrac{3n-1}{2}\) O₂ -> nCO₂ +(n-1) H2O.

4) C_nH_2n-6 +\(\dfrac{3n-3}{2}\) O2 -> nCO2 + (n-3) H2O

5) O+\(\dfrac{3n}{2}\)O2→n+(n+1)H2O

6) 2C_xH_yO_z + \(\dfrac{4x+y-2z}{2}\) O2 →2x CO₂ + yH₂O

7)

8)

9) 2

10)

11)

12) 3

1) 2KClO₃ \(\underrightarrow{to}\) 2KCl + 3O₂

5O₂ + 4P \(\underrightarrow{to}\) 2P₂O₅

P₂O₅ + 3H₂O → 2H₃PO₄

2H₃PO₄ + 3Ca → Ca₃(PO₄)₂ + 3H₂

2) 2KClO₃ \(\underrightarrow{to}\) 2KCl + 3O₂

O₂ + 4Na → 2Na₂O

Na₂O + H₂O → 2NaOH

2KClO₃ \(\underrightarrow{to}\) 2KCl + 3O₂

O₂ + 2H₂ \(\underrightarrow{to}\) 2H₂O

2H₂O \(\xrightarrow[phân]{điện}\) 2H₂ + O₂

2H₂ + O₂ \(\underrightarrow{to}\) 2H₂O

H₂O + K₂O → 2KOH

b)2CxHy + (2x-y)O2 → 2xCO2 + 2yH2O

c)2CmH2m-2+(3m-1)O2 → 2mCO2 + (2m-2) H2O

d)2CxHyOz+(2x+y-z)O2

→2xCO2 + 2yH2O

Đề có vấn đề à

2K + O₂ -> K₂O (tỉ lệ 2:1:1)

2Na + 2H₂O -< 2NaOH + H₂ (tỉ lệ 2:2:2:1)

2Al + 6HCl -> 2AlCl₃ + 3H₂ (tỉ lệ 2:6:2:3)

2KMnO₄ -> K₂MnO₄ + MnO₂ + O₂ (tỉ lệ 2:1:1:1)

4FeS₂ + 11O₂ -> 2Fe₂O₃ + 8SO₂ (tỉ lệ 4:11:2:8)

P₂O₅ + 3H₂O -> 2H₃PO₄ (tỉ lệ 1:3:2)