\(\frac{2^{15}.9^4}{6^7.8^2}\)

\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^2}\)

\(=\frac{2^{15}.3^8}{2^7.3^7.2^6}\)

\(=\frac{2^{15}.3^8}{2^{13}.3^7}\)

\(=2^2.3\)

\(=12\)

_Chúc bạn học tốt_

\(\frac{2^{15}.9^4}{6^7.8^2}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^2}=\frac{2^{15}.3^8}{2^7.3^7.2^6}=\frac{2^{15}.3^8}{2^{13}.3^7}=2^2.3=12\)

\(\frac{2^{15}\cdot9^4}{6^7\cdot8^2}\)

\(=\frac{2^{15}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^7\cdot\left(2^3\right)^2}\)

\(=\frac{2^{15}\cdot3^8}{2^7\cdot3^7\cdot2^6}=\frac{2^{15}\cdot3^8}{2^{13}\cdot3^7}\)

Rút gọn => \(=2^2\cdot3=4\cdot3=12\)

hok tốt ...

1 My parents go shopping twice a week

2 Hoa's house has a balcony

3 My brother usually plays badminton with his friends

4 My favorite book is Tam and Cam. What is yours?

5 There are 10 pencil cases on the table

1, My parents go shopping twice a week.

2, Hoa's house has a balcony.

3, My brother usually plays badminton with his friends.

4, My favorite book is Tam and Cam. What's yours?

5, There are ten pencil cases on the table.

Ex1 ko có verb à

Ex2

1 like

2 listen

3 wears

4 teaches

5 do

6 goes

7 comes

8 goes

9 watch

10 walks

11 is

12 washes

13 studies

14 wants

15 plays

16 buys

17 studies

18 tries

19 washes

20 cries

21 says

22 flies

23 don't have

1 is

2 are

3 is

4 am

5 are

6 is

7 is

8 are

8 are

10 is

11 are

12 is

13 am

14 are

15 are

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Bạn mở ra đằng sau có phần hướng dẫn giải không? Mk mới học lớp 6 nên ko giúp bạn được

bn viết câu hỏi ra luôn đi

cậu viết đề bài ra luôn đi

mk ko bt vẽ hình!

cô có bảo mai chấm đâu! 

điêu thế. Cô bảo cô chấm màk
 

mà mik giở sách ùi, giải trong vơt bài tập được không?

Bài 1: 

a: \(\sqrt{0.49a^2}=-0.7a\)

b: \(\sqrt{25\left(a-7\right)^2}=5a-35\)

c: \(\sqrt{a^4\left(a-2\right)^2}=a^2\cdot\left(a-2\right)\)

d: \(\dfrac{1}{a-3b}\cdot\sqrt{a^6\left(a-3b\right)^2}\)

\(=\dfrac{1}{a-3b}\cdot a^3\cdot\left(a-3b\right)=a^3\)

Bài 2: 

a: \(2\left(x+y\right)\cdot\sqrt{\dfrac{1}{x^2+2xy+y^2}}\)

\(=2\left(x+y\right)\cdot\dfrac{1}{x+y}\)

=2

b: \(\dfrac{3x}{7y}\cdot\sqrt{\dfrac{49y^2}{9x^2}}\)

\(=\dfrac{3x}{7y}\cdot\dfrac{-7y}{3x}\)

=-1

\(1,\\ a,\sqrt{0,49a^2}\left(a< 0\right)=-0,7a\\ b,\sqrt{25\left(7-a\right)^2}\left(a\ge7\Leftrightarrow7-a\le0\right)=5\left(a-7\right)\\ c,\sqrt{a^4\left(a-2\right)^2}\left(a>0\right)=\left[{}\begin{matrix}a^2\left(a-2\right),\forall a\ge2\\a^2\left(2-a\right),\forall0< a< 2\end{matrix}\right.\\ d,\dfrac{1}{a-3b}\sqrt{a^6\left(a-3b\right)^2}\left(a>3b>0\right)=\dfrac{1}{a-3b}\cdot a^3\left(a-3b\right)=a^3\)

1 was arrested before the garden by the boy yesterday

2 his cats taken care of carefully by Jack everyday

3 Has the country been protected from Covid-19 successfully

4 is reported that the man is running out of money

is reported to be running out of money\

5 has been said that the thief got out of the prison

has been said to have got out of the prison

6 was thought that Mary had turned down the job

Mary was thought to have  turned down the job