2³⁰⁰ < 3²⁰⁰

Ta có:

\(2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)

\(3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)

Vì \(8^{100}< 9^{100}\)

Nên \(2^{300}< 3^{200}\)

Ta có: \(2^{300}\)=\(2^{3.100}\)=(2\(^3\))\(^{100}\)=8\(^{100}\)

3\(^{200}\)=3\(^{2.100}\)=(3\(^2\))\(^{100}\)=9\(^{100}\)

Mà 8<9

⇒\(2^{300}\)<3\(^{200}\)

a) 5²⁸ = (5²)¹⁴ = 25¹⁴

Vì 25¹⁴ < 26¹⁴ nên 5²⁸ < 26¹⁴

b) 5³⁰ = (5³)¹⁰ = 125¹⁰

Vì 125¹⁰ > 124¹⁰ nên 5³⁰ > 124¹⁰

c) 4²¹  = (4³)⁷ = 64⁷

Vì 64⁷ = 64⁷ nên 4²¹ = 64⁷

Mong mn ủng hộ mk

\(a,5^{28}=\left(5^2\right)^{14}=25^{14}< \)\(26^{14}\)

\(\Rightarrow5^{28}< 26^{14}\)

\(b,5^{30}=\left(5^3\right)^{10}=125^{10}>124^{10}\)

\(\Rightarrow5^{30}>124^{10}\)

\(c,4^{21}=\left(4^3\right)^7=64^7\)

\(\Rightarrow4^{21}=64^7\)

a) ta có: 5²⁸ = (5²)¹⁴=25¹⁴ < 26¹⁴

=> 5²⁸<26¹⁴

b) ta có:5³⁰ = (5³)¹⁰ =  125¹⁰>124¹⁰

=> 5³⁰ > 124¹⁰

c) ta có: 4²¹ = (4³)⁷ = 64⁷

=> 4²¹=64⁷

a/

\(27^{81}=\left(3^3\right)^{81}=3^{241}\)

\(81^{27}=\left(3^4\right)^{27}=3^{108}\)

\(\Rightarrow27^{81}=3^{241}>3^{108}=81^{27}\)

b/

\(5^{60}=\left(5^3\right)^{20}=125^{20}\)

\(7^{40}=\left(7^2\right)^{20}=49^{20}\)

\(\Rightarrow5^{60}=125^{20}>49^{20}=7^{40}\)

c/

\(11^{102}=\left(11^2\right)^{51}=121^{51}>121^{50}>99^{50}\)

mình đang cần gâps

625⁵ và 125⁷

a, 625⁵ = (5⁴)⁵ = 5²⁰

125⁷ = (5³)⁷ = 5²¹

Vì 5²⁰ < 5²¹ nên 625⁵ < 125⁷

b,  3²ⁿ = (3²)ⁿ = 9ⁿ

     2³ⁿ = (2³)ⁿ = 8ⁿ

     9ⁿ > 8ⁿ ( nếu n > 0)

      9ⁿ = 8ⁿ (nếu n = 0)

Vậy nếu n = 0 thì 2³ⁿ = 3²ⁿ
      nếu n > 0 thì 3²ⁿ > 2³ⁿ

a) \(625^5=\left(5^4\right)^5=5^{20}\)

\(125^7=\left(5^3\right)^7=5^{21}>5^{20}\)

\(\Rightarrow625^5< 125^7\)

b) \(3^{2n}=9^n\)

\(2^{3n}=8^n< 9^n\)

\(\Rightarrow3^{2n}>2^{3n}\)

a) Ta có \(5^{300}=5^{3.100}=\left(5^3\right)^{100}=125^{100}\)

\(3^{500}=3^{5.100}=\left(3^5\right)^{100}=243^{100}\)

Vì 125 < 243 nên \(125^{100}< 243^{100}\)

Vậy \(5^{300}< 3^{500}\)

b) Ta có \(2^{15}=2^{13+2}=2^{13}.2^2=4.2^{13}\)

Vì 4<7 nên \(4.2^{13}< 7.2^{13}\)

Vậy \(2^{15}< 7.2^{13}\)

\(a)\)\(5^{300}=\left(5^3\right)^{100}=125^{100}\)

\(3^{500}=\left(3^5\right)^{100}=243^{100}\)

Vì \(125^{100}< 243^{100}\) nên \(5^{300}< 3^{500}\)

Vậy \(5^{300}< 3^{500}\)

\(b)\)\(2^{15}=2^{13+2}=2^{13}.2^2=4.2^{13}< 7.2^{13}\)

Vậy \(7.2^{13}>2^{15}\)

Chúc bạn học tốt ~ 

Bài 4:

\(a,2^{30}=\left(2^3\right)^{10}=8^{10};3^{20}=\left(3^2\right)^{10}=9^{10}\\ Vì:8^{10}< 9^{10}\left(Vì:8< 9\right)\Rightarrow2^{30}< 3^{20}\\ b,9^{10}.27^5=\left(3^2\right)^{10}.\left(3^3\right)^5=3^{20}.3^{15}=3^{35}\\ 243^7=\left(3^5\right)^7=3^{35}\\ Vì:3^{35}=3^{35}\Rightarrow243^7=9^{10}.27^5\)

Bài 5:

100< 5^2x-3 < 59

Đề vầy hả em?

a) Ta có: \(8^{28}=2^{84}=16^{21}\)

Mà \(16>15\Rightarrow16^{21}>15^{21}\Rightarrow8^{28}>15^{21}\)

Vậy...

b) \(5^{91}>5^{90}=125^{30}\)   \(\left(1\right)\)

    \(11^{59}< 11^{60}=121^{30}\)                \(\left(2\right)\)

Lại có: \(125>121\)          \(\left(3\right)\)

Từ (1), (2) và (3) suy ra \(5^{91}>11^{59}\)

2^7>7^2

96^5>27^3

3^200>2^300

31^11>17^4

TÍCH CHO MÌNH 3 TÍCH ĐI !