tìm x biết:
\(5\frac{4}{7}:\left\{x:1,3+8,4.\frac{6}{7}.\left[6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\frac{1}{14}\)
Mọi người giúp mình bài này với :
Tìm x biết :
\(5\frac{4}{7}:\left\{x:1,3+8,4.\frac{6}{7}.\left[6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\frac{1}{14}\)
\(5\frac{4}{7}\): [ x : 1,3 + 8,4 . \(\frac{6}{7}\). ( 6 - \(\frac{\left(2,3+5\div6,25\right)\times7}{8\times0,-125+6,9}\)) ] = \(1\frac{1}{14}\)
\(\frac{39}{7}\): [ x : 1,3 + \(\frac{36}{5}\). ( 6 - \(\frac{\left(2,3+0,8\right).7}{0,1+6,9}\)) ] = \(\frac{15}{14}\)
\(\frac{39}{7}\): [ x : 1,3 + \(\frac{36}{5}\). ( 6 - \(\frac{3,1.7}{7}\)) ] = \(\frac{15}{14}\)
\(\frac{39}{7}\): [ x : 1,3 + \(\frac{36}{5}\). ( 6 - 3,1 ) ] = \(\frac{15}{14}\)
x : 1,3 + \(\frac{36}{5}\). 2,9 = \(\frac{39}{7}\): \(\frac{15}{14}\)
x : 1,3 + 20,88 = 5,2
x : 1,3 = - 15,68
x = - 15,68 . 1,3
x = - 20,384
ta có
\(5\frac{4}{7}:\left\{x:1,3+8,4.\frac{6}{7}.\left[6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\frac{1}{14}\)
\(\Leftrightarrow\frac{39}{7}:\left\{x:1,3+7,2.\left[6-\frac{\left(2,3+0,8\right).7}{0,1+6,9}\right]\right\}=\frac{15}{14}\)
\(\Leftrightarrow\frac{39}{7}:\left\{x:1,3+7,2.\left[6-\frac{3,1.7}{7}\right]\right\}=\frac{15}{14}\)
\(\Leftrightarrow\frac{39}{7}:\left\{x:1,3+7,2.2,9\right\}=\frac{15}{14}\Leftrightarrow\left\{x:1,3+7,2.2,9\right\}=\frac{39}{7}:\frac{15}{14}\)
\(\Leftrightarrow x:1,3+20,88=5,2\Leftrightarrow x:1,3=-15,68\Leftrightarrow x=-20,384\)
\(5\frac{4}{7}:\left\{x:1,3+8,4.\frac{6}{7}\left[6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\frac{1}{14}\)
thế này có đau đầu ko các bác: tìm x biết
\(5\frac{4}{7}:\left\{x:1,3+8,4.\frac{6}{7}.\left[6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\frac{1}{14}\)
Hello everyone, my name is James. I'm from America. I'm in grade 7. I'm not good at math so can you help me to do this math question?
Find x
\(5\frac{4}{7}:\left\{x:1,3+8,4.\frac{6}{7}.\left[6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\frac{1}{14}\)
I hope you will help me.
wow, it's so hard, i am caculating it
X= -20,384
Tìm x:
a)\(5\dfrac{4}{7}:\left\{x:1,3+8,4.\dfrac{6}{7}.\left[6-\dfrac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\right]\right\}=1\dfrac{1}{14}\)
b)\(\left|3x-2\right|+\left|2x-1\right|=4\)
a: \(\Leftrightarrow\dfrac{39}{7}:\left\{x\cdot\dfrac{10}{13}+7.2\cdot\dfrac{257}{79}\right\}=\dfrac{15}{14}\)
\(\Leftrightarrow x\cdot\dfrac{10}{13}+\dfrac{9252}{395}=\dfrac{26}{5}\)
\(\Leftrightarrow x\simeq-23,69\)
b: TH1: x<1/2
Pt sẽ là 2-3x+1-2x=4
=>-5x+3=4
=>-5x=1
=>x=-1/5(nhận)
TH2: 1/2<=x<2/3
Pt sẽ là 2x-1+2-3x=4
=>1-x=4
=>x=-3(loại)
TH3: x>=2/3
Pt sẽ là 3x-2+2x-1=4
=>5x-3=4
=>5x=7
=>x=7/5(nhận)
\(5\frac{4}{7}\): {x : 1.3 + 8,4 .\(\frac{6}{7}\)[6- \(\frac{\left(2,3+5.6,25\right).7}{8.0,0125+6,9}\)]} = 11
giải giúp mk với thanks các bạn
các anh ,chị giải chi tiết , rõ ràng cho em nha , em cần gấp lắm:
bài 2: tìm x , biết :
\(5\frac{4}{7}\div\left\{x\div1,3+8,4\times\left[6-\frac{\left(2,3+5\div6,25\right)}{8\times0,0125+6,9}\right]\right\}=1\frac{1}{14}\)
tính giá trị biểu thức
a)\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
b)\(6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\)
c)\(\)
a)\(\frac{-212}{351}\)
b)\(\frac{29}{10}\)
c)thiếu đề
tính giá trị biểu thức
a) \(\left|111-324\right|+\left|-2-415\right|+\left|354-123\right|\)
b) \(\left|-2^3+5^2-35\right|-\left|3^4-2^5-12^2\right|\)
c) \(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
d) \(\left(2\frac{1}{3}-1\frac{1}{9}\right):4-\frac{3}{4}\)
e)\(6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\)
g)\(45\frac{10}{63}-44\frac{25}{84}\)