\(\frac{-3}{5}+\frac{28.43}{5.56}+\frac{28.5}{5.24}-\frac{28.21}{5.63}\)

=\(\frac{-3}{5}+\frac{2.2.7.43}{5.2.2.7.2}+\frac{2.2.7.5}{2.2.2.3.5}-\frac{2.2.7.3.7}{5.7.3.3}\)

=\(\frac{-3}{5}+\frac{43}{5.2}+\frac{7}{2.3}-\frac{28}{15}\)

=\(\frac{-3}{5}+\frac{43}{10}+\frac{7}{6}-\frac{28}{15}\)

=\(\frac{-18}{30}+\frac{129}{30}+\frac{35}{30}-\frac{56}{30}\)

=\(\frac{-18+129+35-56}{30}\)

=\(\frac{90}{30}=3\)

Chúc bn học tốt

tự làm đê đồ đầu đất

đề có sai ko bạn

\(\frac{27^2.8^5}{6^6.32^3}=\frac{\left(3^3\right)^2.\left(2^3\right)^5}{2^3.3^3.\left(2^5\right)^3}=\frac{3^6.2^{15}}{2^3.3^3.2^{15}}=\frac{27}{8}\)

học tốt

\(\frac{27^2.8^5}{6^6.32^3}\)=\(\frac{3^6.32^3}{6^6.32^3}\)=\(\frac{3^6}{6^6}\)=\(\frac{729}{46656}\)=\(\frac{1}{64}\)

a)\(\frac{15\times3^5}{27^3\times10^2}=\frac{5\times3^6}{3^9\times5\times20}=\frac{1}{3^3\times20}=\frac{1}{540}\)

b) đề thiếu

c) \(\frac{81^{14}\times3^{17}}{27^{10}\times9^{15}}=\frac{\left(9^2\right)^{14}\times3^{17}}{3^{10}\times9^{10}\times9^{15}}=\frac{9^{28}\times3^{17}}{3^{10}\times9^{25}}=\frac{9^3\times3^7}{1}=1594323\)

xin lỗi!phần b là 32^2

Đáp án là A

Thay x = 8 vào biểu thức ta được:

(27 - 32).x = (27 - 32).8

= [27 + (-32)].8 = [-(32 - 27)].8

= -5.8 = -40

a: \(2^3-5^3:5^2+12\cdot2^2\)

\(=8-5+48\)

\(=51\)

b: \(5\cdot\left[\left(85-35:7\right):8+90\right]-5\)

\(=5\cdot\left[10+90\right]-5\)

=495

a)=16.5-[131-(13-16)]

=80-[131--3] 

=80-134=-54

b

.ta có 

=-3/5+28/5.43/56+28/5.5/24-28/5.21/63 

=-3/5+28/5.(43/56+5/24-21/63)

=5.9/14=45/14

suy ra 

biểu thức b có giá trị là 45/14

a,  15 . { 32 : [ 6 - 5 + 5 ( 9 : 3 ) ] + 3 } - 2018 0

= 15.{32:[1+15]+3}–1

= 15.5–1

= 74

b,  25 . { 2 7 : [ 12 - 4 + 2 2 . 16 : 2 3 ] - 2 4 }

= 25.{128:[8+4.2]–16}

= 25.24

= 600

c,  2019 . { 101 - 1000 : [ 2 2 . 2 3 + 5 6 : 5 3 - 6 2 : 11 - 2018 0 ] }

= 2019.{101–1000:[(32+125–36):11–1]}

= 2019.{101–1000:[121:11–1]}

= 2019.{101–1000:10}

= 2019.1

= 2019

a: A=32+15=47

A=47
B=49
C=3

A = \(\dfrac{18}{26}\) + (-\(\dfrac{5}{27}\)) + (-\(\dfrac{22}{86}\)) + \(\dfrac{12}{39}\) - \(\dfrac{32}{43}\)

A = \(\dfrac{9}{13}\) - \(\dfrac{5}{27}\) -  \(\dfrac{11}{43}\) + \(\dfrac{4}{13}\) - \(\dfrac{32}{43}\)

A = (\(\dfrac{9}{13}\) + \(\dfrac{4}{13}\)) - (\(\dfrac{11}{43}\) + \(\dfrac{32}{43}\)) - \(\dfrac{5}{27}\)

A = \(\dfrac{13}{13}\) - \(\dfrac{43}{43}\) - \(\dfrac{5}{27}\)

A = 1 - 1 - \(\dfrac{5}{27}\)

A = 0 - \(\dfrac{5}{27}\)

A = - \(\dfrac{5}{27}\)

B = -\(\dfrac{10}{12}\) + \(\dfrac{8}{15}\) - \(\dfrac{19}{56}\) + \(\dfrac{3}{-18}\) + \(\dfrac{28}{60}\)

B = - \(\dfrac{5}{6}\) + \(\dfrac{8}{15}\) - \(\dfrac{19}{56}\) - \(\dfrac{1}{6}\) + \(\dfrac{7}{15}\)

B = -(\(\dfrac{5}{6}\) + \(\dfrac{1}{6}\)) - \(\dfrac{19}{56}\) + (\(\dfrac{8}{15}\) + \(\dfrac{7}{15}\))

B = -1  - \(\dfrac{19}{56}\) + 1

B = - \(\dfrac{19}{56}\) 

[32.(-7)] : 32 = (-7).(32:32) = (-7).1 = -7