a) 59 753 498

b) 2 018 016

a) 63 759 500

b) 2 018 016

P=\(\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)

\(=\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)

\(=\frac{2002\times\left(14+1+2001\right)}{2002\times1008}=\frac{2016}{1008}=2\)

(2003*14+1988+2001*2002)  /    ( 2002 + 2002 * 503 + 2002 * 504 )

=4036042:2018016

=2

kết quả là bao nhiêu

bấm máy nha bạn

Kết quả là 2

AAĂn loz

 2003 x 14 + 1988 + 2001 x 2002

=28042 + 1988 + 4006002

=4036032

 2002 + 2002 x 503 +504 x 2002

=2002 x 1 + 2002 x 503 + 504 x 2002

=2002 x (1 + 503 + 504)

=2002 x 908

=1817816

a ) \(\frac{2003\times14+1988+2001+2002}{2002+2002\times503+504\times2002}\)

= \(\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)

= \(\frac{2002\times14+14+1998+2001\times2002}{2002\times1008}\)

= \(\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)

= \(\frac{2002\times\left(14+1+2001\right)}{2002\times1008}\)

= \(\frac{2016}{1008}\)

= 2

b ) Đặt A = 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128

=> 2A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64

=> 2A - A = ( 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ) - ( 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 )

=> A = 1/2 - 1/128

A = 63/128

\(b,\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+..+\frac{1}{128}\)

\(=\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}=A\)

\(\Rightarrow2A=\frac{1}{2}+\frac{1}{2^2}+..+\frac{1}{2^6}\)

\(\Rightarrow2A-A=\left(\frac{1}{2}+\frac{1}{2^2}+..+\frac{1}{2^6}\right)-\left(\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\right)\)

\(\Rightarrow A=\frac{1}{2}-\frac{1}{2^7}\)

(2002+1)x14+1998+2001x2002/2002x1+2002x503+504x(2002+1)

=2002x14+14+1998+2001x2002/2002x1+2002x503+504x2002+504

=2002x(2001+14)+14+1998/2002x(1+503+504)+504

=2015+14+1998/1008+504

=4027/1512

 2003 x 14 + 1988 + 2001 x 2002

=28042 + 1988 + 4006002

=4036032

 2002 + 2002 x 503 +504 x 2002

=2002 x 1 + 2002 x 503 + 504 x 2002

=2002 x (1 + 503 + 504)

=2002 x 908

=1817816