Ta có: \(25^{15}=\left(5^2\right)^{15}=25^{30}\)

\(\left(-8\right)^{10}.3^{30}=8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}=2^{30}.3^{30}=\left(2.3\right)^{30}=6^{30}\)

Mà \(25^{30}>6^{30}\) nên \(25^{15}>\left(-8\right)^{10}.3^{30}\)

Vậy \(25^{15}>\left(-8\right)^{10}.3^{30}\)

ta có 25^15=(5^2)^15=5^30

(-8)^10 . 3^30=(2^3)^10 . 3^30=2^30 . 3^30=6^30

vì 5<6 nên 5^30<6^30

vậy 25^15 > (-8)^10 . 3^30

\(1)\) \(3^x+3^{x+1}+3^{x+2}=351\)

\(\Leftrightarrow\)\(3^x.1+3^x.3+3^x.3^2=351\)

\(\Leftrightarrow\)\(3^x\left(1+3+3^2\right)=351\)

\(\Leftrightarrow\)\(3^x.13=351\)

\(\Leftrightarrow\)\(3^x=\frac{351}{13}\)

\(\Leftrightarrow\)\(3^x=27\)

\(\Leftrightarrow\)\(3^x=3^3\)

\(\Leftrightarrow\)\(x=3\)

Vậy \(x=3\)

Chúc bạn học tốt ~ 

\(2)\) 

\(a)\) Ta có : 

\(25^{15}=\left(5^2\right)^{15}=5^{2.15}=5^{30}\)

\(8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}=2^{30}.3^{30}=\left(2.3\right)^{30}=6^{30}\)

Vì \(5^{30}< 6^{30}\) nên \(25^{15}< 8^{10}.3^{30}\)

Vậy \(25^{15}< 8^{10}.3^{30}\)

\(b)\) Ta có : 

\(\left(0,3\right)^{20}=\left[\left(0,3\right)^2\right]^{10}=\left(0,09\right)^{10}\)

Vì \(\left(0,1\right)^{10}>\left(0,09\right)^{10}\) nên \(\left(0,1\right)^{10}>\left(0,3\right)^{20}\)

Vậy \(\left(0,1\right)^{10}>\left(0,3\right)^{20}\)

Chúc bạn học tốt ~ 

a)

Dễ thấy:

\(-\frac{1274}{2530}< 0< 1,2\)

\(\Rightarrow-\frac{1274}{2530}< 1,2\)

b)

Ta có :

\(25^{15}=\left(5^2\right)^{15}=5^{30}\)

\(8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}=2^{30}.3^{30}=6^{30}\)

Vì \(5^{30}< 6^{30}\)

=> \(25^{15}< 8^{10}.3^{30}\)

ta có:

25^15=(5^2)^15=5^30

8^10x3^30=(2^3)^10x3^30=2^30x3^30=(2x3)^30=6^30

vì 5>6 nên 5^30>6^30

vậy 25^15>8^10x3^30

\(25^{15}=\left(5^2\right)^{15}=5^{30}\)

\(8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}=2^{30}.3^{30}=6^{30}\)

\(\Rightarrow25^{15}< 8^{10}.3^{30}\)

Trả lời :

Bạn kia bạn làm đúng rồi nha 

Học tốt !

a) Ta có: \(25^{15}=\left(5^2\right)^{15}=5^{30}\)

               \(8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}\)\(=2^{30}.3^{30}=6^{30}\)

Vì \(5^{30}< 6^{30}\)nên \(25^{15}< 8^{10}.3^{30}\)

b) Ta có: \(\frac{4^{15}}{7^{30}}=\frac{\left(2^2\right)^{15}}{7^{30}}=\frac{2^{30}}{7^{30}}\)

\(\frac{8^{10}.3^{30}}{7^{30}.4^{15}}=\frac{\left(2^3\right)^{10}.3^{30}}{7^{30}.\left(2^2\right)^{15}}=\frac{2^{30}.3^{30}}{7^{30}.2^{30}}=\frac{3^{30}}{7^{30}}\)

Vì \(2^{30}< 3^{30}\)nên \(\frac{2^{30}}{7^{30}}< \frac{3^{30}}{7^{30}}\)hay \(\frac{4^{15}}{7^{30}}< \frac{8^{10}.3^{30}}{7^{30}.4^{15}}\)

_Học tốt_

25^15>(-8)^10 x 3^30

k cho mình nhé

Ta có:

8¹⁰ . 3³⁰ = ( 2³)¹⁰ . 3³⁰

= 2³⁰ . 3³⁰

= 6³⁰

= (6²)¹⁵

⁼ 36¹⁵

Vì 25<36

=>25¹⁵ < 36¹⁵

hay 25¹⁵ < 8¹⁰ . 3³⁰