a ) 4 x y = 502 x 8 = 4016

y = 4016 : 4

y = 1004

a ) 4 x y = 502 x 8 = 4016

y = 4016 : 4

y = 1004

Ta có: \(502\times m+n\)

Tại \(\hept{\begin{cases}m=4\\n=8\end{cases}}\) ta được:

\(BT=502\times4+8=2016\)

4 × 125 × 25 × 8

= (4 × 25) × (125 × 8)

= 100 × 1000

= 100 000

2 × 8 × 50 × 25 × 125

= (2 × 50) × (8 × 125) × 25

= 100 × 1000 × 125

= 12 500 000

2 × 3 × 4 × 5 × 50 × 25

= (2 × 50) × (4 × 25) × (3 × 5)

= 100 × 100 × 15

= 150 000

25 × 20 × 125 × 8 - 8 × 20 × 5 × 125

= 8 × 125 × 20 × (25 - 5)

= 1000 × 20 × 20

= 400 000

- (25 x 4) x (125 x8)=100 x 1000 =100000

- (50 x 2) x (8 x 125) x 25=100 x 1000 x 25 =2500000

- (2 x 50 ) x (4 x 25) x (3 x5)=100 x 100 x 15=150000

- 25 x 20 x125 x 8 - 5

= (20 x 5) x (125 x 8) -25=100 x 1000 -5 =100000 - 5 =99995

4 *125*25*8

=4*25*125*8

=100*1000

=100000

2*8*50*25*125

=2*50*8*125*25

=100*1000*25

=2500000

2*3*4*5*50*25

=2*50*4*25*3*5

=100*100*15

=150000

25*20*125*8-8*20*5*125

=25*4*5*125*8-8*125*20*5

=100*1000*5-1000*100

=500000-100000

=400000

=

n) Theo bài ra ta có: \(\frac{x+1}{2008}=\frac{502}{x+1}\)

=> (x+1).(x+1) = 2008.502

=> (x+1)² = 1008016

=> (x+1)² = 1004²

=> x+1 = 1004

=> x = 2004-1

=> x = 2003

Vậy x = 2003

p) Theo bà ra ta có: \(\left|\frac{5}{4}.x-\frac{7}{2}\right|-\left|\frac{5}{8}.x+\frac{3}{5}\right|=0\)

=> \(\left|\frac{5}{4}.x-\frac{7}{2}\right|=\left|\frac{5}{8}.x+\frac{3}{5}\right|\)

=> \(\frac{5}{4}.x-\frac{7}{2}=\pm\left(\frac{5}{8}.x+\frac{3}{5}\right)\)

=> \(\left[\begin{array}{nghiempt}\frac{5}{4}.x-\frac{7}{2}=\frac{5}{8}.x+\frac{3}{5}\\\frac{5}{4}.x-\frac{7}{2}=\frac{-5}{8}.x-\frac{3}{5}\end{array}\right.\)

=> \(\left[\begin{array}{nghiempt}\frac{5}{4}.x-\frac{5}{8}.x=\frac{3}{5}+\frac{7}{2}\\\frac{5}{4}.x+\frac{5}{8}.x=\frac{-3}{5}+\frac{7}{2}\end{array}\right.\)

=> \(\left[\begin{array}{nghiempt}\frac{5}{8}.x=\frac{41}{10}\\\frac{15}{8}.x=\frac{29}{10}\end{array}\right.\)

=> \(\left[\begin{array}{nghiempt}x=\frac{164}{25}\\x=\frac{116}{75}\end{array}\right.\)

Vậy x=\(\frac{164}{25}\) hoặc x=\(\frac{116}{75}\)

Dễ mà!

\(\frac{x+1}{2008}\)=\(\frac{502}{x+1}\)

=>(x+1)²=502.2008=1008016

=>(x+1)=1004  => x=1004-1=1003

Vậy x=1003

a, 2019 x (2 x 5)

= 2019 x 10

= 20 190

b, (5 x 2) x (8 x 125) x 9

= 10 x 1000 x 9

= 90 000

c, (4 x 25) x 2019

= 100 x 2019

= 201 900

d, (50 x 2) x (125 x 8) x 202

= 100 x 1000 x 202

= 20 200 000

a) 2019 x 2 x 5

= (2 x 5) x 2019

= 10 x 2019

b) 5 x 8 x 9 x 2 x 125

= (5 x 2) x (125 x 8) x 9

= 10 x 1000 x 9

= 10000 x 9

= 90000

c) 4 x 2019 x 25

= (4 x 25) x 2019

= 100 x 2019

= 201900

d) 50 x 125 x 2 x 8 x 202

= (50 x 2) x (125 x 8) x 202

= 100 x 1000 x 202

= 100000 x 202

= 20200000