(√6 +2)(√3-√2)
\(x^3=\left(\sqrt[3]{5+2\sqrt{6}}+\sqrt[3]{5-2\sqrt{6}}\right)^3=\sqrt[3]{5+2\sqrt{6}}^3\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)^2}.\sqrt[3]{5-2\sqrt{6}}+3\sqrt[3]{5+2\sqrt{6}}.\sqrt[3]{\left(5-2\sqrt{6}\right)^2}+\sqrt[3]{5-2\sqrt{6}}^3\)
\(=5+2\sqrt{6}+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5+2\sqrt{6}}\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5-2\sqrt{6}}+5-2\sqrt{6}\)
\(=5+5+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5-2\sqrt{6}}\)
\(=10+ 3\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{5-2\sqrt{6}}\)
p/s : có bạn hỏi nên mình đăng , các bạn đừng report nhé
>, <, =?
6…5 | 3…6 | 6…1 | 3…3 |
6…4 | 6…3 | 4…2 | 3…5 |
6…2 | 6…6 | 2…6 | 3…4 |
Lời giải chi tiết:
6 > 5 | 3 < | 6 > 1 | 3 = 3 |
6 > 4 | 6 > 3 | 4 > 2 | 3 < 5 |
6 > 2 | 6 = 6 | 2 < 6 | 3 < 4 |
Rút gọn: (6 ^ 6 + 2 ^ 7 * 3 ^ 6 + 2 ^ 6 * 3 ^ 7)/(4.2 ^ 3 * 3 ^ 2 * 2 ^ 2)
\(\dfrac{6^6+2^7.3^6+2^6.3^7}{4.2^3.3^2.2^2}\)
\(=\dfrac{\left(2^2.3\right)^6+2^7.3^6+2^6.3^7}{2^2.2^3.3^2.2^2}\)\(=\dfrac{2^{12}.3^6+2^7.3^6+2^6.3^7}{2^7.3^2}\)
\(=\dfrac{2^6.3^6.\left(2^6+2+3\right)}{2^7.3^2}\)\(=\dfrac{3^4.69}{2}=\dfrac{5589}{2}\)
Các phân số 1/3: 1/6: 5/2: 3/2 xếp theo thứ tự tăng dần
a. 1/3; 1/6; 5/2; 3/2 b. 1/3; 5/2; 1/6; 3/2 c. 1/6; 1/3; 3/2; 5/2 d. 1/6; 3/2; 3/2; 5/2
Bài 3: Tính
1 + 5 =
2 + 3 =
3 + 6 =
4 + 5 =
5 + 1 =
6 + 2 =
7 + 1 =
8 + 1 =
9 + 0 =
10 + 2=
11 + 2 =
1 + 3 =
2 + 6 =
3 + 7 =
4 + 2 =
5 + 2 =
6 + 3 =
7 + 3 =
8 + 2 =
9 + 1 =
10 + 0 =
11 + 3 =
1 + 4 =
2 + 8 =
3 + 2 =
4 + 1 =
5 + 4 =
6 + 4 =
7 + 2 =
8 + 0 =
9 + 2 =
10 + 6 =
11 + 6 =
Bài 4: Tính
6 - 2 =
3 - 1 =
4 - 2 =
5 - 2 =
8 - 5 =
10 - 6 =
4 - 3 =
3 - 3 =
5 - 1 =
2 - 2 =
3 - 1 =
4 - 1 =
2 - 1 =
4 - 3 =
5 - 0 =
9 - 4 =
8 - 6 =
7 - 3 =
8 - 4 =
7 - 6 =
9 - 5 =
7 - 7=
5 - 3 =
5 - 3=
6 - 3 =
7 - 3 =
7 - 6 =
6 - 5 =
9 - 7 =
9 - 3 =
8 - 8 =
8 - 0 =
5 - 3 =
Bài 5: Tính
6 - 2 =
5 + 2 =
9 - 5 =
2 + 0 =
8 + 2 =
4 - 4 =
7 - 3 =
3 + 6 =
7 + 2 =
9 - 5 =
3 + 6 =
1 + 5 =
7 - 6 =
7 + 1 =
3 + 5 =
2 - 1 =
6 + 3 =
5 + 2 =
9 - 4 =
6 + 4 =
4 + 2 =
6 + 1=
7 - 7=
4 + 3 =
7 + 3 =
5 - 2 =
6 - 5 =
8 - 6 =
6 - 4 =
7 - 3 =
10 + 0 =
5 +4 =
8 - 2 =
Tính:
6 - 4 -2 = 6 - 2 - 2 = 6 - 3 - 3 =
6 - 2 -4 = 6 - 1 - 2 = 6 - 6 =
6 - 4 - 2 = 0 6 - 2 - 2 = 2 6 - 3 - 3 = 0
6 - 2 - 4 = 0 6 - 1 - 2 = 3 6 - 6 = 0
6 - 4 -2 = 0 6 - 2 - 2 = 2 6 - 3 - 3 =0
6 - 2 -4 =0 6 - 1 - 2 = 3 6 - 6 =0 nha em, chúc em năm mới học giỏi và cố gắng lên lớp 2 giống anh nha!
Tính:
6 – 3 – 1 = … | 1 + 3 + 2 = … | 6 – 1 – 2 = … |
6 – 3 – 2 = … | 3 + 1 + 2 = … | 6 – 1 – 3 = … |
Lời giải chi tiết:
6 – 3 – 1 = 2 | 1 + 3 + 2 = 6 | 6 – 1 – 2 = 3 |
6 – 3 – 2 = 1 | 3 + 1 + 2 = 6 | 6 – 1 – 3 = 2 |
6 – 3 – 1 = 2… | 1 + 3 + 2 = 6… | 6 – 1 – 2 = 3… |
6 – 3 – 2 = 1… | 3 + 1 + 2 = 6… | 6 – 1 – 3 = 2… |
6 – 3 – 1 = 2 | 1 + 3 + 2 = 6 | 6 – 1 – 2 = 3 |
6 – 3 – 2 = 1 | 3 + 1 + 2 = 6 | 6 – 1 – 3 = 2 |
HT nhé
Tính:
1 + 3 + 2 = 6 - 3 -1 = 6 - 1 - 2 =
3 + 1 + 2 = 6 - 3 -2 = 6 - 1 - 3 =
1 + 3 + 2 = 6 6 - 3 -1 = 2 6 - 1 - 2 = 3
3 + 1 + 2 = 6 6 - 3 -2 = 1 6 - 1 - 3 = 2
1 + 3 + 2 =6 6 - 3 -1 =2 6 - 1 - 2 =3
3 + 1 + 2 = 6 6 - 3 -2 = 1 6 - 1 - 3 =2
5) (3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) 6) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
7) (5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) 8) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 pls help me
5: \(=3-\dfrac{1}{4}+\dfrac{2}{3}-5+\dfrac{1}{3}+\dfrac{6}{5}-6+\dfrac{7}{4}-\dfrac{3}{2}\)
\(=3-5-6+\dfrac{-1}{4}+\dfrac{7}{4}+\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{6}{5}-\dfrac{3}{2}\)
\(=-8+\dfrac{3}{2}+1+\dfrac{-3}{10}\)
\(=-7+\dfrac{15-3}{10}=-7+\dfrac{6}{5}=-\dfrac{29}{5}\)
6: \(=6-\dfrac{2}{3}+\dfrac{1}{2}-5-\dfrac{5}{3}+\dfrac{3}{2}-3+\dfrac{7}{3}-\dfrac{5}{2}\)
\(=6-5-3-\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{7}{3}+\dfrac{1}{2}+\dfrac{3}{2}-\dfrac{5}{2}\)
\(=-2-\dfrac{1}{2}=-\dfrac{5}{2}\)
7: \(=\dfrac{5}{3}-\dfrac{3}{7}+9-2-\dfrac{5}{7}+\dfrac{2}{3}+\dfrac{8}{7}-\dfrac{4}{3}-10\)
\(=9-2-10+\dfrac{5}{3}+\dfrac{2}{3}-\dfrac{4}{3}+\dfrac{-3}{7}-\dfrac{5}{7}+\dfrac{8}{7}\)
=-3+1
=-2
8: \(=8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{2}{4}+\dfrac{9}{7}\)
\(=8+6-3+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}-1-\dfrac{2}{4}\)
\(=11+2-1-\dfrac{1}{2}\)
=11+1/2
=11,5
>, <, = ?
2 + 3 … 6 | 3 + 3 … 5 | 6 – 0 … 4 |
2 + 4 … 6 | 3 + 2 … 5 | 6 – 2 … 4 |
Lời giải chi tiết:
2 + 3 < 6 | 3 + 3 > 5 | 6 – 0 > 4 |
2 + 4 = 6 | 3 + 2 = 5 | 6 – 2 = 4 |