\(a,-7x^2+11x+6\)

\(=-7x^2-3x+14x+6\)

\(=-x\left(7x+3\right)+2\left(7x+3\right)\)

\(=\left(2-x\right)\left(7x+3\right)\)

\(b,-x^2-4x-3\)

\(=-\left(x^2+4x+3\right)\)

\(=-\left(x^2+x+3x+3\right)\)

\(=-\left[x\left(x+1\right)+3\left(x+1\right)\right]\)

\(=-\left[\left(x+3\right)\left(x+1\right)\right]\)

\(=\left(-x-3\right)\left(x+1\right)\)

\(A=-7x^2+11x+6\)

\(A=-7x^2+14x-3x+6\)

\(A=-7x\left(x-2\right)-3\left(x-2\right)\)

\(A=\left(x-2\right)\left(-7x-3\right)\)

\(B=-x^2-4x-3\)

\(B=-x^2-x-3x-3\)

\(B=-x\left(x+1\right)-3\left(x+1\right)\)

\(B=\left(x+1\right)\left(-x-3\right)\)

a, − 7x + 11x + 6

= −7x − 3x + 14x + 6

= −x 7x + 3 + 2 7x + 3

= 2 − x 7x + 3 b, − x − 4x − 3

= − x + 4x + 3

= − x + x + 3x + 3

= − x x + 1 + 3 x + 1

= − x + 3 x + 1

= −x − 3 x + 1 2 2 ( ) ( ) ( ) ( ) 2 ( 2 ) ( 2 ) [ ( ) ( )

\(x^3y^3+x^2y^2+4=x^3y^3+2x^2y^2-x^2y^2+4\)

\(=\left(x^3y^3+2x^2y^2\right)-\left(x^2y^2-4\right)=x^2y^2\left(xy+2\right)-\left(xy-2\right)\left(xy+2\right)\)

\(=\left(xy+2\right)\left(x^2y^2-xy+2\right)\)

Phân tích đa thức thành nhân tử( pp tách hạng tử):

x³y³+x²y²+4

Câu trả lời của mik giống bạn Nguyễn Lê Tiến Huy .

a) \(x^2-5x+6=x^2-2x-3x+6=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)

b) \(x^2+x-12=x^2+4x-3x-12=x.\left(x+4\right)-3.\left(x+4\right)=\left(x+4\right)\left(x-3\right)\)

cho mik câu trả lời

a) \(x^2-5x+6=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\)

b)\(3x^2+9x-30=3x^2-6x+15x-30=3\left(x-2\right)\left(x+5\right)\)

c)\(x^2-7x+12=x^2-3x-4x+12=\left(x-3\right)\left(x-4\right)\)

d)\(x^2-7x+10=x^2-2x-5x+10=\left(x-2\right)\left(x-5\right)\)

a) \(x^2-5x+6=x^2-2x-3x+6=\left(x^2-2x\right)-\left(3x-6\right)\)

\(=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)

b) \(3x^2+9x-30=3\left(x^2+3x-10\right)=3\left(x^2-2x+5x-10\right)\)

\(=3\left[\left(x^2-2x\right)+\left(5x-10\right)\right]=3\left[x\left(x-2\right)+5\left(x-2\right)\right]\)

\(=3\left(x-2\right)\left(x+5\right)\)

c) \(x^2-7x+12=x^2-3x-4x+12=\left(x^2-3x\right)-\left(4x-12\right)\)

\(=x\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x-4\right)\)

d) \(x^2-7x+10=x^2-2x-5x+10=\left(x^2-2x\right)-\left(5x-10\right)\)

\(=x\left(x-2\right)-5\left(x-2\right)=\left(x-2\right)\left(x-5\right)\)

a,\(x^2-5x+6=x^2-2x-3x+6 =x(x-2)-3(x-2) =(x-2)(x-3)\)

b,\(3x^2+9x-30=3x^2+15x-6x-30=3x(x+5)-6(x+5)=(x+5)(3x-6)\)

c,\(x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)\)

d,\(x^2-7x+10=x^2-2x-5x+10=x(x-2)-5(x-2)=(x-2)(x-5)\)

Hok tốt !!!!!!!!!!

a) \(x^3+4x^2-21x\)

\(=x\left(x^2+4x-21\right)\)

\(=x\left(x^2-3x+7x-21\right)\)

\(=x\left[x\left(x-3\right)+7\left(x-3\right)\right]\)

\(=x\left(x-3\right)\left(x+7\right)\)

b) \(5x^3+6x^2+x\)

\(=x\left(5x^2+6x+1\right)\)

\(=x\left(5x^2+5x+x+1\right)\)

\(=x\left[5x\left(x+1\right)+\left(x+1\right)\right]\)

\(=x\left(x+1\right)\left(5x+1\right)\)

c) \(x^3-7x+6\)

\(=x^3+2x^2-3x-2x^2-4x+6\)

\(=x\left(x^2+2x-3\right)-2\left(x^2+2x-3\right)\)

\(=\left(x-2\right)\left(x^2+2x-3\right)\)

\(=\left(x-2\right)\left(x-1\right)\left(x+3\right)\)

d) \(3x^3+2x-5\)

\(=3x^3+3x^2+5x-3x^2-3x-5\)

\(=x\left(3x^2+3x+5\right)-\left(3x^2+3x+5\right)\)

\(=\left(x-1\right)\left(3x^2+3x+5\right)\)

Bạn ơi ở câu hỏi tương tự có pp bậc ba trở lên đấy

Mk lm câu a nha! :D 

a) 4x + 3x - 10 

 = ( 4x - 5 ) ( x+2 ) 

^^ Học tốt!  

Dúng không thế I have a crazy idea

Làm luôn câu b đi I have a crazy idea