C. Remind

C

C

3.

Từ BBT ta thấy hàm đồng biến trên các khoảng \(\left(-\infty;-1\right)\) và \(\left(1;+\infty\right)\)

B đúng

4.

Từ BBT ta thấy hàm đồng biến trên các khoảng \(\left(-\infty;-1\right)\) và \(\left(0;1\right)\)

A đúng

1.

B sai (thiếu điều kiện \(f'\left(x\right)=0\) tại hữu hạn điểm)

Câu 2 đề thiếu yêu cầu

Câu 9:

Từ đồ thị ta thấy hàm đồng biến trên các khoảng \(\left(-\infty;0\right)\) và \(\left(2;+\infty\right)\)

\(\Rightarrow\) A đúng do \(\left(-1;0\right)\subset\left(-\infty;0\right)\)

1. If you are calm, you won't make a wrong decision.
2. These wonderful poems were written by a great poet.
3.Because of rained heavily, Jane didn't go fishing yesterday.
4.Vietnamese people use Khue Van pavilion as a symbol of Hanoi.
5. His idea is not the same as me.
6. Those modern paintings are not as expensive as these Dong Ho paintings.
7. What food do you like?
8.These machines are used by chefs to mix the ingredients.
9. It i've most seen such a boring movie.
10. There are not many eggs in the fridge.
11.They started living there 2 years ago.
12. I have never drunk cocktail before.
13.This exercise is not as difficult as the last one.
14. I find playing computer games boring.
15. The new building has the same height as the old one.
16. She didn't have enough eggs to make an omelette.
17. In spite of promising that wouldn't be late, he didn't arrive until 9 o'clock.
18. 

1)

$a)m_{Cl_2} = 0,3.71 = 21,3(gam)$
$b)V_{Cl_2} = 0,3.22,4 = 6,72(lít)$
Số phân tử $= 0,3.6.10^{23} = 1,8.10^{23}$ phân tử

2)

$a)m_{CO_2} = 0,45.44 = 19,8(gam)$
$b) V_{CO_2} = 0,45.22,4 = 10,08(lít)$
Số phân tử $= 0,45.6.10^{23} = 2,7.10^{23}$ phân tử

1 B

2 B

3 A

4 D

5 A

6 C

7 D

8 D

9 A

10 C

11 B

12 C

13 B

14 B

15 B

16 D

17 C

18 A

19 B

20 B

III

1 C

2 A

3 C

4 D

5 D

6 B

7 D

8 B

9 D

10 A

11 B

T T F T T F

The Soup Kitchen, founded in 1986, is a resource for the homeless, elderly, lonely and poor inCentral London, providing free hot meals, clothes and toiletries, and creating a sense of belonging and community. Serving around 70 people a day from 10 am -12 noon on Monday, Tuesday, Thursday, Friday and Saturday, with the Clothes Closet open on alternate Mondays, four to five volunteers are required each morning to carry out this vital work.
 The Soup Kitchen is run by a Board of Trustees, a part-time Director and Kitchen Manager, three more staff and a team of volunteers. Support for The Soup Kitchen comes from individuals, corporations and trusts. Volunteers and donations (both financial and in-kind) are vital to support our work and enable us to continue this service to the community.

1. The Soup Kitchen is a non-profit organization. T
2. It provides free meals for people in need. T 
3. It opens five days a week from 10am to 12pm.  F 
4. Clothing is provided every Monday morning. T
5. The organization is funded by donations from individuals, corporations and trusts. T 
6. People can only donate money to the Soup Kitchen. F 

29: Ta có: \(\dfrac{1}{\sqrt{7}+\sqrt{5}}+\dfrac{2}{1-\sqrt{7}}\)

\(=\dfrac{\sqrt{7}-\sqrt{5}}{2}-\dfrac{2\sqrt{7}-2}{6}\)

\(=\dfrac{3\sqrt{7}-3\sqrt{5}-2\sqrt{7}+2}{6}\)

\(=\dfrac{-3\sqrt{5}-2}{6}\)

30: Ta có: \(\dfrac{4}{1-\sqrt{3}}+\dfrac{\sqrt{3}-1}{\sqrt{3}+1}\)

\(=\dfrac{-4\sqrt{3}-4}{2}+\dfrac{4-2\sqrt{3}}{2}\)

\(=\dfrac{-4\sqrt{3}-4+4-2\sqrt{3}}{2}=-3\sqrt{3}\)

31: Ta có: \(\dfrac{1}{\sqrt{2}-\sqrt{3}}-\dfrac{3}{\sqrt{18}+2\sqrt{3}}\)

\(=-\sqrt{3}-\sqrt{2}-\dfrac{3}{3\sqrt{2}+2\sqrt{3}}\)

\(=-\sqrt{3}-\sqrt{2}-\dfrac{9\sqrt{2}-6\sqrt{3}}{6}\)

\(=\dfrac{-6\sqrt{3}-6\sqrt{2}-9\sqrt{2}+6\sqrt{3}}{6}=\dfrac{-15\sqrt{2}}{6}\)

\(=\dfrac{-5\sqrt{2}}{2}\)

29.

\(=\frac{\sqrt{7}-\sqrt{5}}{(\sqrt{7}-\sqrt{5})(\sqrt{7}+\sqrt{5})}+\frac{2(1+\sqrt{7})}{(1-\sqrt{7})(1+\sqrt{7})}\)

\(=\frac{\sqrt{7}-\sqrt{5}}{7-5}+\frac{2(1+\sqrt{7})}{1-7}=\frac{\sqrt{7}-\sqrt{5}}{2}-\frac{1+\sqrt{7}}{3}=\frac{\sqrt{7}-3\sqrt{5}-2}{6}\)

30.

\(=\frac{4(1+\sqrt{3})}{(1-\sqrt{3})(1+\sqrt{3})}+\frac{(\sqrt{3}-1)^2}{(\sqrt{3}+1)(\sqrt{3}-1)}=\frac{4(1+\sqrt{3})}{1-3}+\frac{4-2\sqrt{3}}{3-1}\)

\(=\frac{4(1+\sqrt{3})}{-2}+\frac{4-2\sqrt{3}}{2}=-2(1+\sqrt{3})+2-\sqrt{3}=-3\sqrt{3}\)