tim x,y thuoc z
\(\frac{x}{3}=\frac{6}{y}\)
Tim x,y thuoc Z biet
a.\(\frac{x+8}{y-7}=\frac{1}{3}\)và x-y=1
b.\(\frac{2x}{x-4y}=\frac{1}{y}\)
CHO E=\(\left(\frac{x^3}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{2+x}\right):\left(x+2+\frac{10-x^2}{x-2}\right)\)
a) Rut gon E
b) Tim x thuoc Z sao cho E thuoc Z
1)tim x biet
\(\frac{x-2}{-3}\)=\(\frac{25}{15}\)
2)tim x thuoc Z
\(\frac{x-1}{4}\) =\(\frac{8}{3}\)
3)tim x y thuoc Z biet
\(\frac{x}{7}\)=\(\frac{9}{y}\) va x>y
tim x thuoc Z biet : 2x+\(\frac{1}{7}=\frac{1}{y}\)
Tim cac so x;y thuoc z sao cho
\(\frac{1}{x}+\frac{2}{y}=2\)
x=1
y=2
ai k mk ,mk k lai, neu k thi phai nhan tin thi to moi biet
Tim x,y thuoc Z biet: \(2x+\frac{1}{7}=\frac{1}{y}\)
\(\frac{6}{x-3}+\frac{2x^2}{^{x^2}-1}+\frac{6-2x}{x^{3^{ }}-3x^2-x+3}\)
a / Rut gon A
b/ Tim x thuoc Z de A thuoc Z
c/ Tinh gia tri cua A khi x = căn 2
1 tim x,y,z biet
\(\frac{-4}{x}=\frac{y}{-14}=\frac{12}{21}=\frac{z}{-63}\)
2 tim n thuoc z n khac 0
a \(\frac{1111100:n}{23331:n}+\frac{-10}{-21}\)
b \(\frac{1075:n}{600:n}=\frac{43}{24}\)
TIM X, Y ,Z , BIET :\(\frac{x-2}{6}=\frac{y+3}{9}=\frac{z-7}{10}\)va \(x+y+z=106\)
Đặt \(\frac{x-2}{6}=\frac{y+3}{9}=\frac{z-7}{10}=k\Rightarrow\hept{\begin{cases}x=6k+2\\y=9k-3\\z=10k+7\end{cases}}\)
Theo đề bài: x+y+z=106
<=>\(6k+2+9k-3+10k+7=106\)
<=>\(25k+6=106\)
<=> 25k = 100
<=> k = 4
=> \(\hept{\begin{cases}x=6.4+2=26\\y=9.4-3=33\\z=10.4+7=47\end{cases}}\)
Vậy .........................
bảo oline math giải hộ dễ thế hihi
chúc thành công