\(\frac{x}{3}=\frac{6}{y}\)
\(\Rightarrow xy=3.6\)
\(\Rightarrow xy=18\)
=> x = 1 hoặc y = 18
x = 2 hoặc y = 9
x = 3 hoặc y = 6
x = 6 hoặc y= 3
x = 9 hoặc y = 2
x = 18 hoặc y = 1
Tim x,y thuoc Z biet
a.\(\frac{x+8}{y-7}=\frac{1}{3}\)và x-y=1
b.\(\frac{2x}{x-4y}=\frac{1}{y}\)
1)tim x biet
\(\frac{x-2}{-3}\)=\(\frac{25}{15}\)
2)tim x thuoc Z
\(\frac{x-1}{4}\) =\(\frac{8}{3}\)
3)tim x y thuoc Z biet
\(\frac{x}{7}\)=\(\frac{9}{y}\) va x>y
Tim cac so x;y thuoc z sao cho
\(\frac{1}{x}+\frac{2}{y}=2\)
1 tim x,y,z biet
\(\frac{-4}{x}=\frac{y}{-14}=\frac{12}{21}=\frac{z}{-63}\)
2 tim n thuoc z n khac 0
a \(\frac{1111100:n}{23331:n}+\frac{-10}{-21}\)
b \(\frac{1075:n}{600:n}=\frac{43}{24}\)
Tim x thuoc Z, biet: \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{x\left(x+1\right):2}=\frac{2009}{2011}\)
tim x,y thuoc z biet
-24/-6 = x/3 = 4/y^2 = z^3/-2
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100Tim x biet :
a, \(4\frac{1}{3}\left(\frac{1}{6}-\frac{1}{2}\right)\le x\le\frac{2}{3}\left(\frac{1}{2}-\frac{1}{3}-\frac{3}{4}\right)\) x thuoc Z
b , \(|x-3|+1=x\)
Tim x,y\(\in\) z biet :
a)\(\frac{x}{3}-\frac{2}{y}=\frac{1}{5}\) b)\(\frac{2}{x}-\frac{y}{3}=\frac{5}{6}\)
c)\(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\) d) \(\frac{x}{6}-\frac{2}{y}=\frac{1}{4}\)
