a,  3 x - 2 3 = 2 . 32

3 x - 2 3 = 64

3 x - 2 3 = 4 3

3 x - 2 = 4 ⇔ x = 2

b,  5 x + 1 - 5 x = 500

5 x . 5 - 5 x = 500

5 x . ( 5 - 1 ) = 500

5 x . 4 = 500

5 x = 125 = 5 3

x = 3

a,(-12).x= 60-12

(-12).x=48

x=48:(-12)

x = -4

b,(-5).x + 5 = -24+6

(-5).x + 5 = 30

(-5).x      = 30-5

(-5).x      = 25

x = 25 : (-5)

x = -5

c,

$3x+36=-7x-64$

$10x=-100$

$x=-10$

$b,-5x-178=14x+145$

$-19x=323$

$x=-17$

Tham khảo:

a)

( 2x + 1 ) . ( y - 3 ) = 12

Vì 2x +1 là số lẻ.

Do ( 2x + 1 ) . ( y - 3) = 12

=> 2x + 1   :  y - 3 thuộc Ư ( 12) = { 1 ; 2 ; 3 ; 4 ; 6 ; 12 }

=> 2 x +1 = 1 => x= 0 

hoặc y - 3 = 12 => y = 15

=> 2x + 1 = 3 => x = 2

hoặc y - 3 = 4 => y = 7

=> 2x + 1 = 2 ( L)

VẬY ( x ; y) = { ( 0 ; 15 ) ; ( 2 ; 7) }

a, (2x + 1) (y - 3) = 12
=> y-3 ϵ Ư(12) = {+-1; +-2; +-3; +-4; +-6; +-12}
=> Tìm các giá trị của y (tự làm:>)
Ta có bảng sau (tự làm nốt:>)
2x+1
y-3
x
y
=> (x; y) =...
b, Ý này tương tự ý trên
còn nếu bạn muốn mình giải chi tiết thì bảo nha:>

a) (2x+1)(y-3)=12
 <=> 2x+1=12
        y-3=12
<=> x=11/2
       y=15

a) (3.x - 2)³ = 2.32

=> (3.x - 2)³ = 64 = 4³

=> 3.x - 2 = 4

=> 3.x = 6

=> x = 2.

b) 5^x+1 - 5^x = 500

=>5^x.5 - 5^x = 500

=> 5^x.(5 - 1) = 500

=> 5^x.4 = 500

=> 5^x = 125 = 5³

=> x = 3

\(a,\left(3.x-2\right)^3=2.32\)

\(\Rightarrow\left(3x-2\right)^3=64\)

\(\Rightarrow\left(3x-2\right)^3=4^3\)

\(\Rightarrow3x-2=4\)

\(\Rightarrow3x=4+2=6\)

\(\Rightarrow x=2\)

\(b,5^{x+1}-5^x=500\)

\(\Rightarrow5^x.5-5^x=500\)

\(\Rightarrow5^x\left(5-1\right)=500\)

\(\Rightarrow5^x=500:4=125=5^3\)

\(\Rightarrow x=3\)

a,(3.x-2)³=64

(3.x-2)³=4³

(3.x-2)=4

3.x=4+2

3.x=6

x=6:3=2

a, (3.x-2)³=2.32

=>(3x-2)³=64

=>(3x-2)³=4³

=>3x-2=4

=>3x=6

=>x=2

b,5^x+1-5^x=500

=>5^x(5-1)=500

=>5^x*4=500

=>5^x=125

=>5^x=5³

=>x=3

\(a,\Leftrightarrow6x^2-6x^2-11x+10=-12\\ \Leftrightarrow-11x=-22\\ \Leftrightarrow x=2\\ b,\Leftrightarrow x^3+27-x^3-2x=12-5x\\ \Leftrightarrow3x=-15\\ \Leftrightarrow x=-5\\ c,\Leftrightarrow x^2-6x-16=0\\ \Leftrightarrow\left(x-8\right)\left(x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\)

a: ta có: \(6x^2-\left(2x+5\right)\left(3x-2\right)=-12\)

\(\Leftrightarrow6x^2-6x^2+4x-15x+10=-12\)

\(\Leftrightarrow-11x=-22\)

hay x=2

b: Ta có: \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x^2+2\right)=12-5x\)

\(\Leftrightarrow x^3+27-x^3-2x+5x=12\)

\(\Leftrightarrow x=-5\)

`@` `\text {Ans}`

`\downarrow`

`(3x - 2)^3 = 2*32`

`=> (3x - 2)^3 = 2*2^5`

`=> (3x - 2)^3 = 2^6`

`=> (3x - 2)^3 = 4^3`

`=> 3x - 2 = 4`

`=> 3x = 6`

`=> x = 6 \div 3`

`=> x = 2`

Vậy, `x = 2.`

=>(3x-2)^3=64

=>3x-2=4

=>3x=6

=>x=2

a) \(PT\Leftrightarrow3x-2x=2-3\Leftrightarrow x=-1\)

Vậy: \(S=\left\{-1\right\}\)

b) \(PT\Leftrightarrow-2x+3x=-7+22\Leftrightarrow x=15\)

Vậy: \(S=\left\{15\right\}\)

c) \(PT\Leftrightarrow8x-5x=3+12\Leftrightarrow3x=15\Leftrightarrow x=5\)

Vậy: \(S=\left\{5\right\}\)

d) \(PT\Leftrightarrow x+4x-2x=12+25-1\Leftrightarrow3x=36\Leftrightarrow x=12\)

Vậy: \(S=\left\{12\right\}\)

e) \(PT\Leftrightarrow x+2x+3x-3x=19+5\Leftrightarrow3x=24\Leftrightarrow x=8\)

Vậy: \(S=\left\{8\right\}\)

a)3x-2=2x-3

=>x=-1

b)7-2x=22-3x

=>x=15

c)8x-3=5x+12

=>3x=15

=>x=5

d)x-12+4x=25+2x-1

=>3x=12

=>x=4

e)x+2x+3x-19=3x+5

=>3x=24

=>x=8

a)3x-2=2x-3

=>x=-1

b)7-2x=22-3x

=>x=15

c)8x-3=5x+12

=>3x=15

=>x=5

d)x-12+4x=25+2x-1

=>3x=36

=>x=12

e)x+2x+3x-19=3x+5

=>3x=24

=>x=8

a: =>7x=42

hay x=6

b: =>5x=35

hay x=7

c: =>x-14=16

hay x=30

d: =>36-4x=4

=>4x=32

hay x=8

e: =>x-12=144

hay x=156

f: =>3x-16=14

hay x=10

g: =>x+33=45

hay x=12

h: =>(x+9):2=39

=>x+9=78

hay x=69

a: =>7x=42

hay x=6

b: =>5x=35

hay x=7

c: =>x-14=16

hay x=30

d: =>36-4x=4

=>4x=32