\(a,2017\times\left(8+2\right)=2017\times10=20170\\ b,=\dfrac{3}{7}\times\left(\dfrac{9}{7}-\dfrac{2}{7}\right)=\dfrac{3}{7}\times1=\dfrac{3}{7}\)

a) 2017 x 34 + 2017 x 65 + 2017

= 2017 x ( 34+65+1)

= 2017 x 100

= 201700

b) 3/5 x 7/9 - 3/5 x 2/9

= 3/5 x ( 7/9- 2/9)

= 3/5 x 5/9

= 1/3

a) 2017 x 34 + 2017 x 65 + 2017

= 2017 x (34 + 65 + 1)

= 2017 x 100

= 201700

b) \(\dfrac{3}{5}\) x \(\dfrac{7}{9}\) - \(\dfrac{3}{5}\) x \(\dfrac{2}{9}\)

= \(\dfrac{3}{5}\) x \(\left(\dfrac{7}{9}-\dfrac{2}{9}\right)\)

= \(\dfrac{3}{5}\) x \(\dfrac{5}{9}\)

= \(\dfrac{1}{3}\)

\(a,=2017\times\left(34+65+1\right)=2017\times100=201700\)

\(b,\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{15}{45}=\dfrac{1}{3}\)

x³ + 2x = 0

x(x² + 2) = 0

x = 0 hoặc x² + 2 = 0

*) x² + 2 = 0

x² = -2 (vô lí)

Vậy x = 0

--------------------

8x(x - 2017) - 2x + 4034) = 0

8x(x - 2017) - 2(x - 2017) = 0

(x - 2017)(8x - 2) = 0

x - 2017 = 0 hoặc 8x - 2 = 0

*) x - 2017 = 0

x = 2017

*) 8x - 2 = 0

8x = 2

x = 1/4

Vậy x = 1/4; x = 2017

1)x^3+2x=0

<=>x(x^2+2)=0

<=>x^2=-2(vô lý)

2)8x(x-2017)-2x+4034=0

<=>(x-2017)(8x-2)=0

<=>X=2017,x=1/4

2016.x²⁰¹⁷ + 2018 = 4034

2016.x²⁰¹⁷  = 4034-2018

2016.x²⁰¹⁷  = 2016

x²⁰¹⁷  = 1

=>x =1

8x(x-2017)-2x+4034=0

\(\Leftrightarrow\)8x(x-2017)-2(x-2017)=0

\(\Leftrightarrow\)(x-2017)(8x-2)=0

\(\Leftrightarrow\left\{{}\begin{matrix}x-2017=0\\8x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2017\\x=\frac{1}{4}\end{matrix}\right.\)

Vậy x\(\in\left\{2017;\frac{1}{4}\right\}\)