a, x = 384

b, x = 161

c, x = 8

d, x = 15

X

390-(x-7)=169:13

390-(x-7)=13

X-7=390-13

X-7=377

X=377+7

X=384

phần a bạn ở dưới làm r nhé

phần b chép sai đề 

phần c : 

      x - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0

<=>x - 3 - 24 : 12 - 3 = 0 

<=>x - 3 - 2 - 3 = 0

<=>x=8

Vậy x = 8

phần d :

       x + 5 . 2 - ( 32 + 16 . 3 : 16 - 15 ) = 0

 <=>x + 10 - ( 32 + 3 - 15 ) = 0

<=> x + 10 - 20 = 0

<=>x = 10

Vậy x = 10

a) 390 - ( x - 7 ) = 169 : 13

    390 - ( x - 7 ) =  13

               x - 7   = 390 - 13

               x - 7   = 377

                      x = 377  + 7

                      x = 384

b) ( x - 110 ) : 7 - 3³ - 2³ . 3  ( Sai )

c ) x - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0

                      x - 6 : 2 - 24 : 2 : 6 = 0 + 3

                                x - 3 - 12 : 6 = 3

                                       x - 3 - 2 = 3

                                 x - ( 3 + 2 ) = 3

                                           x - 5 = 3

                                                x = 3 + 5

                                               x = 8

d) x + 5 . 2 - ( 32 +16 . 3 : 16 - 15 ) = 0

x + 10 - ( 32 + 3 - 15 ) = 0

x + 10 - 20                   = 0

x + 10                           = 0 + 20

x + 10                           = 20

x                                   = 20 - 10

x                                   = 10

hình như bài làm r bạn ạ :0 mình giải r đấy xem lại nhé :V

a) \(390-\left(x-7\right)=169:13\)

\(390-\left(x-7\right)=13\)

\(x-7=390-13\)

\(x-7=377\)

\(x=384\)

b) \(\left(x-110\right):7-3^3-2^3.3\)

Đề sai nhé bạn

c) \(x-6:2-\left(48-24\right):2:6-3=0\)

\(x-3-\left(24\right):2:6=3\)

\(x-3-\left(24\right):2=18\)

\(x-3-\left(24\right)=36\)

\(x-3=36+24\)

\(x-3=60\)

\(x=63\)

d) \(x+5.2-\left(32+16.3:16-15\right)=0\)

\(x+10-\left(32+48:16-15\right)=0\)

\(x+10-\left(32+3-15\right)=0\)

\(x+10-20=0\)

\(x+10=20\)

\(x=10\)

Mọi người ơi, giúp em với ạ

a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)

=\(9^4.13:9^3=13.9=117\)

b) 100-(75-25)=100-50=50

\(a,\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)

\(< =>\left(8\cdot6561+729\cdot45\right):\left(81\cdot10-81\right)\)

\(< =>\left(52488+32805\right):\left(810-81\right)\)

\(< =>85293:729\)

\(< =>117\)

\(b,100-\left[75-\left(7-2\right)^2\right]\)

\(< =>100-\left[75-\left(5\right)^2\right]\)

\(< =>100-\left[75-25\right]\)

\(< =>100-50\)

\(< =>50\)

\(c,\left(20\cdot2^4+12\cdot2^4\right)-\left(48\cdot2^2\right):8^2\)

\(< =>\left[2^4\cdot\left(20+12\right)\right]-\cdot\left(48\cdot4\right):8^2\)

\(< =>\left[2^4\cdot32\right]-192:8^2\)

\(< =>\left[16\cdot32\right]-192:64\)

\(< =>512-3\)

\(< =>509\)

\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)

a)390-(x-7)=169:13

<=>390-(x-7)=13

<=>x-7=390-13

<=>x-7=377

<=>x=377+7

<=>x=384

b)x-6:2-(48-24):2:6-3=0

<=>x-3-24:2:6-3=0

<=>x-6-12:6=0

<=>x-6-2=0

<=>x-8=0

<=>x=8

a) 390 - ( x - 7 ) = 169 : 13

390 - ( x - 7 ) = 13

x - 7 = 390 - 13

x - 7 = 377

     x = 377 + 7

     x = 384

b) x - 6 : 2 - ( 48 - 24  ) : 2 : 6 - 3 = 0

x - 3 - ( 48 - 24 ) : 2 : 6 = 0 + 3 = 3

x - 3 - ( 48 - 24 ) : 2 = 3 x 6 = 18

x - 3 - ( 48 - 24 ) = 18 x 2

x - 3 - 24 = 36

x - 3 = 36 + 24

x - 3 = 60

    x = 60 + 3 

    x = 63

Jang Ha Na làm sai mà cũng đc ****

Bài 1: 

1: =-5/24+16/27+3/4

=-5/24+18/24+16/27

=13/24+16/27

=117/216+128/216=245/216

2: =-1/3+1/3+6/7=6/7

3: \(=\dfrac{1}{2}-\dfrac{7}{12}+\dfrac{1}{2}=1-\dfrac{7}{12}=\dfrac{5}{12}\)

4: \(=-\dfrac{5}{8}+\dfrac{14}{25}-\dfrac{6}{10}=\dfrac{-125+112-120}{200}=\dfrac{-133}{200}\)

thu gọn 7^3*7^5

Oh no nhiều kí tự đặc biệt quá

dễ quá mình ko làm  đc