Tìm x
A,102÷(2012-(x-12)=6
Câu1
( x-7/4)+( x-6/3)+( x-5/2)+( x+81/7)=0
Câu2
( 1/1×101)+( 1/2×102)+( 1/3×103)+(1/10×11×X=(1/1×11)+(1/2×12)+...+(1/100×110)
Câu3
( x-1/2013)+( x-2/2012)+( x-3/2011)+...+( x-2012/2) =2012
(1-2+3-4+5-6+7-8+...+101-102+103) * x-120=2012
(1-2+3-4+5-6+7-8+...+101-102+103) * x-120=2012
[ -1 + ( -1 ) ... ( -1 ) + 103] * x -120 = 2012
( -1 x 51 + 103 ) * x - 120 = 2012
( -51 +103) * x = 2012 + 120
52 * x =2132
x= 2132 : 52
x= 41
Tìm X:
a, |5/3 -x| -|-5/6|=|-5/9|
b,|x+1/102|+|x+2/102|+...+|x+100/102| = 102x
a) |5/3 - x| - |-5/6| = |-5/9|
=> |5/3 - x| - 5/6 = 5/9
=> |5/3 - x| = 5/9 + 5/6
=> |5/3 - x| = 25/18
=> \(\orbr{\begin{cases}\frac{5}{3}-x=\frac{25}{18}\\\frac{5}{3}-x=-\frac{25}{18}\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{5}{18}\\x=\frac{55}{18}\end{cases}}\)
a, \(\left|\frac{5}{3}-x\right|-\left|-\frac{5}{6}\right|=\left|-\frac{5}{9}\right|\)
\(\Leftrightarrow\left|\frac{5}{3}-x\right|-\frac{5}{6}=\frac{5}{9}\Rightarrow\left|\frac{5}{3}-x\right|=\frac{5}{9}+\frac{5}{6}=\frac{25}{18}\)
\(\Rightarrow\orbr{\begin{cases}\frac{5}{3}-x=\frac{25}{18}\\\frac{5}{3}-x=-\frac{25}{18}\end{cases}\Rightarrow}x.\)
b, \(\left|x+\frac{1}{102}\right|+\left|x+\frac{2}{102}\right|+...+\left|x+\frac{100}{102}\right|\ge0\)
\(\Rightarrow102x\ge0\Leftrightarrow x\ge0\)=> Ta có thể phá dấu GTTĐ
\(\Rightarrow x+\frac{1}{102}+x+\frac{2}{102}+...+x+\frac{100}{102}=102x\)
\(\Rightarrow100x+\frac{1+2+3+...+100}{102}=102x\Rightarrow2x\Rightarrow x.\)
Câu1: Cho A=(a^2012 +b^2012+c^2012)-(a^2008+b^2008+c^2008) (a b c thuộc Z+) chứng minh rằng A chia hết cho 30.
câu 2: Tìm dư trong phép chia:
a, 5^70+7^50 cho 12
b,3^8+3^6+3^2004 cho 91
câu 3: Cho x y thuộc Z
x^3y-xy^3 chia hết cho 6
Tìm số tự nhiên x biết:
a, 71.2 – 6.(2x+5) = 10 5 : 10 3
b, 5 x + 3 4 . 6 8 = 6 9 . 3 4
c, 12:{390:[5. 10 2 – ( 5 3 + x . 7 2 )]} = 4
d, 5 3 .(3x+2):13 = 10 3 : 13 5 : 13 4
a, 71.2 – 6.(2x+5) = 10 5 : 10 3
71.2 – 6.(2x+5) = 10 2
6.(2x+5) = 71.2 – 100
6.(2x+5) = 42
x = 1
b, 5 x + 3 4 . 6 8 = 6 9 . 3 4
5 x + 3 4 . 6 8 = 6 8 . 6 . 3 4
5 x + 3 4 = 6 8 . 6 . 3 4 : 6 8 = 6 . 3 4
5x = 6 . 3 4 - 3 4 = 5 . 3 4
x = 3 4
c, 12:{390:[5. 10 2 – ( 5 3 + x . 7 2 )]} = 4
390:[5. 10 2 – ( 5 3 + x . 7 2 )] = 12:4 = 3
5. 10 2 – ( 5 3 + x . 7 2 ) = 390:3 = 130
5 3 + x . 7 2 = 5. 10 2 – 130 = 370
x . 7 2 = 370 – 5 3 = 245
x = 245: 7 2 = 5
d, 5 3 .(3x+2):13 = 10 3 : 13 5 : 13 4
5 3 .(3x+2):13 = 10 3 : 13
3x+2 = 10 3 : 13 : 5 3 .13 = 8
x = 2
Tìm x :
e) -12. ( x - 5 ) + 7 . ( 3 - x )=5
g) 30. ( x +2) + 6. ( x - 5 ) - 24x= 102
h) ( x + 1 ) + (x + 2 ) + ... + ( x + 99) =0
- 12 . ( x - 5 ) + 7 . ( 3 - x ) = 5
=> - 12x - 12 . 5 + 7 . 3 - 7x = 5
=> - 12x - 60 + 21 - 7x = 5
=> ( - 12 - 7 )x + ( 60 + 21 ) = 5
=> - 19x + 81 = 5
=> - 19x = - 76
=> x = 4
30 . ( x + 2 ) - 6 . ( x + 5 ) - 24x = 100
=> 30x + 30 . 2 - 6x + 6 . 5 - 24x = 100
=> 30x + 60 - 6x + 30 - 24x = 100
=> 0 . x = 100
=> Không có giá trị x
( x + 1 ) + ( x + 2 ) + . . . + ( x + 99 ) = 0
=> x . 99 + ( 1 + 2 + . . . + 99 ) = 0
=> x . 99 + 4950 = 0
=> x . 99 = - 4950
=> x = - 50
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+99\right)=0\)
\(x+1+x+2+...+x+99=0\)
\(99x+\left(1+2+3+...+98+99\right)=0\)
\(99x+\frac{\left(99+1\right).99}{2}=0\)
\(99x+4950=0\)
\(99x=-4950\)
\(x=-4950:99=-50\)
tính
a)A=0-2+4-6+...+2010-2012
b)B=1+2+3-4-5-6+7+8+9-10-11-12+.....+97+98+99-100-101-102
làm chi tiết hộ mình
a,A=0-2+4-6+...+2010-2012
A=-2+-2+...+-2+-2 (503 cặp)
A=-2.503
A=-1006
Bài 1: Tìm x, biết:
1) 24 ⋮ x; 36 ⋮x ; 150 ⋮ x và x lớnnhất. 3) x ∈ ƯC(54 ; 12) và x > -10 | 2) x∈ BC(6; 4) và 16 ≤ x ≤50. 4) x ⋮ 4; x ⋮ 5; x ⋮ 8 và -20 < x < 180 |
1: \(\Leftrightarrow x=UCLN\left(24;36;150\right)=6\)
2: \(\Leftrightarrow x\in\left\{24;48;72;...\right\}\)
mà 16<=x<=50
nên \(x\in\left\{24;48\right\}\)
3: \(\Leftrightarrow x\inƯ\left(6\right)\)
mà x>-10
nên \(x\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
4: \(\Leftrightarrow x\in BC\left(4;5;8\right)\)
\(\Leftrightarrow x\in\left\{...;-40;0;40;80;120;160;200;...\right\}\)
mà -20<x<180
nên \(x\in\left\{0;40;80;120;160\right\}\)
Giải phương trình sau
a) (x-2012)/1 + (x-2011)/2 + (x-2010)/3 +...+ (x-1)/2012 + x/2013
b) 1/(x^2+3x+2) + 1/(x^2+5x+6) + 1/(x^2+7x+12) + 1/(x^2+9x+20) = 1/8