1, \(\frac{5}{21}+0,5-\frac{19}{23}+\frac{16}{21}-\frac{4}{23}\)

\(=\frac{5+16}{21}-\frac{19+4}{23}+0,5\)

\(=1-1+0,5\)

\(=0,5\)

2,\(\frac{27}{23}+\frac{5}{21}-\frac{4}{23}+\frac{6}{21}+\frac{1}{2}\)

\(=\frac{27-4}{23}+\frac{5+6}{21}+\frac{1}{2}\)

\(=1+\frac{11}{21}+\frac{1}{2}\)

\(=\frac{42+22+21}{42}\)

\(=\frac{85}{42}\)

( 27/23 - 4/23 ) + ( 5/21 + 6/21 ) + 1/2 = 1 + 11/21 +1/2 = 85/42

hình như bạn ghi có chút nhầm lẫn !

27/23 + 5/21 - 4/23 + 6/21 + 1/2

=> A = ( 27/23 - 4/23 ) + ( 5/21 + 6/21 ) + 1/2

=> A = 1 + 1 + 1/2

<=> A = 5/2

~ ủng hộ mk nha ~

\(\dfrac{27}{23}+\dfrac{5}{21}-\dfrac{4}{23}+\dfrac{6}{21}-\dfrac{1}{2}\)

\(=\left(\dfrac{27}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{6}{21}\right)-\dfrac{1}{2}\)

\(=1+\dfrac{11}{21}-\dfrac{1}{2}\)

\(=\dfrac{32}{21}-\dfrac{1}{2}\)

\(=\dfrac{43}{42}\)

(-3/4+2/3):5/11+(-1/4+1/3):5/11

a)|x-13|-35-45=-47

b)(4+x).(x+3)=0

c)25-(5-x)=120-(28-5)

\(\left(\frac{27}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+\frac{1}{2}\)

\(=1+1+\frac{1}{2}\)

\(=\frac{5}{2}\)

k cho mk nha!

Bài 1:

a, Ta có: \(\dfrac{27}{23}+\dfrac{5}{21}-\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}\)

= \(\left(\dfrac{27}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{1}{2}\)

=\(\dfrac{23}{23}+\dfrac{21}{21}+\dfrac{1}{2}\) = \(1+1+\dfrac{1}{2}\)

= \(2\dfrac{1}{2}\)

b: \(=\dfrac{3}{2}-\dfrac{5}{6}:\dfrac{1}{4}+2=\dfrac{7}{2}-\dfrac{5}{6}\cdot4=\dfrac{7}{2}-\dfrac{10}{3}\)

\(=\dfrac{21-20}{6}=\dfrac{1}{6}\)

a: \(=\left(\dfrac{27}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{1}{2}=2+\dfrac{1}{2}=\dfrac{5}{2}\)

3)

\(\dfrac{29-x}{21}+\dfrac{27-x}{23}+\dfrac{25-x}{25}+\dfrac{23-x}{27}+\dfrac{21-x}{29}=0\)

có vấn đề thì phải

= 5 mới đúng chứ-.-

p/s: câu c = -5 chứ-.-

3)

\(\dfrac{29-x}{21}+\dfrac{27-x}{23}+\dfrac{25-x}{25}+\dfrac{23-x}{27}+\dfrac{21-x}{29}=-5\)

\(\Leftrightarrow\dfrac{29-x}{21}+1+\dfrac{27-x}{23}+1+\dfrac{25-x}{25}+1+\dfrac{23-x}{27}+1+\dfrac{21-x}{29}+1=-5+5\)

\(\Leftrightarrow\dfrac{50-x}{21}+\dfrac{50-x}{23}+\dfrac{50-x}{25}+\dfrac{50-x}{27}+\dfrac{50-x}{29}=0\)

\(\Leftrightarrow\left(50-x\right)\left(\dfrac{1}{21}+\dfrac{1}{23}+\dfrac{1}{25}+\dfrac{1}{27}+\dfrac{1}{29}\right)=0\)

\(\Leftrightarrow50-x=0\) Vì \(\dfrac{1}{21}+\dfrac{1}{23}+\dfrac{1}{25}+\dfrac{1}{27}+\dfrac{1}{29}\ne0\)

\(\Leftrightarrow x=50\)

\(\frac{27}{23}+\frac{5}{21}-\frac{4}{23}+\frac{6}{21}+\frac{1}{2}\)

= \(\left(\frac{27}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{6}{21}\right)+\frac{1}{2}\)

= 1 + \(\frac{11}{21}+\frac{1}{2}\)

= \(\frac{42}{42}+\frac{22}{42}+\frac{21}{42}\)

= \(\frac{85}{42}\)

\(=\dfrac{5}{21}+\dfrac{16}{21}-\left(\dfrac{19}{23}+\dfrac{4}{23}\right)+\dfrac{1}{2}=\dfrac{1}{2}\)