\(\frac{2016+2017x2018}{2017x2019-1}\) rút gọn phân số
\(\frac{2016+2017x2018}{2017x2019-1}\)
\(\frac{2016+2017.2018}{2017.2019-1}\)
\(=\frac{\left(2016+1\right)+2017.2018-1}{2017.2019-1}\)
\(=\frac{2017+2017.2018-1}{2017.2019-1}\)
\(=\frac{2017.\left(1+2018\right)-1}{2017.2019-1}\)
\(=\frac{2017.2019-1}{2017.2019-1}=1\)
\(\frac{2016+2017\times2018}{2017\times2019-1}\)
\(=\frac{2016+2017\times2018}{2017\times\left(2018+1\right)-1}\)
\(=\frac{2016+2017\times2018}{2017\times2018+2017-1}\)
\(=\frac{2016+2017\times2018}{2017\times2018+2016}\)
\(=1\)
__CHÚC BN HOK TỐT__
Tính nhanh:
a)\(\frac{2018x2019-2017}{2017x2018+2019}\) b)\(\frac{2018x2018}{2017x2019+1}\)
các bạn hãy trả lời nhanh cho mình với nhé
a) 2018 x 2019 - 2017 = 2017 = 1 b) 2018 x 2018 = 2018 x 2018 = 2018
2017 x 2018 + 2019 2017 (2017 + 1) x 2019 2018 x 2019 2019
chúc bạn hok tốt
bạn sky ơi! Bài a) bạn có thể giải thích rõ cho mình vì sao bằng 1 dc ko?
so sánh 2 phân số
A = \(\frac{2017x2018-1}{2017x2018-2}\)và B = \(\frac{2017}{2018}\)
Ta có:
\(A=\frac{2017\cdot2018-1}{2017\cdot2018-2}\)
\(A=\frac{2017\cdot2018-2+1}{2017\cdot2018-2}\)
\(A=\frac{2017\cdot2018-2}{2017\cdot2018-2}+\frac{1}{2017\cdot2018-2}\)
\(A=1+\frac{1}{2017\cdot2018-2}\)
Ta có phân số trung gian là 1. Ta có:
\(A>1\) ; \(B< 1\)
\(\Rightarrow A>1>B\)
\(\Rightarrow A>B\)
Vậy A>B
Chúc em học tốt!
\(\Rightarrow\text{❤️✔✨♕✨✔️❤ }\Leftarrow\)
\(\text{Ta có :}\)
\(A=\frac{2017\cdot2018-1}{2017\cdot2018-2}=\frac{4070305}{4070304}=1\frac{1}{4070304}\)
\(B=\frac{2017}{2018}\)
\(\text{Vì : }1\frac{1}{4070304}>1\text{ mà }\frac{2017}{2018}< 1\text{ nên }1\frac{1}{4070304}>\frac{2017}{2018}\)
\(\Rightarrow A>B\)
Rút gọn phân số:
\(\frac{-2017.2016+1}{-2015.\left(-2017\right)+2016}\)
so sánh phân số 2018x2018/2017x2019 và 1
A.2018x2018/2017x2019 = 1
B.2018X2018/2017X2019 > 1
C.2018x2018/2017x2019 <1
D.Không so sánh được
Ta có :
2018 x 2018 = ( 2017 + 1 ) x ( 2019 - 1 )
= ( 2017 + 1 ) x 2019 - ( 2017 + 1 )
= 2017 x 2019 + 2019 - 2017 - 1
= 2017 x 2019 + 1 > 2017 x 2019
\(\Rightarrow\frac{2018\times2018}{2017\times2019}=\frac{2017\times2019+1}{2017\times2019}=1+\frac{1}{2017\times2019}>1\)
Vậy ta chọn B
~~Học tốt~~
các bn chọ hộ mình, đúng mình k cho
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+................+\frac{1}{2006}}{\frac{2016}{1}+\frac{2016}{2}+...........+\frac{2}{2015}+\frac{1}{2016}}\)
rút gọn nha mọi người
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+................+\frac{1}{2006}}{\frac{2016}{1}+\frac{2016}{2}+...........+\frac{2}{2015}+\frac{1}{2016}}\)
rút gọn nha mọi người
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2016}}{\frac{2016}{1}+\frac{2015}{2}+....+\frac{2}{2015}+\frac{1}{2016}}\)
rút gọn nha mọi người
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2016}}{\left(\dfrac{2015}{2}+1\right)+...+\left(\dfrac{2}{2015}+1\right)+\left(\dfrac{1}{2016}+1\right)+1}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2016}}{\dfrac{2017}{2}+\dfrac{2017}{3}+...+\dfrac{2017}{2015}+\dfrac{2017}{2016}}=\dfrac{1}{2017}\)
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+................+\frac{1}{2006}}{\frac{2016}{1}+\frac{2016}{2}+...........+\frac{2}{2015}+\frac{1}{2016}}\)
rút gọn nha mọi người