76502 - x = 10512 : 32

76502 - x =    328,5

            x = 76502 - 328,5

            x =  76173,5

x + 532 = 48 x 23

x + 532 =    1104

x          = 1104 - 532

x          =  572

x - 264 = 1456 : 56

x - 264 =    26

x         = 26 + 264

x         =    290

nhớ tk mik đó

Bài a:

76502 - y = 10528 : 32

76502 - y = 329

y = 76502 - 329

y = 76173

Bài b:

y + 532 = 48 x 32

y + 532 = 1536

y = 1536 - 532

y = 1004

Bài c: 

(y - 264) x 52 = 1456

y - 264 = 1456 : 52

y - 264 = 28

y = 28 + 264

y = 292

Lưu ý: Tớ không chắc là đúng hết nha! Xin hãy cẩn thận. Nếu đúng, chọn đúng và kết bạn với mình nha!

a) 76502-y=10528:32

76502-y=329

y=76502-329

y=76173

b) y+532=48×32

y+532=1536

y=1536-532

y=100

c)(y -264)×52=1456

 y-264=1456:52

y-264=28

y=28+264

y=292

ủng hộ nhé mọi người

a) \(76502-y=10528:32\)

     \(76502-y=329\)

       \(y=76502-329\)

        \(y=76173\)

b) \(y+532=48\cdot32\)

     \(y+532=1536\)

     \(y=1536-532\)

     \(y=1004\)

c) \(\left(y-264\right)\cdot52=1456\)

     \(y-264=1456:52\)

     \(y-264=28\)

     \(y=28+264\)

     \(y=292\)

Dấu chấm có nghĩa là dấu nhân nha bạn

Chúc bạn học tốt !!!

76502-x=328,5

            x=76502-328,5

            x=76173,5 nhé bn k cho mk nha nha nha

76502 - x = 10512 :32

76502 - x = 328,5

            x = 76173,5

76502-x=328,5

x=76502-328,5

x=76173,5

x=76173,5

\(76502-x=328,5\)

\(\Leftrightarrow x=76502-328,5=76173,5\)

76502-x=10512 : 32

76502-x= 328,5

          x=76502-328,5

         x=76173,5

\(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\left(5^{128}-1\right)=2.5^{128}-2\)

c: Ta có: \(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^2-1\right)\left(5^2+1\right)\cdot\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{16}-1\right)\cdot\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{32}-1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{64}-1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{128}-1\right)\)

\(=2\cdot5^{128}-2\)

d: Ta có: \(E=\left(x-2\right)^3-\left(x+1\right)\left(x^2-x+1\right)+6\left(x-1\right)^2\)

\(=x^3-6x^2+12x-8-x^3-1+6x^2-12x+6\)

\(=-3\)

30,31

36+1

20

88

Bài 23: Tìm x:

a) 29 < 30 < 32

b) 36 < 37 + 1 < 39

c) 30 + 30 < 64

d) 46 < 88 - 42 < 48

a, 30

b,37

c, 30

d, 88

a. <=> 42 : x = 3

<=> x = 14

b. 25 * x = 15675

<=> x = 627

c. x = 19

a) \(\left(x-2891\right):3=40688\)

= \(\left(x-2891\right)=40688.3=122064\)

= \(\left(x-2891\right)=122064+2891=124955\)

b)  \(\left(x+2891\right):3=10512\)

= \(\left(x+2891\right)=10512.3=31536\)

= \(\left(x+2891\right)=31536-2891=28645\)

a, ( x - 2891 ) : 3 = 40688

( x - 2891 ) = 40688 x 3

x - 2891 = 122064

=> x = 122064 + 2891

=>x = 124955

b, ( x + 2891 ) : 3 = 10512

( x + 2891 ) = 10512 x 3

x + 2891 = 31536

=> x = 31536 - 2891

=> x = 28645

Muộn quá rồi mấy chế ơi !