Bài 1 câu g bạn kia làm sai mình sửa lại nhá

\(3a^2-6ab+3b^2-12c^2\)

\(=3\left(a^2-2ab+b^2\right)-12c^2\)

\(=3\left(a-b\right)^2-12c^2\)

\(=3\left[\left(a-b\right)^2-4c^2\right]\)

\(=3\left(a-b-2c\right)\left(a-b+2c\right)\)

Để mình làm tiếp cho :))

Bài 2 :

Câu a : \(37,5.8,5-7,5.3,4-6,6.7,5+1,5.37,5\)

\(=\left(37,5.8,5+1,5.37,5\right)-\left(7,5.3,4+6,6.7,5\right)\)

\(=37,5\left(8,5+1,5\right)-7,5\left(3,4+6,6\right)\)

\(=37,5.10-7,5.10\)

\(=10.30=300\)

Câu b : \(35^2+40^2-25^2+80.35\)

\(=\left(35^2+80.35+40^2\right)-25^2\)

\(=\left(30+45\right)^2-25^2\)

\(=75^2-25^2\)

\(=\left(75+25\right)\left(75-25\right)\)

\(=100.50=5000\)

Bài 3 :

Câu a : \(x^3-\dfrac{1}{9}x=0\)

\(\Leftrightarrow x\left(x^2-\dfrac{1}{9}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x^2-\dfrac{1}{9}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\pm\dfrac{1}{3}\end{matrix}\right.\)

Câu b : \(2x-2y-x^2+2xy-y^2=0\)

\(\Leftrightarrow2\left(x-y\right)-\left(x-y\right)^2=0\)

\(\Leftrightarrow\left(x-y\right)\left(2-x+y\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-y=0\\2-x+y=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=y\\x+y=2\Rightarrow x=2-y\end{matrix}\right.\)

Câu c :

\(x\left(x-3\right)+x-3=0\)

\(\Leftrightarrow\left(x-3\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

\(x^2\left(x-3\right)+27-9x=0\)

\(\Leftrightarrow x^2\left(x-3\right)-9\left(x-3\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x^2-9\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x^2-9=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=\pm3\end{matrix}\right.\)

Bài 4 :

Câu a :

\(x^2-4x+3\)

\(=x^2-x-3x+3\)

\(=\left(x^2-x\right)-\left(3x-3\right)\)

\(=x\left(x-1\right)-3\left(x-1\right)\)

\(=\left(x-1\right)\left(x-3\right)\)

Câu b :

\(x^2+x-6\)

\(=x^2-2x+3x-6\)

\(=x\left(x-2\right)+3\left(x-2\right)\)

\(=\left(x-2\right)\left(x+3\right)\)

Câu c :

\(x^2-5x+6\)

\(=x^2-2x-3x+6\)

\(=\left(x^2-2x\right)-\left(3x-6\right)\)

\(=x\left(x-2\right)-3\left(x-2\right)\)

\(=\left(x-2\right)\left(x-3\right)\)

Câu d :

\(x^4+4\)

\(=x^4+4x^2+4-4x^2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2\)

\(=\left(x^2+2-2x\right)\left(x^2+2+2x\right)\)

Bài 1:

a) \(2x^2-2xy-5x+5y\)

\(=\left(2x^2-2xy\right)-\left(5x-5y\right)\)

\(=2x\left(x-y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(2x-5\right)\)

b) \(8x^2+4xy-2ax-ay\)

\(=\left(8x^2+4xy\right)-\left(2ax+ay\right)\)

\(=4x\left(2x+y\right)-a\left(2x+y\right)\)

\(=\left(2x+y\right)\left(4x-a\right)\)

c) \(x^3-4x^2+4x\)

\(=x\left(x^2-4x+4\right)\)

\(=x\left(x-2\right)^2\)

d) \(2xy-x^2-y^2+16\)

\(=-\left[\left(x^2-2xy+y^2\right)-16\right]\)

\(=-\left[\left(x-y\right)^2-4^2\right]\)

\(=-\left[\left(x-y-4\right)\left(x-y+4\right)\right]\)

e) \(x^2-y^2-2yz-z^2\)

\(=-\left[\left(z^2+2yz+y^2\right)-x^2\right]\)

\(=-\left[\left(z+y\right)^2-x^2\right]\)

\(=-\left[\left(z+y+x\right)\left(z+y-x\right)\right]\)

g) \(3a^2-6ab+3b^2-12c^2\)

\(=\left(3a^2-6ab+3b^2\right)-12c^2\)

\(=\left(\sqrt{3a}+\sqrt{3b}\right)^2-12c^2\)

\(=\left(\sqrt{3a}+\sqrt{3b}+\sqrt{12c}\right)\left(\sqrt{3a}+\sqrt{3b}-\sqrt{12c}\right)\)

a) 

=x³+x²+x²+x+x+1

=x²(x+1)+x(x+1)+(x+1)

=(x+1)(x²+x+1)

b) 

=x³-3x²-x²+3x+9x-27

=x²(x-3)-x(x-3)+9(x-3)

=(x-3)(x²-x+9)

a) 

=x³+x²+x²+x+x+1

=x²(x+1)+x(x+1)+(x+1)

=(x+1)(x²+x+1)

b) 

=x³-3x²-x²+3x+9x-27

=x²(x-3)-x(x-3)+9(x-3)

=(x-3)(x²-x+9)

d)x^4+2x^3+2x^2+2x+1(no)

e)x^5+x^4+x^3+x^2+x+1 ( no)

a) x²-x-y²-y=(x²-y²)-(x+y)=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)

b)x²-2xy+y²-z²=(x-y)²-z²=(x-y-z)(x-y+z)

c)5x-5y+ax-ay=5(x-y)+a(x-y)=(x-y)(5+a)

d)a³-a²x-ay+xy=a²(a-x)-y(a-x)=(a-x)(a²-y)

e)4x²-y²+4x+1=[(2x)²+2.2x.1+1²]-y²=(2x+1)²-y²=(2x+1-y)(2x+1+y)

Chúc bạn học tốt!

a) \(x^2+4x-y^2+4\)

\(=\left(x+2\right)^2-y^2\)

\(=\left(x+2-y\right)\left(x+2+y\right)\)

b) \(3x^2+6xy+3y^2-3z^2\)

\(=3\left(x^2+2xy+y^2-z^2\right)\)

\(=3\left[\left(x+y\right)^2-z^2\right]\)

\(=3\left(x+y-z\right)\left(x+y+z\right)\)

c) \(x^2-2xy+y^2-z^2+2zt-t^2\)

\(=\left(x-y\right)^2-\left(z-t\right)^2\)

\(=\left(x-y-z+t\right)\left(x-y+z-t\right)\)

a,\(-4x^2+4x-1\)

\(\Leftrightarrow\left(-2x-1\right)^2\)

b,\(\left(2x+1\right)^2-4\left(x-1\right)^2\)

\(\Rightarrow\left[2x+1-2\left(x-1\right)\right].\left[2x+1+2\left(x-1\right)\right]\)

\(\Rightarrow\left(2x+1-2x+2\right)\left(2x+1+2x-2\right)\)

\(\Rightarrow3\left(4x-1\right)\)

c,\(\left(2x-y\right)^2-4x^2+12x-9\)

\(\Leftrightarrow\left(2x+y\right)^2-\left(4x^2-12x+9\right)\)

\(\Leftrightarrow\left(2x+y\right)^2-\left(2x-3\right)^2\)

\(\Leftrightarrow\left(2x+y-2x+3\right)\left(2x+y+2x-3\right)\)

\(\Rightarrow\left(y+3\right)\left(4x+y-3\right)\)

d,\(\left(x+1\right)^2-4\left(x+1\right)y^2+4y^4\)

\(\Leftrightarrow\left(x+1\right)^2-2\left(x+1\right)2y^2+2^2y^4\)

\(\Leftrightarrow\left(x+1\right)^2-2\left(x+1\right)2y^2+4\left(y^2\right)^2\)

\(\Leftrightarrow\left(x+1\right)^2-2\left(x+1\right)-2y^2+\left(2y^2\right)^2\)

\(\Leftrightarrow\left(x+1-2y^2\right)^2\)

Câu a :

\(\left(x-5\right)^2+\left(x-5\right)\left(x+5\right)-\left(5-x\right)\left(2x+1\right)\)

\(=x^2-10x+25+x^2-25-10x-5+2x^2+x\)

\(=4x^2-19x-5\)

Câu b :

\(\left(3x-2\right)\left(4x-3\right)-\left(2-3x\right)\left(x-1\right)-2\left(3x-2\right)\left(x+1\right)\)

\(=12x^2-9x-8x+6-2x+2+3x^2-3x-6x^2-6x+4x+4\)

\(=9x^2-24x+2\)