Đơn giản biểu thức:
\(a>\left(a+h\right)-\left(-c+a+b\right)\)
\(b>-\left(x+y\right)+\left(-z+x+y\right)\)
1) Cho a^3+b^3+c^3=3abc và abc khác 0. Tính giá trị của P=\(\left(1+\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right)\)
2) Tính giá trị biểu thức A= \(\frac{a^3+b^3+c^3-3abc}{\left(a-b\right)^2+\left(b-c\right)^2+\left(c-a\right)^2}\)
với a khác b, hoặc b khác c, hoặc c khác a
3) Tính giá trị biểu thức B= \(\frac{\left(x^2-y^2\right)^3+\left(y^2-z^2\right)^3+\left(z^2-x^2\right)^3}{\left(x-y\right)^3+\left(y-z\right)^3+\left(z-x\right)^3}\)
với x khác y, hoặc y khác z, hoặc z khác x
4) Tính giá trị biểu thức C= \(\frac{\left(x-y\right)^3+\left(y-z\right)^3+\left(z-x\right)^3}{3\left(x-y\right)\left(y-z\right)\left(z-x\right)}\)
với x khác y; y khác z; z khác x
a) CMR biểu thức ko âm với mọi x,y,z.
M=4x(x+y)(x+y+z)(x+z)+y2z2
b) Tính giá trị của biểu thức
E=\(\frac{\left(a-x\right)^2}{a\left(b-a\right)\left(c-a\right)}\) + \(\frac{\left(b-x\right)^2}{b\left(a-b\right)\left(c-b\right)}\) +\(\frac{\left(c-x\right)^2}{c\left(a-c\right)\left(b-c\right)}\) biết 1-\(\frac{x^2}{abc}\) =0
Rút gọn các biểu thức sau :
a) \(\left(a+b\right)^2-\left(a-b\right)^2\)
b) \(\left(a+b\right)^3-\left(a-b\right)^3-2b^3\)
c) \(\left(x+y+z\right)^2-2\left(x+y+z\right)\left(x+y\right)+\left(x+y\right)^2\)
Bài giải:
a) (a + b)2 – (a – b)2 = (a2 + 2ab + b2) – (a2 – 2ab + b2)
= a2 + 2ab + b2 – a2 + 2ab - b2 = 4ab
Hoặc (a + b)2 – (a – b)2 = [(a + b) + (a – b)][(a + b) – (a – b)]
= (a + b + a – b)(a + b – a + b)
= 2a . 2b = 4ab
b) (a + b)3 – (a – b)3 – 2b3
= (a3 + 3a2b + 3ab2 + b3) – (a3 – 3a2b + 3ab2 – b3) – 2b3
= a3 + 3a2b + 3ab2 + b3 – a3 + 3a2b - 3ab2 + b3 – 2b3
= 6a2b
Hoặc (a + b)3 – (a – b)3 – 2b3 = [(a + b)3 – (a – b)3] – 2b3
= [(a + b) – (a – b)][(a + b)2 + (a + b)(a – b) + (a – b)2] – 2b3
= (a + b – a + b)(a2 + 2ab + b2 + a2 – b2 + a2 – 2ab + b2) – 2b3
= 2b . (3a2 + b2) – 2b3 = 6a2b + 2b3 – 2b3 = 6a2b
c) (x + y + z)2 – 2(x + y + z)(x + y) + (x + y)2
= x2 + y2 + z2+ 2xy + 2yz + 2xz – 2(x2 + xy + yx + y2 + zx + zy) + x2 + 2xy + y2
= 2x2 + 2y2 + z2 + 4xy + 2yz + 2xz – 2x2 – 4xy – 2y2 – 2xz – 2yz = z2
1/Cho a,b,c thỏa mãn \(\frac{2}{\left(x^2+1\right)\left(x-1\right)}=\frac{ax+b}{x^2+1}+\frac{c}{x-1}\)
Tính giá trị biểu thức M=\(\frac{a^{2017}+b^{2018}+c^{2019}}{a^{2017}b^{2018}c^{2019}}\)
2/Cho x,y,z≠0 và x+y+z=2008
Tính giá trị biểu thức P=\(\frac{x^3}{\left(x-y\right)\left(x-z\right)}+\frac{y^3}{\left(y-x\right)\left(y-z\right)}+\frac{z^3}{\left(z-y\right)\left(z-x\right)}\)
Phân tích đa thức thành nhân tử
\(2x\left(y-1\right)-z\left(1-y\right)\)
\(a\left(x-y\right)-b\left(x+y\right)+x-y\)
\(a\left(x-y\right)-b\left(y-x\right)+c\left(x-y\right)\)
\(a^m-a^{m+2}\)
a: \(a\left(x-y\right)-b\left(y-x\right)+c\left(x-y\right)\)
\(=a\left(x-y\right)+b\left(x-y\right)+c\left(x-y\right)\)
\(=\left(x-y\right)\left(a+b+c\right)\)
b: \(a^m-a^{m+2}\)
\(=a^m-a^m\cdot a^2\)
\(=a^m\left(1-a^2\right)\)
\(=a^m\left(1-a\right)\left(1+a\right)\)
a ,Tính \(A=\dfrac{1}{\left(x-y\right)\left(y-z\right)}+\dfrac{1}{\left(y-z\right)\left(z-x\right)}+\dfrac{1}{\left(z-x\right)\left(x-y\right)}\)
b, Cho a,b,c \(\ne\) 0 thỏa mãn a+b+c=0
CMR: \(M=\dfrac{1}{ab}+\dfrac{1}{bc}+\dfrac{1}{ca}=0\)
c, Cho biểu thức :
\(B=\dfrac{y}{\left(x-y\right)\left(y-z\right)}+\dfrac{z}{\left(y-z\right)\left(z-x\right)}+\dfrac{x}{\left(z-x\right)\left(x-y\right)}\)
CMR : Giá trị bth B không phụ thuộc vào giá trị của biến
b: \(M=\dfrac{1}{ab}+\dfrac{1}{bc}+\dfrac{1}{ac}=\dfrac{a+b+c}{abc}=0\)
c: \(B=\dfrac{y}{\left(x-y\right)\left(y-z\right)}-\dfrac{z}{\left(x-z\right)\left(y-z\right)}-\dfrac{x}{\left(x-z\right)\left(x-y\right)}\)
\(=\dfrac{y\left(x-z\right)-z\left(x-y\right)-x\left(y-z\right)}{\left(x-y\right)\left(y-z\right)\left(x-z\right)}\)
\(=\dfrac{xy-yz-xz+zy-xy+xz}{\left(x-y\right)\left(y-z\right)\left(x-z\right)}=0\)
1/Cho a,b,c thỏa mãn \(\frac{2}{\left(x^2+1\right)\left(x-1\right)}=\frac{ax+b}{x^2+1}+\frac{c}{x-1}\)
Tính giá trị biểu thức M=\(\frac{a^{2017}+b^{2018}+c^{2019}}{a^{2017}b^{2018}c^{2019}}\)
2/Cho x,y,z≠0 và x+y+z=2008
Tính giá trị biểu thức P=\(\frac{x^3}{\left(x-y\right)\left(x-z\right)}+\frac{y^3}{\left(y-x\right)\left(y-z\right)}+\frac{z^3}{\left(z-y\right)\left(z-x\right)}\)
Rút gọn biểu thức :
a) \(\left(x+y\right)^2+\left(x-y\right)^2\)
b) \(2\left(x-y\right)\left(x+y\right)+\left(x+y\right)^2+\left(x-y\right)^2\)
c) \(\left(x-y+z\right)^2+\left(z-y\right)^2+2\left(x-y+z\right)\left(y-z\right)\)
\(a,\left(x+y\right)^2+\left(x-y\right)^2=x^2+2xy+y^2+x^2-2xy+y^2=2\left(x^2+y^2\right)\)\(b,2\left(x-y\right)\left(x+y\right)+\left(x+y\right)^2+\left(x-y\right)^2=2x^2-2y^2+x^2+2xy+y^2+x^2-2xy+y^2=3x^2\)\(c,\left(x-y+z\right)^2+\left(z-y\right)^2+2\left(x-y+z\right)\left(y-z\right)=\left[\left(x-y+z\right)-\left(z-y\right)\right]^2=\left(x-2y\right)^2\)
a) \(\left(x+y\right)^2+\left(x-y\right)^2\)
=\(\left(x^2+2xy+y^2\right)+\left(x^2-2xy+y^2\right)\)
=\(x^2+2xy+y^2+x^2-2xy+y^2\)
\(2x^2+2y^2=2\left(x^2+y^2\right)\)
b) \(2\left(x-y\right)\left(x+y\right)+\left(x+y\right)^2+\left(x-y\right)^2\)
\(=\left(x-y\right)^2+2\left(x-y\right)\left(x+y\right)+\left(x+y\right)^2\)
=\(\left[\left(x-y\right)+\left(x+y\right)\right]^2\)
= \(\left(x-y+x+y\right)^2\)
\(=2x^2\)
c) \(\left(x-y+z\right)^2+\left(z-y\right)^2+2\left(x-y+z\right)\left(y-z\right)\)
\(=\left(x-y+z\right)^2-2\left(x-y+z\right)\left(z-y\right)+\left(z-y\right)^2\)
\(=\left[\left(x-y+z\right)-\left(z-y\right)\right]^2\)
= \(\left(x-y+z-z+y\right)^2=x^2\)
a. (x+y)2+(x−y)2
=x2+2xy+y2+x2−2xy+y2=2x2+2y2
b. 2(x−y)(x+y)+(x+y)2+(x−y)2
=[(x+y)+(x−y)]2=(2x)2=4x2
c. (x−y+z)2+(z−y)2+2(x−y+z)(y−z)
=(x−y+z)2+2(x−y+z)(y−z)+(y−z)2=[(x−y+x)+(y−z)]2=x2
Chứng minh đẳng thức
a) \(\left(x-y\right)-\left(x-z\right)=\left(z+x\right)-\left(y+x\right)\)
b) \(\left(x-y+z\right)-\left(y+z-x\right)-\left(x-y\right)=\left(z-y\right)-\left(z-x\right)\)
c) \(a\left(b+c\right)-b\left(a-c\right)=\left(a+b\right)c\)
d) \(a\left(b-c\right)-a\left(b+d\right)=-a\left(c+d\right)\)
e) \(\left(a+b\right)\left(c+d\right)-\left(a+d\right)\left(b+c\right)=\left(a-c\right)\left(d-b\right)\)
f) \(\left(a-c\right)\left(b+d\right)-\left(a-d\right)\left(b+c\right)=\left(a+b\right)\left(d-c\right)\)
a. VT:(x-y)-(x-z)
= x-y-x+z
= z-y
VP:(z+x)-(y+x)
=z+x-y-x
=z-y
=> VT=VP => đpcm.
b. VT:(x-y+z)-(y+z-x)-(x-y)
= x-y+z-y-z+x-x+y
= x-y
VP:(z-y)-(z-x)
= z-y-z+x
= x-y
=> VT=VP => đpcm.
c. VT: a(b+c)-b(a-c)
=ab+ac-ab+bc
= ac+bc
VP: (a+b)c
= ac+bc
=> VT=VP => đpcm.
d. VT: a(b-c)-a(b+d)
= ab-ac-ab-ad
= -ac-ad
VP: -a(c+d)
= -ac-ad
=> VT=VP => đpcm
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