X × 20 + 16 × X = 972
a, Tìm y: y x 20 + 16 x y = 972 |
\(y.\left(20+16\right)=972\Leftrightarrow36y=972\Leftrightarrow y=27\)
y x (20+ 16) = 972
y x 36 = 972
y = 972 : 36
y = 27
X x 20-11 x X =972
X x 20 - 11 x X = 972
X x ( 20 - 11 ) = 972
X x 9 = 972
X = 972 : 9
X = 108
x.20-11.x=972
=x.(20-11)=972
=x.9=972
=x=972:9
=x=108
Vậy x=108
X x ( 20 - 11 ) = 972
X x 9 = 972
X = 972 : 9
X = 108
a,x-108×42=2378
b,1337+13×x=6745
c,x×10+16×x=972
d,25×x-x=59904:32
Tìm x: (3.x + 11) – 17 = 30
a,x-108×42=2378
b,1337+13×x=6745
c,x×10+16×x=972
d,25×x-x=59904:32
a, x - 108 × 42 = 2378
=> x - 4536 = 2378
=> x = 6914
vậy_
b,1337 + 13 × x = 6745
=> 10 × x = 5408
=> x = 540,8
vậy_
c, x × 10 + 16 × x = 972
=> x × (10 + 16) = 972
=> x× 26 = 972
=> x = \(\frac{486}{13}\)
vậy_
d, 25 × x - x = 59904 : 32
=> x × (25 - 1) = 1872
=> x × 24 = 1872
=> x = 78
vậy_
\(x-108.42=2378\)
\(x-4536=2378\)
\(x=6914\)
tìm x: a. 3^9:3^6+ x =89 b. 7^ x =48 c. 16+2^ x=32 d. 2^x+1=64 e. 3^x+1+3^x=972
mk cần cách giải gấp mấy bạn giúp mk nha
Bài 4 tìm x
a ) X 36 = 972
b ) ( X - 47 ) x 21 = 840
c ) X x 22 + X x 50 = 504
d ) 254 : x = 14 ( dư 16 )
e ) 729 : X = 81
f ) y x 15 + y x 13 = 560 x 45
giúp em với !
Có ngay nè e
a. X x 36 =972
X = 972 : 36
X = 27
b. ( X - 47) x 21 = 840
X - 47 = 840 : 21
X - 47 = 40
X = 40 + 47
X = 87
c. X x 22 + X x 50 = 504
X x ( 22 + 50) = 504
X x 72 = 504'
X = 504 : 72
X = 7
d.254 : x = 14 ( dư 16)
X = ( 254 - 16) : 14
X = 238 : 14
X = 17
e. 729 : X = 81
X = 729 : 81
X = 9
f. y x 15 + y x 13 = 560 x 45
y x 15 + y x 13 = 25 200
y x ( 15 + 13 ) = 25 200
y x 28 = 25 200
y = 25 200 : 28
y = 900
Có sai ở đâu thông cảm cho a nhé, Dài quá e ạ
\(\frac{x-971}{972}+\frac{x-973}{970}+\frac{x-975}{968}+\frac{x-977}{966}=\frac{x-972}{971}+\frac{x-970}{973}+\frac{x-968}{975}+\frac{x-966}{977}\)
\(\frac{x-971}{972}+\frac{x-973}{970}+\frac{x-975}{968}+\frac{x-977}{966}=\frac{x-972}{971}+\frac{x-970}{973}+\frac{x-968}{975}+\frac{x-966}{977}\)
\(\Rightarrow\frac{x-971}{972}-1+\frac{x-973}{970}-1+\frac{x-975}{968}-1+\frac{x-977}{966}-1=\frac{x-972}{971}-1+\frac{x-970}{973}-1+\frac{x-968}{975}-1+\frac{x-966}{977}-1\)\(\Rightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}=\frac{x-1943}{971}+\frac{x-1943}{973}+\frac{x-1943}{975}+\frac{x-966}{977}\)
\(\Leftrightarrow\frac{x-1943}{972}+\frac{x-1943}{970}+\frac{x-1943}{968}+\frac{x-1943}{966}-\frac{x-1943}{971}-\frac{x-1943}{973}-\frac{x-1943}{975}-\frac{x-966}{977}=0\)
\(\Leftrightarrow\left(x-1943\right).\left(\frac{1}{972}+\frac{1}{970}+\frac{1}{968}+\frac{1}{966}-\frac{1}{971}-\frac{1}{973}+\frac{1}{975}+\frac{1}{977}\right)=0\)
\(\Leftrightarrow\left(x-1943\right)=0\Leftrightarrow x=1943\)
Vậy...
Tìm x:
a. x x 6 = 972
b. 7332 : x = 12.
Hướng dẫn giải:
a.
x x 6 = 972
x = 972 : 6
x = 162
b.
7332 : x = 12
x = 7332 : 12
x = 611
95,13 x a + 2,07 x a = 972
`95,13 xx a + 2,07 xx a = 972`
`=>(95,13 + 2,07)xx a = 972`
`=>97,2xx a = 972`
`=>x=972 : 97,2`
`=>x=10`
\(95,13a+2,07a=972\)
\(\Rightarrow\left(95,13+2,07\right)a=972\)
\(\Rightarrow97,2a=972\)
\(\Rightarrow a=972:97,2=10\)
Vậy \(a=10\)
\(95,13\times a+2,07\times a\text{=}972\)
\(\left(95,13+2,07\right)\times a\text{=}972\)
\(97,2\times a\text{=}972\)
\(a\text{=}972:97,2\)
\(a\text{=}10\)