1 - 2 + 3 - 4+ ..... + 2011 - 2012 + 2013 - 2014
1) 1/2 + 1/3 + 1/4 + ... + 1/2013 + 1/2014
2) 2014 + 2013/2 + 2012/3 + 2011/4 + ... + 2/2013 + 1/2014
A = (2013/2 + 2013/3+2013/4 + ....+2013/2014) : (2013/1+2012/2 +2011/3+...+1/2013)
\(A=\frac{\frac{2013}{2}+\frac{2013}{3}+\frac{2013}{4}+...+\frac{2013}{2014}}{\frac{2013}{1}+\frac{2012}{2}+\frac{2011}{3}+...+\frac{1}{2013}}\)
\(A=\frac{2013.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}{\left(1+\frac{2012}{2}\right)+\left(1+\frac{2011}{3}\right)+...+\left(1+\frac{1}{2013}\right)+1}\)
\(A=\frac{2013.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}{\frac{2014}{2}+\frac{2014}{3}+...+\frac{2014}{2013}+\frac{2014}{2014}}\)
\(A=\frac{2013.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}{2014.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2013}+\frac{1}{2014}\right)}\)
\(A=\frac{2013}{2014}\)
\(A=\frac{\frac{2013}{2}+\frac{2013}{3}+\frac{2013}{4}+...+\frac{2013}{2014}}{\frac{2013}{1}+\frac{2012}{2}+\frac{2011}{3}+...+\frac{1}{2013}}\)
\(=\frac{2013.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}{\left(1+\frac{2012}{2}\right)+\left(1+\frac{2011}{3}\right)+...+\left(1+\frac{1}{2013}\right)+1}\)
\(=\frac{2013.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}{\frac{2014}{2}+\frac{2014}{3}+...+\frac{2014}{2013}+\frac{2014}{2014}}\)
\(=\frac{2013.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}{2014.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2013}+\frac{1}{2014}\right)}\)
\(=\frac{2013}{2014}\)
\(B=\frac{1-3}{1\cdot3}+\frac{2-4}{2\cdot4}+\frac{3-5}{3\cdot5}+\frac{4-6}{4\cdot6}+............+\frac{2011-2013}{2011.2013}+\frac{2012-2014}{2012\cdot2014}-\frac{2013+2014}{2013\cdot2014}\)
A=1/2+1/3+1/4+...+1/2014 phần 2013/1+2012/2+2011/3+...+1/2013
\(A=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2014}}{\dfrac{2013}{1}+\dfrac{2012}{2}+...+\dfrac{1}{2013}}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2014}}{\left(\dfrac{2012}{2}+1\right)+\left(\dfrac{2011}{3}+1\right)+...+\left(\dfrac{1}{2013}+1\right)+\dfrac{2014}{2014}}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2014}}{2014\left(\dfrac{1}{2}+\dfrac{1}{.3}+...+\dfrac{1}{2014}\right)}\)
\(=\dfrac{1}{2014}\)
Tìm x biết: (1/2+1/3+1/4+...+1/2014).x =2013/1+2012/2+2011/3+...+2/2012+1/2013
trước tiên bạn phải tính:
2013/1+2012/2+2011/3+.....+2/2012+1/2013
=1+2012/2)+(1+2011/3)+.....+(1+2/2012)+(1+1/2013) +1 {BƯỚC NÀY TÁCH 2013 RA LÀM 2013SỐ1 ĐỂ CÔNG VS CÁC THỪA SỐ CÒN LẠI}
=2014/2+2014/3+...+2014/2012+2014/2013+2014/2014
=2014.(1/2+1/3+....+1/2012+1/20131/2014
suy ra x=2014
TÍNH NHANH ;
A= 1*2+2*3+3*4+....+2011*2012
B =2012*2013+2013*2014
A=1/2+1/3+1/4+...+1/2014/2013/1+2012/2+2011/3+...+1/2013
2013/2+2013/3+...+2013/2014
2013/1+2012/2+2011/3+2010/4+...+1/2013
1-2+3-4+.....+2011-2012+2013-2014
1 - 2 + 3 - 4 + 5 - 6 + ... + 2011 - 2012 + 2013 - 2014
= ( 1 - 2 ) + ( 3 - 4 ) + ( 5 - 6 ) + ... + ( 2011 - 2012 ) + ( 2013 - 2014 )
= -1 + ( -1 ) + ( -1 ) + ( -1 ) + ... + ( -1 ) + ( -1 )
Có tất cả số số - 1 trong dãy số trên là :
( 2014 - 2 ) : 2 + 1 = 1007.
Giá trị của dãy số trên là :
1007 . ( - 1 ) = -1007.
Vậy 1 - 2 + 3 - 4 + 5 - 6 + ... + 2011 - 2012 + 2013 - 2014 = -1007.
1-2+3-4+.....+2011-2012+2013-2014
=(1-2)+(3-4)+...+(2011-2012)+(2013-2014)
=-1+(-1)+...+(-1)+(-1)
Có tất cả số số (-1) trong dãy số trên là:
(2014-2):2+1=1007
Giá trị của dãy số trên là:
1007.(-1)=-1007
tick mk nha,viết mỏi cả tay^^
1 - 2 + 3 - 4 + 5 - 6 + ... + 2011 - 2012 + 2013 - 2014
= ( 1-2 ) + ( 3 - 4 ) + ( 5 - 6 ) +...+ ( 2011 - 2012 ) + ( 2013 - 2014 )
= - 1 + ( - 1 ) + ( - 1 ) + ( - 1 ) +...+ ( - 1 ) + ( - 1 )
Có tất cả số - 1 trong dãy số trên là :
( 2014 - 2 ) : 2 + 1 = 1007
Gía trị của dãy số trên là :
1007 . ( - 1 ) = - 1007