\(\left[8x-120:4\right]\times3^3=3^6.\)

\(8x-120:4=3^3\)

\(8x-30=27\)

\(8x=27+30\)

\(8x=57\)

\(x=19\)

123 - 5.(x + 4) = 38

123 - 5x - 20 = 38

-5x = 38 - 123 + 20

-5x = -65

x = -65 : -5

x = 13

Vậy x = 13

\(123-5\left(x+4\right)=38\)

\(5\left(x+4\right)=123-38\)

\(5\left(x+4\right)=85\)

\(\left(x+4\right)=17\)

\(x=17-4\)

\(x=13\)

\(\left(3x-2^4\right)\times7^3=2\times7^4\)

\(\left(3x-2^4\right)=2\times7^4:7^3\)

\(\left(3x-2^4\right)=2\times7\)

\(3x-2^4=14\)

\(3x-16=14\)

\(3x=30\)

\(x=30:3\)

\(x=10\)

3x(x+2):7=120:4=30

3x(x+2)=30x7=210

( 3 x ( x + 2 ) : 7 ) x 4 = 120

( 3 x ( x + 2 ) : 7 ) = 120 : 4

3 x ( x + 2 ) : 7 = 30

( x + 2 ) : 7 = 30 : 3

( x + 2 ) : 7 = 10

( x + 2 ) = 10 x 7

x + 2 = 70

      x = 70 - 2

      x = 68

[ 3 x ( x + 2 ) : 7 ] x 4 = 120

( x + 2 ) : 7 = 120 : 4 :3 = 10

x+ 2 = 10 x 7 = 7

x= 70 - 2 =68

[3(x + 2).7].4 = 120

3(x + 2).7      = 120 : 4

3(x + 2)         = 30 : 7

x + 2             = \(\frac{30}{7}:3\)

x                  = \(\frac{10}{7}-2\)

x                  = \(\frac{5}{7}\)

\(\left[3\left(x+2\right).7\right].4=120\)

\(\Rightarrow3\left(x+2\right)=120:4:7=\frac{30}{7}\)

\(\Rightarrow x+2=\frac{30}{7}.\frac{1}{3}=\frac{10}{7}\)

\(\Rightarrow x=\frac{10}{7}-2=-\frac{4}{7}\)

[3(x+2).7].4=120

=>3(x+2).7 = 120:4=30

=>3(x+2) = 30:7=30/7

=>x+2=30/7:3=10/7

=>x=10/7-2=-4/7

( 3 x ( x + 2 ) : 7 ) x 4 = 120

( 3 x ( x + 2 ) : 7 )       = 120 : 4

  3 x ( x + 2 ) : 7         = 30

  3 x ( x + 2 )             = 30 x 7

3 x ( x +2 )                = 210

      x + 2                  = 210 : 3

      x + 2                  = 70

      x                        = 68

ai help vs  :(((

275-(113+x)+63=158
275-(113+x)=95
113+x=175-95
113+x=80
x=80-113
x=33

[3(x+2):7]4=120
3(x+2):7=30
3(x+2)=210
x+2=70
x=68

Cái đề thiếu rồi nha bạn

Phải bằng bao nhiêu chú

[3x(x+2):7]x4=?

[ 3 . ( x + 2 ) : 7 ] . 4 = 120

[ 3 . ( x + 2 ) : 7 ]      = 120 : 4

[ 3 . ( x + 2 ) : 7 ]      = 30

  3 . ( x + 2 )             = 30 . 7

  3 . ( x + 2 )             = 210

       ( x + 2 )             = 210 : 3

       ( x + 2 )             = 70

         x                     = 70 - 2

         x                     = 68

\(\left[3.\left(x+2\right):7\right].4=120\)

\(3.\left(x+2\right):7=480\)
\(3.\left(x+2\right)=480.7\)
\(3.\left(x+2\right)=3360\)
\(x+2=3360:3\)
\(x+2=1120\)
\(x=1120-2\)
\(x=1118\)

[ 3 x ( x + 2 ) : 7 ] x 4 = 120

[ 3 x ( x + 2 ) : 7 ] = 120 : 4

[ 3 x ( x + 2 ) : 7 ] = 30

[ 3 x ( x + 2 ) ] = 30 x 7

[ 3 x ( x + 2 ) ] = 210

[ ( x + 2 ) ] = 210 : 3

[ ( x + 2 ) ] = 70

x = 70 - 2

x= 68

\(\left[3.\left(x+2\right):7\right].4=120\)

\(\Leftrightarrow\left[3.\left(x+2\right):7\right]=30\)

\(\Leftrightarrow3.\left(x+2\right)=210\)

\(\Leftrightarrow\left(x+2\right)=70\)

\(\Leftrightarrow x=68\)

Vậy \(x=68\)

[3.(x+2):7]=120:4=30

3.(x+2)=30x7=210

x+2=210:3=7

x=7-2

x=5

vậy x =5

\(\Leftrightarrow3\left(x+2\right):7=30\)

=>3(x+2)=210

=>x+2=70

hay x=68

\(\left[3\cdot\left(x+2\right)\div7\right]\cdot4=120\)

\(3\cdot\left(x+2\right)\div7=120\div4\)

\(3\cdot\left(x+2\right)\div7=30\)

\(3\left(x+2\right)=30\cdot7\)

\(3\cdot\left(x+2\right)=210\)

x+2=210:3

x+2=70

x=68