\(1.x-\dfrac{2}{3}\times\left(x+9\right)=1\)

\(x-\dfrac{2}{3}\times x-6=1\)

\(x\times\left(1-\dfrac{2}{3}\right)=7\)

\(x\times\dfrac{1}{3}=7\)

\(x=21\)

\(2.x-\dfrac{11}{15}=\dfrac{3+x}{5}\)

\(\dfrac{15x}{15}-\dfrac{11}{15}=\dfrac{9+3x}{15}\)

\(15x-11=9+3x\)

\(12x=20\)

\(x=\dfrac{5}{3}\)

minh@@22@22222@@@@? 

giải giúp mk vs ạ

bn ơi mk rất mún giải hộ pạn nhưng mk k bít để giải xin lỗi pạn nhìu

k mk nhé

ahihu tk k ai pít giải à 

\(\Leftrightarrow x^2+4x+4+x-3-2\left(x^2-1\right)=9.\)

\(\Leftrightarrow-x^2+5x-6=0\)

\(\Leftrightarrow x^2-5x+6=0\Leftrightarrow x^2-2x-3x+6=0\Leftrightarrow x\left(x-2\right)-3\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(x-3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x_1=2\\x_2=3\end{cases}}\)

(x + 3)(x² - 3x + 9) - x(x - 1)(x + 1) = 14

<=> x³ + 27 - x(x² - 1) = 14

<=> x³ + 27 - x³ + x = 14

<=> x³ - x³ + x = 14 - 27

<=> x = -13

\(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)=14\)

\(\Leftrightarrow x^3+27-x^3+x=14\)

hay x=-13

(x + 3)(x² - 3x + 9) - x(x - 1)(x + 1) = 14

=> x³ + 27 - x(x² - 1) = 14

=> x³ + 27 - x³ + x = 14

=>  x = 14 - 27

=> x = -13

Ta có:(x-3)(x²+3x+9)-x(x²-4)=1

     => x³-27-x³+4x=1

     =>4x=28=>x=7

= 0