toi khong biey xin hay giup toi

X=56/27

\(x+\frac{16}{9}=\frac{x}{7}\)

\(\frac{16}{9}=\frac{x}{7}-\frac{x}{1}\) 

\(\frac{16}{9}=\frac{x}{7}-\frac{7x}{7}\)

\(\frac{19}{9}=\frac{\left(-6\right)x}{7}\)

\(\frac{133}{63}=\frac{\left(-54\right)x}{63}\)

\(\Rightarrow133=\left(-54\right)x\)

\(\Rightarrow133:\left(-54\right)=x\)

\(\Rightarrow-2,4629=x\)

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\(\frac{x+2}{3}=\frac{x-2}{2}\Rightarrow2\left(x+2\right)=3\left(x-2\right)\)

=>2x+4=3x-6

=>2x-3x=-4-6

=>-x=-10

=>x=10

k minh di minh lm cho

x(2 + x²)(7 - x) = 0

<=> x = 0 hoặc 2 + x² = 0 hoặc 7 - x = 0

Mà 2 + x² > 0 => x = 0 và 7 - x = 0

=> x = 0 và x = 7

Vậy  x = 0 và x = 7

=>3.(x-3)=2.(x+1)

<=>3x-9=2x+2

<=>3x-2x=2+9

<=>x=11

x-y=2(x+y)                               x-y=x;y                      x=3y

x-y=2x+2y                               3y-y=3y;y                  x=3.3/2

x=3y                                       2y=3                        x=9/2

                                              y=3/2

x^2-2x+1=0

x²-x-x+1=0

x(x-1)-(x-1)=0

(x-1)(x-1)=0

(x-1)²=0

=>x-1=0

x=1

vậy x=1

x²=x⁵ =>x²-x⁵=0

=>x²(1-x³)=0

=>x²(1-x)(x²+x+1)=0

=>x²=0 hoặc 1-x=0 hoặc x²+x+1=0

x³-x²=0

x²(x-1)=0

Suy ra 

x²=0     su ra   x=0

x-1=0   suy ra  x=1

3-x2 =0

3-x=0:2

3-x = 0

  x= 3-0

   x = 3