\(\frac{1,11+0,19-1,3x2^6}{0,296+0,094}-x=\left(\frac{1}{2}+\frac{1}{3}\right):2\)

\(\frac{1,3-1,3x2^6}{0,39}-x=\left(\frac{3}{5}+\frac{2}{5}\right):2\)

\(\frac{0x2^6}{0,39}-x=1:2\)

\(\frac{0}{0,39}-x=0,5\)

\(0-x=0,5\)

\(x=0-0,5\)

\(x=-0,5\)

a) \(\frac{1,11+0,19-12,2}{0,296+0,094}-x=\left(\frac{1}{2}+\frac{1}{3}\right):2\)

Đề đúng:

\(\frac{1,11+0,19-1,3.2^6}{0,296+0,094}-x=\left(\frac{1}{2}+\frac{1}{3}\right):2\)

\(\frac{1,3-1,3.64}{0,39}-x=\left(\frac{3}{6}+\frac{2}{6}\right).\frac{1}{2}\)

\(\frac{1,3.\left(-63\right)}{0,39}-x=\frac{5}{6}.\frac{1}{2}\)

\(\frac{-81,9}{0,39}-x=\frac{5}{12}\)

\(\left(-210\right)-x=\frac{5}{12}\)

\(x=\left(-210\right)-\frac{5}{12}\)

\(x=\frac{-2520}{12}-\frac{5}{12}\)

\(x=\frac{-2525}{12}\)

b) \(x:\left(3\frac{1}{2}-5\frac{1}{6}\right)=4\frac{1}{5}-6\frac{2}{3}\)

\(x:\left(\frac{7}{2}-\frac{31}{6}\right)=\frac{21}{5}-\frac{20}{3}\)

\(x:\left(\frac{21}{6}-\frac{31}{6}\right)=\frac{63}{15}-\frac{100}{15}\)

\(x:\frac{-10}{6}=\frac{-37}{15}\)

\(x.\frac{6}{-10}=\frac{-37}{5}\)

\(x.\frac{-6}{10}=\frac{-37}{5}\)

\(x.\frac{-3}{5}=\frac{-37}{5}\)

\(x=\frac{-37}{5}:\frac{-3}{5}\)

\(x=\frac{-37}{5}.\frac{5}{-3}\)

\(x=\frac{-37}{-3}\)

\(x=\frac{37}{3}\)

Sai đề bài

Lẽ ra câu a chỉ chia 2 thì chia 22

Sai đề bài mina-san 

thank you vì đã trả lời hihi

Ta tách ra làm 2 ý nhé:

* \(1,11+0,19-1,32-\left(\frac{1}{2}+\frac{1}{3}\right):2\)

\(=1,3-1,32-\frac{5}{6}=-0,02-\frac{5}{6}=-\frac{1}{50}-\frac{5}{6}=-\frac{64}{75}\)

* \(\left(5\frac{7}{8}-2\frac{1}{4}-0,5\right):2\frac{23}{26}\)

\(\left(3\frac{5}{8}-\frac{1}{2}\right):2\frac{23}{26}=3\frac{1}{8}:2\frac{23}{26}=1\frac{1}{12}=\frac{13}{12}\)

VẬY TA CÓ: \(\frac{-64}{75}< x< \frac{13}{12}\)mà  \(\left(x\inℕ\right)\)

\(\Rightarrow\)ta có x là số nguyên nằm giữa -0.8533... và 1,0833...

vậy ta có x là các số nguyên 0 và 1 

MK KO CHẮC CHO LẮM NÊN BN CÓ THỂ THAM KHẢO Ý KIẾN MẤY BN KHÁC NHÉ.

K MK NHA. CHÚC BN HỌC TỐT. ^_^

fqaeggg

a)
=\(2x-\dfrac{1}{2}=\dfrac{12}{9}\cdot\dfrac{3}{4}=1\)
=\(2x=1+\dfrac{1}{2}=1.5\)
=\(x=1.5:2=0.75\)
b)
=\(x^2=0+2=2\)
TH1:\(x=2\)
TH2:\(x=-2\)

Bài 1:

a: \(2x-\dfrac{1}{2}:\dfrac{3}{4}=\dfrac{12}{9}\)

=>\(2x-\dfrac{1}{2}\cdot\dfrac{4}{3}=\dfrac{4}{3}\)

=>\(2x=\dfrac{4}{3}+\dfrac{2}{3}=\dfrac{6}{3}=2\)

=>x=2/2=1

b: \(x^2-2=0\)

=>\(x^2=2\)

=>\(\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\end{matrix}\right.\)

Bài 2:

a: \(A=\dfrac{1,11+0,19-13\cdot2}{2,06+0,54}-\left(\dfrac{1}{2}+\dfrac{1}{4}\right):2\)

\(=\dfrac{1,3-26}{2,6}-\dfrac{3}{4}:2\)

\(=-9,5-\dfrac{3}{8}=-\dfrac{79}{8}\)

\(B=\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right):\left(2\dfrac{23}{26}\right)\)

\(=\left(5+\dfrac{7}{8}-2-\dfrac{1}{4}-\dfrac{1}{2}\right):\dfrac{75}{26}\)

\(=\left(3+\dfrac{1}{8}\right)\cdot\dfrac{26}{75}=\dfrac{25}{8}\cdot\dfrac{26}{75}=\dfrac{13}{12}\)

b: A<x<B

=>\(-\dfrac{79}{8}< x< \dfrac{13}{12}\)

mà \(x\in Z\)

nên \(x\in\left\{-9;-8;...;0;1\right\}\)

  ( 1.11 + 0.19 - 2.6 ) : ( 2.06 + 0.54 ) - ( 1/2 + 1/3 ) : 2

=         -1.3            :         2.6            -          5/6            :                  2

=               -1/2                                -                      5/12

=                                                   -11/12

=     -11/12  ( bằng âm mười một phần mười hai )