tinh gia tri bieu thuc
A=(1999*1998+1998+1997)*1+1/2:1/1/2-1/1/3
Những câu hỏi liên quan
Tinh gia tri moi biêu thuc sau:a.0,1+0,2+0,3+...+0,9+0,10+0,11+...+0,19. B. (1999×1998+1998×1997)×(1+1/2:1 1/2_1 1/3)
tinh gia tri bieu thuc
a) A= 5a3b8 voi a = -1, b = 1
b) B= -9a4b2voi a = -1, b =2
a: Thay a=-1 và b=1 vào A, ta được:
\(A=5\cdot\left(-1\right)^3\cdot1^8=5\cdot\left(-1\right)\cdot1=-5\)
b: Thay a=-1 và b=2 vào B, ta được:
\(B=-9\cdot\left(-1\right)^4\cdot2^2=-9\cdot4=-36\)
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tính D =1/2000*1999 -1/1999*1998-1/1998*1997-..-1/3*2-1/2*1
\(D=\dfrac{1}{2000.1999}-\dfrac{1}{1999.1998}-\dfrac{1}{1998.1997}-...-\dfrac{1}{3.2}-\dfrac{1}{2.1}\)
\(D=\dfrac{1}{1999.2000}-\left(\dfrac{1}{1998.1999}+\dfrac{1}{1997.1998}+...+\dfrac{1}{2.3}+\dfrac{1}{1.2}\right)\)\(D=\dfrac{1}{1999.2000}-\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+....+\dfrac{1}{1997.1998}+\dfrac{1}{1998.1999}+\dfrac{1}{1999.2000}\right)\)
\(D=\dfrac{1}{1999.2000}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+....+\dfrac{1}{1997}-\dfrac{1}{1998}+\dfrac{1}{1998}-\dfrac{1}{1999}+\dfrac{1}{1999}-\dfrac{1}{2000}\right)\)\(D=\dfrac{1}{1999.2000}-\dfrac{1999}{2000}\)
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(1999 x 1998 + 1998 + 1997) x ( 1 + 1/2 : 1 1/2 - 1 1/3 )
(1999×1998+1998+1997)×(1/1+1/2:3/2-4/3)
(1999×1998+1998+1997)×(1/1+1/2×2/3-4/3)
1999×1998+1998+1997)×(1/1+1/3-4/3)
(1999×1998+1998+1997)×(4/3-4/3)
(1999×1998+1998+1997)×0
0
Tính nhanh:
( 1999 x 1998 + 1998 x 1997 ) x ( 1 + 1/2 : 1 1/2 - 1 1/3)
\(=\left(1999\times1998+1998\times1997\right)\times\left(1+\dfrac{1}{2}:1\dfrac{1}{2}-1\dfrac{1}{3}\right)\)
\(=\left(1999\times1998+1998\times1997\right)\times\left(1+\dfrac{1}{2}:\dfrac{3}{2}-\dfrac{4}{3}\right)\)
\(=\left(1999\times1998+1998\times1997\right)\times\left(1+\dfrac{1}{3}-\dfrac{4}{3}\right)\)
\(=\left(1999\times1998+1998\times1997\right)\times\left(\dfrac{4}{3}-\dfrac{4}{3}\right)\)
\(=\left(1999\times1998+1998\times1997\right)\times0\)
\(=0\)
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Tinh M : 1-2-3+4+5-6-7+8...+1997-1998-1999+2000
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1/2 + 1/3 + 1/4 + ... + 1/2000 / 1999/1 + 1998/2 + 1997/3 +...+ 1999/1
< 1999 x 1998+1998 + 1997 > x < 1+ 1/2 : 1 1/2 - 1 1/3 >
\(\left(1999.1998+1998+1997\right).\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).\left(1+\frac{1}{3}-\frac{4}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).\left(\frac{4}{3}-\frac{4}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).0=0.\)
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< 1999 x 1998 + 1998 + 1997 > x < 1 1/2 : 1 1/2 - 1 1/3 >
= ( 1999 . 1998 + 1998 + 1997 ) .\(\left(1\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)
= 3997997 .\(-\frac{1}{3}\)
=\(-\frac{3997997}{3}\)
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