m=8^10+4^10\8^4+4^11
Tính M = \(\sqrt{\dfrac{8^{10}-4^{10}}{4^{11}-8^4}}\)
\(M=\sqrt{\dfrac{2^{30}-2^{20}}{2^{22}-2^{12}}}=\sqrt{\dfrac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}=\sqrt{2^8}=\sqrt{16^2}=16\)
tinh M = (8^10+4^10)/ 8^4+4^11
M= (2x4)^10 + 4^11 / (2x4)^4 + 4^8
M= 2^10 x 4^10 + 4^11 / 2^4 x 4^4 + 4^8
M= 2^6 x 4^21 / 2 x 4^12
M=2^7 x 4^9 / 2 x 4
M=2^6 x 4^8
M=2^6 x (2x2)^8
M=2^6 x 2^8 x 2^8 = 2 x 2^2 X 2^8 = 2^11 = 2048
nguyển như quỳnh bạn Nguyễn Đình Phương làm đúng rồi bạn **** bạn ấy đi nhé
=(2^3)^10+(2^2)10/(2^2)^4+(2^4)^11
=2^30+2^20/2^12+2^22
=2^20(2^10+1)/2^12(2^10+1)
=2^8
=256
M= 8^10 + 4^10 chia cho 8^4 + 8^11
tính M = 8^10 +4^10/ 8^4 +4 ^11
Mình ns kết quả nha
Bằng 256
Ủng hộ mk nhaaa
Tim M
M=\(\frac{^{8^{10}}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(M=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}\)
\(M=\frac{2^{20}}{2^{12}}\)
\(M=\frac{2^{12}.2^8}{2^{12}}\)
\(M=2^8\)
M = 256
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}=2^8=256\)
tính \(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{ \left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)
Chúc học tốt :)
Tính : M = \(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(M=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(1+2^{10}\right)}\)
\(M=\frac{2^{20}}{2^{12}}\)
\(M=2^8=256\)
\(M=\frac{8^{10}+4^{10}=1.074.790.400}{8^4+4^{11}=4.198.400}\)
Vậy
\(\Rightarrow M=\frac{1.074.790.400}{4.198.400}\)
P/s; Ko chắc đâu nhé
Tính M= \(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.2^8\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=2^8\)
TÌM M=\(\sqrt{\frac{8^{10}-4^{10}}{4^{11}-8^4}}\)
vô danh
\(M=\sqrt{\frac{8^{10}-4^{10}}{4^{11}-8^4}}\)
\(M=\sqrt{\frac{2^{30}-2^{20}}{2^{22}-2^{12}}}\)
\(M=\sqrt{\frac{2^{20}.\left(2^{10}-1\right)}{2^{12}.\left(2^{10}-1\right)}}\)
\(M=\sqrt{\frac{2^{20}}{2^{12}}}\)
\(M=\sqrt{2^{20-12}}\)
\(M=\sqrt{2^8}\)
\(M=16\)
vậy \(M=16\)
P/S Đừng ai coppy bài mình nha