a) 2(2x - 8) = 24

2x - 8 = 12

2x = 20

x = 10

b)3.(2^x - 26) = 18

2^x - 26 = 6

2^x = 32

x = 5

\(a,2448:\left[119-\left(x-6\right)\right]=24\)

\(119-\left(x-6\right)=2448:24\)

\(119-\left(x-6\right)=102\)

\(x-6=119-102\)

\(x-6=17\)

\(x=17+6\)

\(\Rightarrow x=23\)

\(b,2016-100\times\left(x+11\right)=128:8\)

\(2016-100\times\left(x+11\right)=16\)

\(100\times\left(x+11\right)=2016-16\)

\(100\times\left(x+11\right)=2000\)

\(x+11=2000:100\)

\(x+11=20\)

\(x=20-11\)

\(\Rightarrow x=9\)

\(a,2448:\left[119-\left(x-6\right)\right]=24\\ 119-\left(x-6\right)=2448:24\\ 119-\left(x-6\right)=102\\ x-6=119-102\\ x-6=17\\ x=17+6\\ x=23\\ b,2016-100\times\left(x+11\right)=128:8\\ 2016-100\times\left(x+11\right)=16\\ 100\times\left(x+11\right)=2016-16\\ 100\times\left(x+11\right)=2000\\ x+11=2000:100\\ x+11=20\\ x=20-11\\ x=9\)

\(a=0;1;2;3\) ở câu a

\(a=0;1;2;3;4;5;6;7\) ở câu b

\(a=0;1;2;3;4;5;6\) ở câu c

a) a = 3

b) b = 8

c) x = 1

d) ab = 23

{24;42}

{51;15}

ab hay \(\overline{ab}\) vậy em?

ừ nhỉ

ko để ý

ab x ab =600+ab 

ab x (ab -1) =600=24 va 25

hai so lien tiep moi duoc 600 nen 

ab=25

ab x ab=6ab         =600+ab ab x ab‐ab        =600

abx﴾ab‐1﴿=600

Vì abx﴾ab‐1﴿là 2 số tự nhiên liên tiếp mà 600=24.25

Vậy ab=25

\(\overline{ab}\cdot5+18=\overline{bab}\)

\(\Rightarrow\overline{ab}\cdot5+18=b\cdot100+\overline{ab}\)

\(\Rightarrow\overline{ab}\cdot5-\overline{ab}+18=b\cdot100\)

\(\Rightarrow\overline{ab}\cdot4=b\cdot100-18\)

\(\Rightarrow\overline{ab}\cdot4:2=\left(b\cdot100-18\right):2\)

\(\overline{ab}\cdot2=b\cdot50-9\)

Ta có:  \(\overline{ab}\cdot2\) ⋮ \(2\) 

\(\Rightarrow b\cdot100-9\) ⋮ \(2\) 

Mà: \(b\cdot100\) ⋮ 2 còn 9 ⋮ 2 (vô lý)

Vậy không có giá trị \(\overline{ab}\) phù hợp

ai giải giúp mình mình thanh kiu nhìu nhé