a=12

b=72

= (1+99) + (3 + 97) + ( 5 + 95 ) + ....... + ( 49 + 51 )

có tất cả 25 cặp

= 100 x 25 = 2500

Nhớ k mình nhé! Thanks bạn

(1+99)+(3+97)+....+(49+51)=100+100+...+100=5000

Luu y:co 50 so 100

mk thieu la:5000:2=2500 vi co 25 cap

\(\sqrt{14-8\sqrt{3}}\)\(=\sqrt{6-2.4.\sqrt{3}+8}\)

\(=\sqrt{\left(\sqrt{6}\right)^2-2\sqrt{3.16}+\left(\sqrt{8}\right)^2}\)

\(=\sqrt{\left(\sqrt{6}\right)^2-2\sqrt{48}+\left(\sqrt{8}\right)^2}\)

\(=\sqrt{\left(\sqrt{6}-\sqrt{8}\right)^2}\)

\(=\sqrt{6}-\sqrt{8}\)

\(\dfrac{2}{5}-\left|\dfrac{1}{2}-x\right|=6\)

\(\Leftrightarrow\left|\dfrac{1}{2}-x\right|=\dfrac{2}{5}-6\)

\(\Leftrightarrow\left|\dfrac{1}{2}-x\right|=-\dfrac{28}{5}\)( vô lý do \(\left|\dfrac{1}{2}-x\right|\ge0\forall x\))

Vậy \(x\in\left\{\varnothing\right\}\)

\(\Rightarrow\left|\dfrac{1}{2}-x\right|=\dfrac{2}{5}-6=-\dfrac{28}{5}\\ \Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}-x=-\dfrac{28}{5},\forall\dfrac{1}{2}-x\ge0\\\dfrac{1}{2}-x=\dfrac{28}{5},\forall\dfrac{1}{2}-x< 0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{61}{10},\forall x\le\dfrac{1}{2}\left(loại\right)\\x=-\dfrac{51}{10},\forall x>\dfrac{1}{2}\left(loại\right)\end{matrix}\right.\Rightarrow x\in\varnothing\)

\(\frac{-6}{30}=\frac{x}{-20}\)

nhân chéo  \(x\cdot30=\left(-6\right)\cdot\left(-20\right)\)

=>\(30x=120\)

\(x=4\)

\(\frac{-6}{30}=\frac{3}{y}\)

nhân chéo => \(-6x=90\)

\(x=-15\)

\(\frac{-6}{30}=\frac{z}{5}\)

nhân chéo => \(30z=-30\)

\(z=-1\)

x/-20 = -6/30 

=> 30x = 120 

<=> x = 4 

3/y = -6/30 

=> -6y = 90 

<=> y = -15 

z/5 = -6/30 

=> -6z = 150 

<=> z = - 25 

x=4,y=-15,z=1

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