BT: tìm x
a, 14,9 + x = 58,3
b, 75 : 5 + x = 100.
Tìm x
a/ \(^{2^x}\). \(^{5^x}\) = 1000
b/ \(\dfrac{75^x}{25^x}\) = 81
B1:Tính
a,3.52-16:22
b,22.17-23.14
c,15.141+59.10
d,17.85+15.17-120
e,100-[75-(7-2)]2
g,(23.94+93.45):(92.10-92)
B2:Tìm x
a,420+65.4=(x+175):3+30
b,96-3.(x+1)=42
c,(x-47)-115=0
d,(x-36):18=12
e,2x=16
B3:Tìm x
a,60-3.(x-2)=51
b,4x-20=25:22
c,8.6+288:(x-3)2=50
mk đang càn rất gấp
Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
Tìm x bt :
a. 75 : x = ( - 5 ) + 20
b. 5x+5 - 20170 = 23 . 3
Tìm x , bt:
a, 75 : x = ( -5) + 20
75: x = 15
x= 75: 15
x= 5
Vậy x = 5
b, \(5^{x+5}\) - \(2017^0\) = \(2^3\) .3
\(5^{x+5}\) - 1 = 8 . 3
\(5^{x+5}\) - 1 = 24
\(5^{x+5}\) = 25
\(5^{x+5}\)= \(5^2\)
=> x + 5 = 2
=> x= 2-5
x= -3
Vậy x= -3
a, 75 : x = ( -5 ) + 20
75 : x = 15
x = 75 : 15
x = 5
b, \(5^{x+5}-2017^0=2^3.3\)
\(5^{x+5}-1=8.3\)
\(5^{x+5}-1=24\)
\(5^{x+5}=24+1\)
\(5^{x+5}=25\)
\(5^{x+5}=5^2\)
\(\Rightarrow x+5=2\)
\(x=2-5\)
\(x=-3\)
a.
75 : x = ( - 5 ) + 20
75 : x = 15
x = 75 : 15
x = 3
b.
5x+5 - 20170 = 23 x 3
5x+5 - 20170 = 8 x 3
5x+5 - 1 = 24
5x+5 = 24 + 1
5x+5 = 25
Mà 55 = 25 => x + 5 = 25
x = 25 - 5
x = 20
Vậy x = 20
( 3,7 x X) + 5,28= 14,9
tìm X
(3,7*x)+5,28=14,9
3,7*x =14,9-5,28
3,7*x =9,62
x =9,62:3,7
x =2,6
tìm x,bt
1-3+5-7+9-11+...+x=-100
Mk ko viết lại đề bài nhé
<=> -2-2-2-...-2=-100
<=>(-2)(\({\\{x-1} \over 4}\)+1)=-100
<=>\({\\{x-1} \over 4}\)+1=50
<=>\({\\{x-1} \over 4}\)=49
<=>x-1=196
<=>x=197
Nhớ k nha
x = 197
tìm x : 52.x-3 - 100 = 75
bạn có thể ghi lại đề cho rõ ràng hơn một chút được không ạ??
Tìm x , biết :
5 + ( 75 - x ) + ( 60 - x ) + x = 100
TL :
5 + ( 75-x ) + ( 60 - x ) + x = 100
5 + 75 - x + 60 - x + x = 100
( 5 + 75 + 60 ) + ( x - x - x) = 100
140 - x = 100
x = 140 - 100
x = 40
Hok tốt ạ :33
Tìm x
a) \(x+1-2\sqrt{x+1}=0\)
b) \(2x-4-\sqrt{x-2}=0\)
c) \(2\sqrt{9x-27}-\dfrac{1}{5}\sqrt{25x-75}-\dfrac{1}{7}\sqrt{49x-147}=20 \)
\(a)ĐK:x\ge-1\\ \Leftrightarrow x+1=2\sqrt{x+1}\\ \Leftrightarrow x^2+2x+1=4x+4\\ \Leftrightarrow x^2+2x-4x+1-4=0\\ \Leftrightarrow x^2-2x-3=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\left(tm\right)\\x=-1\left(tm\right)\end{matrix}\right.\)
Vậy \(S=\left\{3;-1\right\}\)
\(b)ĐK:x\ge2\\ \Leftrightarrow2x-4=\sqrt{x-2}\\ \Leftrightarrow4x^2-16x+16=x-2\\ \Leftrightarrow4x^2-16x-x+16+2=0\\ \Leftrightarrow4x^2-17x+18=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\left(tm\right)\\x=2\left(tm\right)\end{matrix}\right.\)
Vậy \(S=\left\{\dfrac{9}{4};2\right\}\)
\(c)ĐK:x\ge3\\ \Leftrightarrow2\sqrt{9\left(x-3\right)}-\dfrac{1}{5}\sqrt{25\left(x-3\right)}-\dfrac{1}{7}\sqrt{49\left(x-3\right)}=20\\ \Leftrightarrow2.3\sqrt{x-3}-\dfrac{1}{5}\cdot5\sqrt{x-3}-\dfrac{1}{7}\cdot7\sqrt{x-3}=20\\ \Leftrightarrow6\sqrt{x-3}-\sqrt{x-3}-\sqrt{x-3}=20\\ \Leftrightarrow4\sqrt{x-3}=20\\ \Leftrightarrow\sqrt{x-3}=5\\ \Leftrightarrow x-3=25\\ \Leftrightarrow x=25+3\\ \Leftrightarrow x=28\left(tm\right)\)
Vậy \(S=\left\{28\right\}\)
Tìm x
a)(x-15)-75=10
b)124+(448-x)=217
c)814-(x-305)=712
Giúp mình vớiiiiiii
\(a,\Rightarrow x-15=85\Rightarrow x=100\\ b,\Rightarrow448-x=217-124=93\\ \Rightarrow x=448-93=355\\ c,\Rightarrow x-305=804-712=92\Rightarrow x=92+305=397\)