Rút gọn giúp Giang nha
\(\frac{x-\frac{x-1}{2}}{2}\)
Những câu hỏi liên quan
Rút gọn giúp Giang nha
\(\frac{\frac{2x-5}{3}-2\left(2x+\frac{x-1}{5}\right)}{4}\)
Rút gọn A:
A = \(\frac{x+2}{x+3}-\frac{5}{x^2+x-6}+\frac{1}{2-x}.\)
GIÚP MK GIẢI NHA M.N! THANKS!!!!!
Cái này dễ mà bn
Ta có:\(A=\frac{x+2}{x+3}-\frac{5}{x^2+x-6}+\frac{1}{2-x}\left(ĐK:x\ne2;-3\right)\)
\(\Leftrightarrow A=\frac{x+2}{x+3}-\frac{5}{\left(x+3\right)\left(x-2\right)}-\frac{1}{x-2}\)
\(\Leftrightarrow A=\frac{x^2-4-5-x-3}{\left(x+3\right)\left(x-2\right)}\)
\(\Leftrightarrow A=\frac{x^2-x-12}{\left(x+3\right)\left(x-2\right)}=\frac{x+4}{x-2}\)
Đúng 0
Bình luận (0)
\(A=\frac{x+2}{x+3}-\frac{5}{x^2+x-6}+\frac{1}{2-x}\)
\(\Leftrightarrow A=\frac{x}{\left(2+3\right)}^2-\frac{5}{x^3-6}+\left(2-x\right)\)
\(\Leftrightarrow A=\frac{x}{5}^2-\frac{5}{x^3-6}+\left(2-x\right)\)
Ps: Không chắc đâu nhé! Thánh đây mới lớp 6 thôi
Đúng 0
Bình luận (0)
:v công nhận năm lớp 6 tôi trẩu vl!
ĐK: \(x\ne2;x\ne-3\)
\(A=\frac{x+2}{x+3}-\frac{5}{x^2+x-6}+\frac{1}{2-x}\)
\(=\frac{x+2}{x+3}-\frac{5}{\left(x+3\right)\left(x-2\right)}-\frac{1}{x-2}\)
\(=\frac{\left(x+2\right)\left(x-2\right)-5-x-3}{\left(x+3\right)\left(x-2\right)}\)
\(=\frac{x^2-4-5-x-3}{\left(x+3\right)\left(x+2\right)}=\frac{x^2-x-12}{\left(x+3\right)\left(x+2\right)}=\frac{\left(x-4\right)\left(x+3\right)}{\left(x+3\right)\left(x+2\right)}=\frac{x-4}{x+2}\)
Đúng 0
Bình luận (0)
Rút gọn biểu thức:
\(A=\left[\frac{1}{x^2+2xy+y^2}-\frac{1}{x^2-y^2}\right]:\frac{4xy}{y^2-x^2}\)
Giúp nha m.n! thanks!!!
Ta có: \(A=\left(\frac{1}{x^2+2xy+y^2}-\frac{1}{x^2-y^2}\right):\frac{4xy}{y^2-x^2}\)
\(=\left[\frac{1}{\left(x+y\right)^2}-\frac{1}{\left(x+y\right)\left(x-y\right)}\right].\frac{\left(y+x\right)\left(y-x\right)}{4xy}\)
\(=\frac{1}{x+y}\left(\frac{1}{x+y}-\frac{1}{x-y}\right).\frac{\left(x+y\right)\left(y-x\right)}{4xy}\)
\(=\frac{-2y}{\left(x+y\right)\left(x-y\right)}.\frac{x-y}{-4xy}\)
\(=\frac{1}{\left(x+y\right).2x}\)
Kb với mình nha mn!
Đúng 0
Bình luận (0)
MN giúp mK rút gọn con này nha:
\(A=\frac{\sqrt{X}+1}{\sqrt{X}-2}+\frac{2\sqrt{2}}{\sqrt{X}+2}+\frac{2+5\sqrt{X}}{4-X}\)
\(A=\frac{\left(\sqrt{x}+1\right)\left(\sqrt{x}+2\right)+2\sqrt{2}\left(\sqrt{x}-2\right)-2-5\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\frac{x+3\sqrt{x}+2+2\sqrt{2}.\sqrt{x}-4\sqrt{2}-2-5\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)
\(=\frac{x+2\sqrt{x}\left(\sqrt{2}-1\right)-4\sqrt{2}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\sqrt{2}\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\frac{\sqrt{x}+2\sqrt{2}}{\sqrt{x}+2}\)
Đúng 0
Bình luận (0)
Rút gọn biểu thức sau:
\(A=\left(\frac{x^2-2x}{2x^2+8}-\frac{2x^2}{8-4x+2x^2-x^3}\right)\left(1-\frac{1}{x}-\frac{2}{x^2}\right)\)
^ Giúp tui nhanh zới nha! ^
=[x(x-2)/2(x2+4)-2x2/(4+x2)(2-x)][x(x-2)(x+1)/x3]
={[x(x-2)(2-x)-4x2 ]/2(2-x)(4+x2)} .[x(x-2)(x+1)/x3 ]
=[-x(x2+4)/2(2-x)(4+x2)].[x(x-2)(x+1)/x3 ]
=-x.x(x-2)(x+1)/2(2-x)x3
=(x+1)/2x
Cho B=\(1:\left(\frac{x+2}{x\sqrt{x}+1}+\frac{\sqrt{x}-1}{x-\sqrt{x}+1}-\frac{\sqrt{x}-1}{x-1}\right)\)
Rút gọn B, so sánh B với 1
Giúp mình NHa
1/ rút gọn biểu thức:
a) \(\frac{1}{x^2-\sqrt{x}}:\frac{\sqrt{x}+1}{x\sqrt{x}+x+\sqrt{x}}\)
giúp mjk nha m.n!!!! mk thks m.n nhìu
\(=\frac{1}{\sqrt{x}\left(x\sqrt{x}-1\right)}:\frac{\sqrt{x}+1}{\sqrt{x}\left(x+\sqrt{x}+1\right)}\)
\(=\frac{1}{\sqrt{x}\left(\sqrt{x^3}-1\right)}.\frac{\sqrt{x}\left(x+\sqrt{x}+1\right)}{\sqrt{x}+1}\)
\(=\frac{1}{\sqrt{x}\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}.\frac{\sqrt{x}\left(x+\sqrt{x}+1\right)}{\sqrt{x}+1}\)
\(=\frac{1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}=\frac{1}{x-1}\)
Đúng 0
Bình luận (0)
Rút gọn : B=(1-\(\frac{1}{2}\) ) x ( 1-\(\frac{1}{3}\) ) x ( 1-\(\frac{1}{4}\) ) x ..... x (1 - \(\frac{1}{2}\) )
m.n giúp mk nha mk cần gấp
rút gọn
\(\frac{2\left(x+4\right)}{x-3\sqrt{x}-4}+\frac{\sqrt{x}}{\sqrt{x}+1}-\frac{8}{\sqrt{x}-4}\)
mk cần gấp nha bạn
giúp mk với
\(\frac{2.\left(x+4\right)}{\left(\sqrt{x}+1\right).\left(\sqrt{x}-4\right)}+\frac{\sqrt{x}.\left(\sqrt{x}-4\right)}{\left(\sqrt{x}+1\right).\left(\sqrt{x}-4\right)}-\frac{8.\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-4\right)\left(\sqrt{x}+1\right)}\)
=\(\frac{2x+8+x-4\sqrt{x}-8\sqrt{x}-8}{\left(\sqrt{x}+1\right).\left(\sqrt{x}-4\right)}\)
=\(\frac{3x-12\sqrt{x}}{mc}\)
=\(\frac{3\sqrt{x}.\left(\sqrt{x}-4\right)}{\left(\sqrt{x-4}\right)\left(\sqrt{x}+1\right)}=\frac{3\sqrt{x}}{\sqrt{x}+1}\)
k tk mk cung lam cho
Đúng 0
Bình luận (0)