\(A=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03\)

\(A=\left(9,375+7,625\right)+4,03\)

\(A=17+4,03\)

\(A=21,03\)

\(A=\left(9+\frac{30303}{80808}+7+\frac{303030}{484848}\right)+4,03\)

\(A=\left(9+\frac{3\times10101}{8\times10101}+7+\frac{30\times10101}{48\times10101}\right)+4,03\)

\(A=\left(9+\frac{3}{8}+7+\frac{5}{8}\right)+4,03\)

\(A=\left(9+7+\frac{3}{8}+\frac{5}{8}\right)+4,03\)

\(A=\left(16+1\right)+4,03\)

\(A=17+4,03=21,03\)

H = (9/30303/80808+7/303030/484848)+4,03

   = ( \(\frac{75}{8}+\frac{61}{8}\)) + \(\frac{403}{100}\)

   = \(\frac{136}{8}\)+ \(\frac{403}{100}\)

   =  17 + \(\frac{403}{100}\)

   =  \(\frac{2103}{100}\)

Vậy : H = \(\frac{2103}{100}\)

#Chúc bạn học tốt !

\(H=\left(9+\dfrac{3}{8}+7+\dfrac{5}{8}\right)+4.03=17+4.03=21.03\)

\(F=\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}\left(21\frac{3}{7}+18\frac{4}{7}\right)\right).\frac{15}{78}=\left(\frac{39}{4}.40\right).\frac{15}{78}=390.\frac{15}{78}=75\)\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03=\left(9\frac{3}{8}+7\frac{30}{48}\right)+4,03=17+4,03=21,03\)

\(C=9\frac{30303}{80808}+4,03+7\frac{303030}{484848}\)

     \(=9\frac{3}{8}+4\frac{3}{100}+7\frac{5}{8}\)

      \(=\left(9+7\right)+\left(\frac{3}{8}+\frac{5}{8}\right)+4\frac{3}{100}\)

      \(=16+1+4\frac{3}{100}\)

       \(=21\frac{3}{100}\)