tim x biet 1/2(x-2/3)-1/3(2x-3)=x+1/2
tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
Tim x biet
x-4/3=x+2/-2
2x-1/x-3=2x+3/x-1
câu trên mk làm rồi
\(\dfrac{2x-1}{x-3}=\dfrac{2x+3}{x-1}\)
\(\Rightarrow\left(2x-1\right)\left(x-1\right)=\left(x-3\right)\left(2x+3\right)\)
\(\Rightarrow2x^2-x-2x+1=2x^2-6x+3x-9\)
\(\Rightarrow-x-2x+6x-3x=-1-9\)
\(\Rightarrow0=-10\) (vô lí)
Vậy ko tồn tại giá trị của x.
tim x biet -2/3 (x-1/4)=1/3( 2x -1)
\(\frac{-2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)\(\Leftrightarrow-2\left(x-\frac{1}{4}\right)=2x-1\)\(\Leftrightarrow-2x+\frac{1}{2}-2x+1=0\Leftrightarrow x=\frac{3}{8}\)
tim x biet
(x+1)2+(x-2)^3-2x^2(x-1,5)=3
x+1 mu 3 chu ko phai mu 2 nha tui ghi lon cai dau tien
Ta có: (x + 1)3 + (x - 2)3 - 2x2 (x - 1,5) = 3
x3 + 1 + x3 - 8 - 2x3 + 3x2 = 3
(x3 + x3 - 2x3 ) + 3x2 +(1 - 8) = 3
3x2 - 7 = 3
3x2 = 10
x2 = \(\frac{10}{3}\)
Vậy x = \(\sqrt{\frac{10}{3}}\)
Tim so nguyen x biet : -x/2+2x/3+x+1/4+2x+1/6=3/8
12x/6 + 4x/6 - 3x/6 = 3/8 - 1/4 - 1/6
13x/6 = (9 - 6 - 4)/24 = -1/24
--> x = -1/52
Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
Tim x,y,z biet:2(x-1)-3(2x+2)-4(2x+3)=16
2(x-1)-3(2x+2)-4(2x+3)=16
2x-2-6x+6-8x+12=16
(2x-6x-8x)-(2+6+12)=16
(-12).x-20=16
(-12).x=16+20=36
x=36:(-12)=-3
2(x-1)-3(2x+2)-4(2x+3)=16
2x-2-6x-6-8x-12=16
2x-6x-8x=16+2+6+12
-12x=36
x=-3
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Chúc học tốt
tim x biet (x^2+2x+1)(x+2)-x^2(x-3)-7x(x-1)=3x-9