\(\frac{-2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)\(\Leftrightarrow-2\left(x-\frac{1}{4}\right)=2x-1\)\(\Leftrightarrow-2x+\frac{1}{2}-2x+1=0\Leftrightarrow x=\frac{3}{8}\)
có phải 1/2 ta lấy 1/4 nhân 2 đg k
\(-2\times\frac{-1}{4}\) = \(\frac{1}{2}\) đó bạn