`#3107.101107`

`1)`

`58 + 7x = 100`

`=> 7x = 100 - 58`

`=> 7x = 42`

`=> x = 42 \div 7`

`=> x = 6`

Vậy, `x = 6`

`2)`

`(x - 12) \div 12 = 12`

`=> x - 12 = 12*12`

`=> x - 12 = 144`

`=> x = 144 + 12`

`=> x = 156`

Vậy, `x = 156`

`3)`

`x - 56 \div 4 = 16`

`=> x - 14 = 16`

`=> x = 16 + 14`

`=> x = 30`

Vậy, `x = 30`

`4)`

`101 + (36 - 4x) = 105`

`=> 36 - 4x = 105 - 101`

`=> 36 - 4x = 4`

`=> 4x = 36 - 4`

`=> 4x = 32`

`=> x = 32 \div 4`

`=> x = 8`

Vậy, `x = 8`

`5)`

`2(x - 51) = 2*2^3 + 20`

`=> 2(x - 51) = 2^4 + 20`

`=> 2(x - 51) = 16 + 20`

`=> 2(x - 51) = 36`

`=> x - 51 = 36 \div 2`

`=> x - 51 = 18`

`=> x = 18 + 51`

`=> x = 69`

Vậy, `x = 69.`

1) 58 + 7x=100

             7x = 100 - 58

             7x = 42

              x = 42 : 7

              x = 6

2)(x-12):12=12

    (x - 12) = 12 x 12

    x - 12   = 144

     x          = 144 + 12

      x =  156

3)x-56:4=16

   x - 14 = 16

    x       = 16 + 14

    x       = 30

4) 101+(36-4x)=105

             (36-4x) = 105 - 101

              36-4x  =   4

                     4x = 36 - 4

                      4x = 32

                        x = 32 : 4

                        x = 8

5)2(x-51)=2.2 mũ 3 + 20

    2(x-51)=2.8 + 20

     2(x-51)=16 + 20

     2(x-51)= 36

        x - 51 = 36 : 2

         x - 51 = 18

         x = 18 + 51

         x = 69

1: 7x+58=100

=>\(7x=100-58=42\)

=>\(x=\dfrac{42}{7}=6\)

2: \(\left(x-12\right):12=12\)

=>\(x-12=12\cdot12=144\)

=>x=156

3: \(x-56:4=16\)

=>\(x-14=16\)

=>x=30

4: \(101+\left(36-4x\right)=105\)

=>36-4x=4

=>4x=32

=>x=8

5: \(2\cdot\left(x-51\right)=2\cdot2^3+20\)

=>\(2\left(x-51\right)=16+20=36\)

=>x-51=18

=>x=69

`a) 48048 - 48048 : 24 - 24 x 58 `

` = 48048 - 2002- 1392`

` = 46046 - 1392`

` = 44654`

b) 10000 - ( 93120 : 24 - 24 x 57 ) 

` = 10000 -  ( 3880 - 1368)`

` = 10000 - 2512`

` = 7488`

c) 100798 - 9894 : 34 x 23 - 23 =

` = 100798  - 6693 -23`

` = 94082`

a: =48048-2002-1392=44654

b: =10000-3880+1368=7488

c: =100798-6693-23=94082

a)44654
b)7488
c)94082

8 ⋮ \(x\);  12 ⋮  \(x\);  24 ⋮ \(x\) ⇒ 8; 12; 24 ⋮ \(x\) ⇒ \(x\) \(\in\) ƯC(8;12;24)

8 = 2³; 12 = 2².3; 24 = 2².3

ƯCLN(8; 12; 24) =  2² = 4

\(x\) \(\in\) {-4;  -2; -1; 1; 2; 4}

a) 4
b) 6
c) 2

b, 24 ⋮ \(x\); 30 ⋮ \(x\) ⇒ \(x\) \(\in\) ƯC(24; 30) 

24 = 2³.3; 30 = 2.3.5 ⇒ ƯCLN(24; 30) = 2.3 = 6

\(x\) \(\in\) Ư(6) = {-6; -3; -2; -1; 1; 2; 3; 6}

   24 x 32 -  43 + 58 x 78 - 98 x 123

=  768      -  43 +    4524  -   12054

=     - 6805

  24 x 32 -  43 + 58 x 78 - 98 x 123

=  768      -  43 +    4524  -   12054

=     - 6805

\(\dfrac{15}{13}\)

c) (3x + 11) : 8 = 46

=> 3x + 11 = 368

=> 3x = 368 - 11

=> 3x = 357

=> x = 357 : 3

=> x = 119

b) 100 + (x - 23) = 317

=> x - 23 = 317 - 100

=> x - 23 = 217

=> x = 217 + 23

=> x = 240

a) 1002 : (x - 12) = 3

=> x - 12 = 1002 : 3

=> x - 12 = 334

=> x = 334 + 12

=> x = 346

d) 68 - 4x = 24

=> 4x = 68 - 24

=> 4x = 44

=> x = 44 : 4 = 11

e) 110 - (4x + 15) = 3

=> 4x + 15 = 110 - 3

=> 4x + 15 = 107

=> 4x = 107 - 15

=> 4x = 92

=> x = 92 : 4 = 23

a) \(1002:\left(x-12\right)=3\)

\(\Leftrightarrow x-12=1002:3\)

\(\Leftrightarrow x-12=334\)

\(\Leftrightarrow x=334+12\)

\(\Leftrightarrow x=346\)

Vậy \(x=346\)

b) \(100+\left(x-23\right)=317\)

\(\Leftrightarrow x-23=317-100\)

\(\Leftrightarrow x-23=217\)

\(\Leftrightarrow x=217+23\)

\(\Leftrightarrow x=240\)

Vậy \(x=240\)

\(=\dfrac{29}{13}\cdot\dfrac{13}{29}\cdot4\cdot\dfrac{21}{8}\cdot\dfrac{8}{21}=4\)

bài này mik ra \(\dfrac{39}{29}\) ko bt đúng ko :)