\(\frac{15.3^{11}+4.27^4}{9^7}\)

\(=\frac{5.3.3^{11}+4.\left(3^3\right)^4}{\left(3^2\right)^7}\)

\(=\frac{5.3^{12}+4.3^{12}}{3^{14}}\)

\(=\frac{3^{12}.\left(5+4\right)}{3^{14}}\)

\(=\frac{3^{12}.9}{3^{14}}\)

\(=\frac{3^{12}.3^2}{3^{14}}\)

\(=\frac{3^{14}}{3^{14}}\)

\(=1\)

Chúc bạn học tốt !!! 

\(A=\frac{15.3^{11}+4.27^4}{9^7}\)

\(\Rightarrow\frac{3.5.3^{11}+4.3^{3.4}}{3^{2.7}}\)

\(\Rightarrow\frac{3^{12}.5+3^{12}.4}{3^{14}}\)

\(\Rightarrow\frac{3^{12}\left(5+4\right)}{3^{14}}\)

\(\Rightarrow\frac{9}{3^2}=\frac{9}{9}=1\)

Vậy ....

thanks ban

Chứng minh à ?        

\(A=\frac{15.3^{11}+4.27^4}{9^7}=\frac{3.5.3^{11}+4.3^{3.4}}{3^{2.7}}=\frac{3^{12}.5+3^{12}.4}{3^{14}}=\frac{3^{12}\left(5+4\right)}{3^{14}}=\frac{9}{3^2}=\frac{9}{9}=1\)

\(\frac{16.3^{11+4.27^4}}{9^7}=\frac{2^4.3^{11+2^2.3^{12}}}{3^{14}}\)

\(=\frac{2^4.3^{11+2^2.531441}}{3^{14}}=\frac{2^4.3^{2125764}}{3^{14}}=2^4.3^{2125750}\)

Ta có: 

\(\frac{16.3^{11+4.27^4}}{9^7}=\frac{2^4.3^{11+2^2.\left(3^3\right)^4}}{\left(3^2\right)^7}=\frac{2^4.3^{11+2^2.3^{12}}}{3^{14}}=\frac{2^4.3^{11}.3^{2^2.3^{12}}}{3^{14}}=\frac{2^4.3^{15}.3^{3^{12}}}{3^{14}}=2^4.3^{3^{12}}\)

Vậy ...

\(F=\frac{15.3^{11}+4.27^4}{9^7}=\frac{5.3.3^{11}+4.\left(3^3\right)^4}{\left(3^2\right)^7}=\frac{5.3^{12}+4.3^{12}}{3^{14}}=\frac{3^{12}.\left(5+4\right)}{3^{14}}=\frac{3^{12}.9}{3^{12}.9}=1\)

\(G=\frac{5.2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\)

\(G=\frac{5.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}{3^2.2^{34}}\)

\(G=\frac{5.2^{13}.2^{22}-2^{36}}{3^2.2^{34}}\)

\(G=\frac{5.2^{35}-2^{36}}{3^2.2^{34}}\)

\(G=\frac{2^{35}.\left(5-2\right)}{3^2.2^{34}}\)

\(G=\frac{2^{35}.3}{3^2.2^{34}}=\frac{2}{3}\)

= 5.3.3^11+4.(3^3)^4/(3^2)^7

= 5.3^12+4.3^12/3^14

= 3^12.(5+4)/3.3^12.3^2

= 3^12.9/3^12.9 = 1

k mk nha