Question

Tính giá trị biểu thức :

F = \(\frac{15.3^{11}+4.27^4}{9^7}\)

G = \(\frac{5.2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\)

Answer 1

\(F=\frac{15.3^{11}+4.27^4}{9^7}=\frac{5.3.3^{11}+4.\left(3^3\right)^4}{\left(3^2\right)^7}=\frac{5.3^{12}+4.3^{12}}{3^{14}}=\frac{3^{12}.\left(5+4\right)}{3^{14}}=\frac{3^{12}.9}{3^{12}.9}=1\)

\(G=\frac{5.2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\)

\(G=\frac{5.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}{3^2.2^{34}}\)

\(G=\frac{5.2^{13}.2^{22}-2^{36}}{3^2.2^{34}}\)

\(G=\frac{5.2^{35}-2^{36}}{3^2.2^{34}}\)

\(G=\frac{2^{35}.\left(5-2\right)}{3^2.2^{34}}\)

\(G=\frac{2^{35}.3}{3^2.2^{34}}=\frac{2}{3}\)