A = 1 + 5 + 5² + 5³ + 5³ + ...+ 5⁴⁹ + 5⁵⁰

5A = 5(5⁰+5¹+5²+5³+...+5⁴⁹+5⁵⁰)

5A=5¹+5²+5³+5⁴+...+5⁵⁰+5⁵¹

5A-A=(5¹+5²+5³+5⁴+...+5⁵⁰+5⁵¹)-(5⁰ + 5¹ + 5² + 5³ + 5³ + ...+ 5⁴⁹ + 5⁵⁰)

4A=5⁵¹-1

A=(5⁵¹-1):4

5A = 5 + 5^2 + 5^3 + 5^4 + 5^5 +...+ 5^50 + 5^51

=> 4A = ( 5 + 5^2 + 5^3 + 5^4 + 5^5 +...+ 5^50 + 5^51 ) - ( 1 + 5 + 5^2 + 5^3 +...+ 5^49 + 5^50 )

=> 4A = 5^51 - 1

=> A = \(\frac{5^{51}-1}{4}\) 

5A=5+5²+5³+...+5⁵⁰+5⁵¹

5A-A=5⁵¹-1

A=5⁵¹-1:4

tick mk nha cái kia sai rôi

\(\frac{5^{51}-1}{4}\)

A    =1+5+5²+5³+...+5⁴⁹+5⁵⁰

 5A =  5 + 5² + 5³ + 5⁴ + ...+ 5⁵⁰+ 5⁵¹

5A -A =   5 + 5² + 5³ + 5⁴ + ...+ 5⁵⁰+ 5⁵¹  - 1- 5 - 52-53- ... - 549-550

4A= 5⁵¹ -1

A= 5⁵¹ -1 / 4

Ta có :A = 1 + 5 + 5² + 5³ + .... + 5⁴⁹ + 5⁵⁰

=> 5A = 5 + 5² + 5³ + .... + 5⁵⁰ + 5⁵¹

=> 5A - A = 5⁵¹ - 1 

=> 4A = 5⁵¹ - 1

=> A = \(\frac{5^{51}-1}{4}\)

A=\(5^{51}\)\(-5^0\)

k mk nha

mk k lại cho!

A=1+5+5²+5³+...+5⁴⁹+5⁵⁰

5A=5.(1+5+5²+5³+...+5⁵⁰)

5A=5+5²+5³+5⁴+...+5⁵¹

5A-A=(5+5²+5³+...+5⁵¹)-(1+5+5²+...+5⁵⁰)

 4A=5⁵¹-1

  A=\(\frac{5^{50}-1}{4}\)

Ta có:

A = 1+ 5 + 5² + 5³ + ......... + 5⁴⁹ + 5⁵⁰

=> 5A = 5 + 5² + 5³ + 5⁴ +.......+ 5⁴⁹ + 5⁵⁰

Do đó: 5A - A = 5⁵¹ - 1

Vậy A =  \(\frac{5^{51}-1}{4}\)

Rút gọn: 

\(A=5^0+5^1+5^2+...+5^{99}+5^{50}\)

\(5A=5^1+5^2+5^3+...+5^{51}\)

\(5A-A=\left(5^1+5^2+5^3+...+5^{51}\right)-\left(5^0+5^1+5^2+...+5^{50}\right)\)

\(4A=5^{51}-5^0\)

\(=>A=\left(5^{51}-5^0\right):4\)

Vậy : \(A=\left(5^{51}-5^0\right):4\)

=(5⁵¹-1 ):4

 tick nha