1212+2=1214

cậu tk cho tớ nhé

1214 nha!k mình mình k lại!

1212 + 2

= 1214

K NHA MIK XIN BN LUÔN ĐÓ

\(\frac{1212}{1515}+\frac{1212}{3535}+\frac{1212}{6363}+\frac{1212}{9999}\)

\(=1212.\left(\frac{1}{1515}+\frac{1}{3535}+\frac{1}{6363}+\frac{1}{9999}\right)\)

Sau đó tự tính rồi làm típ nha 

Study well 

0,44 x (\(x+x\times\) 5 - \(\dfrac{23}{55}\)) + \(\dfrac{3}{14}\) x 2,24 = 1

 0,44 x (\(x+x\times\)5 - \(\dfrac{23}{55}\)) + 0,48 = 1

 0,44 x (\(x+x\times\) 5 - \(\dfrac{23}{55}\)) = 1 - 0,48

0,44 x (\(x+x\times5\) - \(\dfrac{23}{55}\)) = 0,52

           \(x+x\times5\) - \(\dfrac{23}{55}\) = 0,52 : 0,44

          \(x\) x (1 + 5) -\(\dfrac{23}{55}\)  = \(\dfrac{13}{11}\)

         \(x\) x 6 - \(\dfrac{66}{10}\) = \(\dfrac{13}{11}\) + \(\dfrac{23}{55}\)

         \(x\) x 6 = \(\dfrac{65}{55}\) + \(\dfrac{23}{55}\)

          \(x\times\) 6 = \(\dfrac{8}{5}\)

         \(x\) x 6 = \(\dfrac{8}{5}\)  : 6

          \(x\)      = \(\dfrac{4}{15}\)

Vậy \(x=\dfrac{4}{15}\)

a. \(\frac{26}{42}< \frac{56}{78}\)

b.\(\frac{58}{89}< \frac{36}{53}\)

c.\(\frac{1530}{1632}>\frac{1414}{1515}\)

d.\(\frac{-373737}{515151}>\frac{-1111}{1212}\)

k cho mk nha!!!!

giải chi tiết  hộ mk nha!

\(=\lim\limits\dfrac{n^2+an+2020-n^2}{\sqrt{n^2+an+2020}+n}+\lim\limits\dfrac{n^3-bn^3-6n^2-3n-2021}{n^2+\sqrt[3]{\left(bn^3+6n^2+3n+2021\right)^2}+n\sqrt[3]{bn^3+6n^2+3n+2021}}\)

\(=\lim\limits\dfrac{\dfrac{an}{n}+\dfrac{2020}{n}}{\sqrt{\dfrac{n^2}{n^2}+\dfrac{an}{n^2}+\dfrac{2020}{n^2}}+\dfrac{n}{n}}+\lim\limits\dfrac{\dfrac{\left(1-b\right)n^3}{n^2}-\dfrac{6n^2}{n^2}-\dfrac{3n}{n^2}-\dfrac{2021}{n^2}}{\dfrac{n^2}{n^2}+\dfrac{\sqrt[3]{\left(bn^3+6n^2+3n+2021\right)^2}}{n^2}+\dfrac{n\sqrt[3]{bn^3+6n^2+3n+2021}}{n^2}}\)

\(=\dfrac{1}{2}a+\lim\limits\dfrac{\left(1-b\right)n-6}{1+\sqrt[3]{b^2}+\sqrt[3]{b}}\)

De gioi han bang 0 thi \(\left(1-b\right)=0\Leftrightarrow b=1\Rightarrow\lim\limits\dfrac{\left(1-b\right)n-6}{1+\sqrt[3]{b^2}+\sqrt[3]{b}}=-\dfrac{6}{3}=-2\)

\(\Rightarrow\dfrac{1}{2}a-2=0\Leftrightarrow a=4\)

\(\Rightarrow P=4^{2020}+2^{2021}-1\)

P/s: Tổng này hỏi có bao nhiêu chữ số thì tui còn tìm được, chứ viết hẳn ra thì..chắc nhờ siêu máy tính của nasa :v

Ta có : 1212/3535=12/35 ; 1212/9999=12/99

Từ đề bài => = 12/15 +12/35 +12/63 +12/99

                    = 6 x ( 2/15 + 2/35 +2/63+2/99 )

                    = 6 x ( 2/3x5 + ....+ 2/9x11)

                    = 6 x ( 1/3 - 1/5 +....+1/9 - 1/11)

                    = 6 x ( 1/3 - 1/11)

                    = 6 x 8/33 = 48/33

ai giúp zới. mai đi hok rùi

48/33

12/15+12/35+12/63+4/33

=4/3+4/33

=16/11

bạn có thể giải thích cho mk luôn dc k ban

\(\dfrac{1212}{1515}+\dfrac{1212}{3535}+\dfrac{1212}{6363}+\dfrac{1212}{9999}\)

=\(\dfrac{12}{15}+\dfrac{12}{35}+\dfrac{12}{63}+\dfrac{12}{99}\)

=\(\dfrac{16}{11}\)

Giải:

\(\dfrac{1212}{1515}+\dfrac{1212}{3535}+\dfrac{1212}{6363}+\dfrac{1212}{9999}\) 

\(=\dfrac{12}{15}+\dfrac{12}{35}+\dfrac{12}{63}+\dfrac{12}{99}\) 

\(=12.\left(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}\right)\) 

\(=12.\dfrac{1}{2}.\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}\right)\) 

\(=6.\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\right)\) 

\(=6.\left(\dfrac{1}{3}-\dfrac{1}{11}\right)\) 

\(=6.\dfrac{8}{33}\) 

\(=\dfrac{16}{11}\)

\(=\dfrac{12}{15}+\dfrac{12}{35}+\dfrac{12}{63}+\dfrac{12}{99}=12\cdot\left[\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}\right]=12\cdot\left[\dfrac{1}{3\cdot5}+\dfrac{1}{5\cdot7}+\dfrac{1}{7\cdot9}+\dfrac{1}{9\cdot11}\right]=12\cdot\dfrac{1}{2}\cdot\left[\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\right]=6\cdot\left[\dfrac{1}{3}-\dfrac{1}{11}\right]=6\cdot\dfrac{8}{33}=\dfrac{48}{33}=\dfrac{16}{11}\)

1212/3030=1212:303/3030:303=4/10

32032/48048=32032:2002/48048:2002=16/21

456456/234234=456456:6006/234234:6006=76/39

16161616/38383838=16161616:2020202/38383838:2020202=8/19

\(\frac{1212}{3030}\)=\(\frac{2}{5}\)

\(\frac{32032}{48048}\)=\(\frac{2}{3}\)

\(\frac{45456}{234234}\)=\(\frac{7576}{39039}\)

\(\frac{16161616}{38383838}\)=\(\frac{8}{19}\)

\(\frac{1212}{3030}=\frac{2.6.101}{5.6.101}=\frac{2}{5}\)

\(\frac{32032}{48048}=\frac{2.16.1001}{3.16.1001}=\frac{2}{3}\)

\(\frac{456456}{234234}=\frac{76.61001}{39.6.1001}=\frac{76}{39}\)(Bạn ghi thiếu số 6 ở tử số nha)

\(\frac{16161616}{38383838}=\frac{2.8.1010101}{19.2.1010101}=\frac{8}{19}\)

(Dấu chấm là nhân nha)