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\(3a^2-6ab+3b^2-12c^2\)

\(=3\left(a^2-2ab+b^2-4c^2\right)\)

\(=3\left(\left(a-b\right)^2-\left(2c\right)^2\right)\)

\(=3\left(a-b-2c\right)\left(a-b+2c\right)\)

\(3a^2-6ab+3b^2-12c^2=3\left(a^2-2ab+b^2-4c^2\right)=3\left[\left(a-b\right)^2-\left(2c\right)^2\right]=3\left(a-b-2c\right)\left(a-b+2c\right)\)

a) 3a²-6ab+3b²-12c²

=3.(a²-2ab+b²-4c²)

=3.[(a-b)²-4c²]

=3.(a-b-2c)(a-b+2c)

\(3a^2-6ab-3b^2-12c^2=3\left(a^2-2ab+b^2\right)-12c^2=\left(\sqrt{3}\left(a-b\right)\right)^2-\left(\sqrt{12}c\right)^2=\left(\sqrt{3}a-\sqrt{3}b-\sqrt{12}c\right)\left(\sqrt{3}a-\sqrt{3}b+\sqrt{12}c\right)\)

Sửa đề :\(3a^2-6ab+3b^2-12c^2\)=\(3\left(a^2-2ab+b^2-4c^2\right)\)

=\(3\left(a-b\right)^2-3\left(2c\right)^2\)=\(3\left(a-b-c\right)\left(a-b+c\right)\)

3a² - 6ab + 3b² - 12c²

⁼ 3a² - 3a x 2b + 3b² - 3 x 4c²

= 3(a² -a x b +b² - 4c²)

phân tích thành nhân tử :
3a² - 6ab + 3b² - 12c²

=3(a\(^2\)-2ab+b\(^2\)-4c\(^2\))

=3[(a-b)\(^2\)-(2c)\(^2\)]

=3(a-b-2c)(a-b+2c)

3a^2 -6ab +3ab^2 -12c^2

= 3(a^2 -2ab +b^2 -4c^2)

= 3[(a- b)^2 -4c^2]=3(a- b+ 4c)(a- b- 4c)

3a² - 6ab + 3b² - 12c²

= 3a² - 3.2ab + 3b² - 3.4c²

= 3 (a² - 2ab + b² - 4c²)

$3a^2 -6ab +3ab^2 -12c^2$

$= 3(a^2 -2ab +b^2 -4c^2)$

$= 3[(a- b)^2 -4c^2]$

$=3(a- b+ 4c)(a- b- 4c)$

\(3a^2-6ab+3b^2-12c^2\)

\(=3a^2-3ab-3ab+3b^2-12c^2\)

\(=\left(3a^2-3ab\right)-\left(3ab-3b^2\right)-12c^2\)

\(=3a\left(a-b\right)-3b\left(a-b\right)-12c^2\)

\(=\left(3a-3b\right)\left(a-b\right)-12c^2\)

\(=3\left(a-b\right)^2-12c^2\)

3a² - 6ab + 3b² - 12c²

= 3(a² - 2ab + b² - 4c²)

= 3[(a - b)² - (2c)²]

= 3(a - b + 2c)(a - b - 2c)

ủa thế mk sai rồi à Xyz?

b) a² + 2ab + b² - ac - bc

= ( a + b)² - c (a + b)

= ( a + b).( a + b - c )

c) x³ - x² - x + 1

= x² .(x - 1) - ( x - 1)

= ( x- 1).( x² - 1)

= ( x-1).(x-1).(x+1)

1)\(3a^2+6ab+3b^2-12c^2\)

\(=3\left(a^2+2ab+b^2-4c^2\right)\)

\(=3\left[\left(a^2+2ab+b^2\right)-4c^2\right]\)

\(=3\left[\left(a+b\right)^2-\left(2c\right)^2\right]\)

\(=3\left(a+b-2c\right)\left(a+b+2c\right)\)

Câu a) tớ cứ thắc mắc cái chỗ - 12c² nó ko ghép cặp vs cái nào hết Hình như đề sai

đề đúng 100% chờ tí tui giải cho