\(M=\frac{\left(3^2\right)^4.\left(3^3\right)^5.3^6.3^4}{3^8.\left(3^4\right)^4.3^5.\left(2^3\right)^2}=\frac{3^8.3^{15}.3^6.3^4}{3^8.3^{16}.3^5.2^6}=\frac{3^{29}.3^4}{3^{29}.2^6}=\frac{1.81}{1.64}=\frac{81}{64}\)

\(A=\frac{2\cdot\left(2^3\right)^4\cdot\left(3^3\right)^8+2^2\cdot\left(2\cdot3\right)^9}{2^7\cdot6^7+2^7\cdot\left(2^3\cdot5\right).\left(3^2\right)^4}\)

\(A=\frac{2\cdot2^{12}\cdot3^{24}+2^2\cdot\left(2\cdot3\right)^9}{12^7+2^7\cdot\left(2^3\cdot5\right)\cdot3^8}\)

Đến đó thì bí

hihi

đến đó thì bt rồi

\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.243.8^2}\)

\(M=\frac{\left(3^2\right)^4.\left(3^3\right)^5.3^6.3^4}{3^8.\left(3^4\right)^4.\left(3^5\right).\left(2^3\right)}\)

\(M=\frac{3^8.3^{15}.3^6.3^4}{3^8.3^{16}.3^5.8}\)

\(M=\frac{3^{33}}{3^{29}.8}\)

\(M=\frac{3^4}{1.8}\)

\(M=\frac{81}{8}\)

Chúc bạn học tốt !!! 

Sửa hộ mk : 

\(8^2=2^9\)

Kết quả : \(\frac{81}{512}\)

có kq ch bn ?

11/4 giờ = bao nhiêu phút

lop6 đi mà học

a, \(\dfrac{2\cdot8^4\cdot27^2+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)

=\(\dfrac{2\cdot\left(2^3\right)^4\cdot\left(3^3\right)^2+2^2\cdot2^9\cdot3^9}{2^7\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot\left(3^2\right)^4}\)

=\(\dfrac{2\cdot2^{12}\cdot3^6+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)

=\(\dfrac{2^{11}\cdot3^6\cdot\left(2^2+3^3\right)}{2^{10}\cdot3^7\cdot\left(2^4+5\cdot3\right)}\)

=\(\dfrac{2^{11}\cdot3^6\cdot31}{2^{10}\cdot3^7\cdot31}\)

=\(\dfrac{2}{3}\)

b, \(\dfrac{\dfrac{8}{27}\cdot\dfrac{9}{16}\cdot\left(-1\right)}{\dfrac{4}{25}\cdot\dfrac{-125}{1728}}\)

=\(\dfrac{\dfrac{8\cdot9\cdot\left(-1\right)}{27\cdot16}}{\dfrac{4\cdot\left(-125\right)}{25\cdot1728}}\)

=\(\dfrac{\dfrac{-1}{6}}{\dfrac{-5}{432}}\)

=\(\dfrac{-1}{6}\cdot\dfrac{-432}{5}\)

=\(\dfrac{72}{5}\)

\(\frac{15.3^{11}+4.27^4}{9^7}\)

\(=\frac{5.3.3^{11}+4.\left(3^3\right)^4}{\left(3^2\right)^7}\)

\(=\frac{5.3^{12}+4.3^{12}}{3^{14}}\)

\(=\frac{3^{12}.\left(5+4\right)}{3^{14}}\)

\(=\frac{3^{12}.9}{3^{14}}\)

\(=\frac{3^{12}.3^2}{3^{14}}\)

\(=\frac{3^{14}}{3^{14}}\)

\(=1\)

Chúc bạn học tốt !!! 

\(A=\frac{15.3^{11}+4.27^4}{9^7}\)

\(\Rightarrow\frac{3.5.3^{11}+4.3^{3.4}}{3^{2.7}}\)

\(\Rightarrow\frac{3^{12}.5+3^{12}.4}{3^{14}}\)

\(\Rightarrow\frac{3^{12}\left(5+4\right)}{3^{14}}\)

\(\Rightarrow\frac{9}{3^2}=\frac{9}{9}=1\)

Vậy ....

thanks ban