\(\frac{16.3^{11+4.27^4}}{9^7}=\frac{2^4.3^{11+2^2.3^{12}}}{3^{14}}\)
\(=\frac{2^4.3^{11+2^2.531441}}{3^{14}}=\frac{2^4.3^{2125764}}{3^{14}}=2^4.3^{2125750}\)
Ta có:
\(\frac{16.3^{11+4.27^4}}{9^7}=\frac{2^4.3^{11+2^2.\left(3^3\right)^4}}{\left(3^2\right)^7}=\frac{2^4.3^{11+2^2.3^{12}}}{3^{14}}=\frac{2^4.3^{11}.3^{2^2.3^{12}}}{3^{14}}=\frac{2^4.3^{15}.3^{3^{12}}}{3^{14}}=2^4.3^{3^{12}}\)
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