\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(3\cdot5^2\right)^{15}}=\dfrac{3^{20}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot5^{30}}=3^5=243\\ \dfrac{6^6+6^3+3^3+3^6}{-73}=\dfrac{46656+216+27+729}{-73}=-\dfrac{47628}{73}\\ \dfrac{27^7+3^{15}}{9^9-27}=\dfrac{\left(3^3\right)^7+3^{15}}{\left(3^2\right)^9-3^3}=\dfrac{3^{21}+3^{15}}{3^{18}-3^3}=\dfrac{3^{15}\left(3^6+1\right)}{3^3\left(3^{15}-1\right)}=\dfrac{3^5\cdot730}{3^{15}-1}\\ \dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)

a) Khoanh vào C. Trừ, chia, cộng.

b) Giá trị của biểu thức 6 + (45 – 27) : 2 là 15

Giải thích: 6 + (45 – 27) : 2 = 6 + 18 : 2 = 6 + 9 = 15.

\(a,\dfrac{5^{16}\cdot27^7}{125^5\cdot9^{11}}=\dfrac{5^{16}\cdot\left(3^3\right)^7}{\left(5^3\right)^5\cdot\left(3^2\right)^{11}}\)

\(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)

\(b,\left(-0,2\right)^2\cdot5-\dfrac{2^{13}\cdot27^3}{4^6\cdot9^5}\)

\(=0,04\cdot5-\dfrac{2^{13}\cdot\left(3^3\right)^3}{\left(2^2\right)^6\cdot\left(3^2\right)^5}\)

\(=0,2-\dfrac{2^{13}\cdot3^9}{2^{12}\cdot3^{10}}\)

\(=0,2-\dfrac{2}{3}\)

\(=-\dfrac{7}{15}\)

\(c,\dfrac{5^6+2^2\cdot25^3+2^3\cdot125^2}{26\cdot5^6}\)

\(=\dfrac{5^6+2^2\cdot\left(5^2\right)^3+2^3\cdot\left(5^3\right)^2}{5^6\cdot26}\)

\(=\dfrac{5^6+4\cdot5^6+8\cdot5^6}{5^6\cdot26}\)

\(=\dfrac{5^6\left(1+4+8\right)}{5^6\cdot26}\)

\(=\dfrac{13}{26}\)

\(=\dfrac{1}{2}\)

#\(Toru\)

\(a,\dfrac{5^{16}.27^7}{125^5.9^{11}}=\dfrac{\left(5^2\right)^8.9^7.3^7}{25^5.5^5.9^{11}}\\ =\dfrac{25^8.9^7.\left(3^2\right)^3.3}{25^5.\left(5^2\right)^2.5.9^{11}}=\dfrac{25^8.9^7.9^3.3}{25^5.25^2.5.9^{11}}\\ =\dfrac{25^8.9^{10}.3}{25^7.5.9^{11}}=\dfrac{25^7.9^{10}.25.3}{25^7.9^{10}.5.9}\\ =\dfrac{25.3}{5.9}=\dfrac{5.5.3}{5.3.3}=\dfrac{5}{3}\)

\(a.17+26:2\\ =17+13\\ =30\\ b.300:\left[130-6\left(45-40\right)\right]\\ =300:\left[130-6.5\right]\\ =300:\left[130-30\right]\\ =300:100\\ =3\\ c.\left(-15\right).\left(-2\right)\\ =15.2\\ =30\\ d.\left(-27\right).36+54.\left(-27\right)\\ =\left(-27\right)\left(36+54\right)\\ =\left(-27\right).90\\ =-2430\)

a) 17+14=31

b) 300:[130-6.5)

300:[130-30]

300:100

3

c)30

d)(36+54).(-27)

=90.(-27)

=-2430

\(\left(-\frac{1}{2}\right)^2\cdot2\cdot\frac{7}{4}\div\left(\frac{5}{8}-1\frac{3}{16}\right)\)

\(=\frac{1}{4}\cdot2\cdot\frac{7}{4}\div\left(\frac{10}{16}-\frac{19}{16}\right)\)

\(=\frac{7}{8}\div\left(-\frac{9}{10}\right)\)

\(=\frac{7}{8}\cdot\left(-\frac{10}{9}\right)\)

\(=-\frac{35}{36}\)

-1/2^2.7/4:(5/8-1 3/16)=1/4.7/4:(5/8-19/16)=1/4.7/4:(10/16-19/16)=1/4.7/4:-9/16=1/4.7/4.-16/9=1/4.-28/9=-7/9

\(17\frac{6}{11}\cdot\frac{4}{27}-8\frac{6}{11}\div\frac{27}{4}+350\%\)

\(=17\frac{6}{11}\cdot\frac{4}{27}-8\frac{6}{11}\cdot\frac{4}{27}+\frac{7}{2}\)

\(=\frac{4}{27}\cdot\left(17\frac{6}{11}-8\frac{6}{11}\right)+\frac{7}{2}\)

\(=\frac{4}{27}\cdot9+\frac{7}{2}\)

\(=\frac{4}{3}+\frac{7}{2}\)

\(=\frac{29}{6}\)

(-12) + (-18)

= -30

------------------

(-90) + 27 + (-10) + 73

= [(-90) + (-10) + (27 + 73)

= -100 + 100

= 0

---------------------------------

25 . (-5) . (-4)

= 25 . (-4) . (-5)

= -100 . (-5)

= 100 . 5

= 500

----------------------------------------

(-15) . 40 : 6

= [(-15) . 40] : 6 

= (-600) : 6

= -100

-----------------------------------

(-27) . 58 + (-27) . 42

= (-27) . (58 + 42)

= (-27) . 100

= -2700

2^(10 : 64 x 16) = 2^[(10 x 16) : 64] = 2^(160 : 64) = 2^25

2^(10 x 8) = 2^80     3^(5 : 27) = 3^(5/27)     5^(2 x 125) = 5^250     6^(6 : 36) = 6^(1/6)

3,27x1,6+3,27x8,4

=3,27x(1,6+8,4)

=3,27x10

=0,327