Tìm X biết:          

X : 6 x 7,2 + 1,3 x X + X : 2 + 15 = 19,95 

(X x 7,2) / 6 + (7,8 x X) / 6 + (X x 3) / 6 + 90/6 = 119,7/6

X x 7,2 + 7,8 x X + X x 3 + 90 = 119,7

X x (7,2 + 7,8 + 3) = 119,7 - 90

X x 18 = 29,7

X = 29,7 : 18

X = 1,65

Tìm X biết:          

X : 6 x 7,2 + 1,3 x X + X : 2 + 15 = 19,95 

(X x 7,2) / 6 + (7,8 x X) / 6 + (X x 3) / 6 + 90/6 = 119,7/6

X x 7,2 + 7,8 x X + X x 3 + 90 = 119,7

X x (7,2 + 7,8 + 3) = 119,7 - 90

X x 18 = 29,7

X = 29,7 : 18

X = 1,65

Tìm X biết:          

X : 6 x 7,2 + 1,3 x X + X : 2 + 15 = 19,95 

(X x 7,2) / 6 + (7,8 x X) / 6 + (X x 3) / 6 + 90/6 = 119,7/6

X x 7,2 + 7,8 x X + X x 3 + 90 = 119,7

X x (7,2 + 7,8 + 3) = 119,7 - 90

X x 18 = 29,7

X = 29,7 : 18

X = 1,65

1,65

a: =>|x+2|=2x-6

\(\Leftrightarrow\left\{{}\begin{matrix}x>=3\\\left(2x-6-x-2\right)\left(2x-6+x+2\right)=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x>=3\\\left(x-8\right)\left(3x-4\right)=0\end{matrix}\right.\Leftrightarrow x=8\)

b: =>1,2x+1,3x=2,95

=>2,5x=2,95

hay x=1,18

a, |x + 2| + 6 = 2x

\(\Rightarrow\left|x+2\right|=2x-6\) (1)

Vì |x + 2| \(\ge\) 0 \(\Rightarrow2x-6\ge0\Rightarrow2x\ge6\Rightarrow x\ge3\)

Từ (1) \(\Rightarrow\left[{}\begin{matrix}x+2=2x-6\\x+2=-\left(2x-6\right)\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x+2x=-6-2\\x+\left(-2x\right)=6-2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}3x=-8\\-x=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{8}{3}\\x=-4\end{matrix}\right.\)(Loại)

Vậy không có giá trị x thỏa mãn

\(7,75-\left(0,5\times y\div5-6,2\right)=5\)

\(0,5\times y\div5-6,2=7,75-5=2,75\)

\(0,5\div5\times y-6,2=2,75\)

\(0,1\times y=2,75+6,2=8,95\)

\(\dfrac{1}{10}y=8,95\)

\(y=8,95\times10=89,5\)

\(y\div6\times7,2+1,3\times y+y\div2+15=19,95\)

\(1,2\times y+1,3\times y+0,5y=19,95-15=4,95\)

\(y\left(1,2+1,3+0,5\right)=4,95\)

\(2y=4,95\)

\(y=4,95\div2=2,475\)